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...\n", argv[0]); //Set up Device 　　 intdev =0;　　Cudadeviceprop Deviceprop; CHECK (Cudagetdeviceproperties (Deviceprop, Dev)); printf ("Using Device%d:%s\n", Dev, deviceprop.name); CHECK (Cudasetdevice (dev));//set up date size of matrix 　　 intNX =1 -; intNY =1 -; intNxy = nx*NY; intNbytes = Nxy *sizeof(float); printf ("Matrix size:nx%d NY%d\n", NX, NY);//malloc

http_code; return http_code "content"; e.g. location/api/test/{return 403; } location/stat/{return 204; } location/ping/{return } For mobilemove end and site side jump to each other Location =/{Try_files $uri @mobile_rewrite; } location ~ ^/(login|register|search|album|404|album/\d+|item/\d+|topic) $ {try_files $uri @mobile_rewrite; } location @mobile_rewrite {if ($http _user_agent ~* (android|bb\d+|meego). +mobile|avantgo|bada\/|blackberry|bla Zer|compal|ela

Today boring turn code, turn out a previously written C # screenshot function ... Take it out and share it with everyone. This code is written in reference to a section of the screen in C + + code rewrite. It's just a statement of the API. The declared APIs are also appended. For reference. If there are any questions, please note. (Appledotnet@hotmail.com) /// Intercepting part of the screen /// Upper left corner Lower right corner is full screen return value bitmap public static Bitmap G

=" http://s3.51cto.com/wyfs02/M01/49/D8/wKioL1Qb58Lx3jQHAAE7MfILbzQ828.jpg "style=" float: none; "title=" Trimino_3.png "alt=" Wkiol1qb58lx3jqhaae7mfilbzq828.jpg "/>The source code for the algorithm is as follows:/*** @author shuaiguangying* To solve the problem of board coverage by division and treatment * there is a bad point in the 2^n*2^n board * bad points can be anywhere * cover the board with the L-plate ** The key to solving this problem is: Divide and conquer * The key to division is

Put each column in the adjacent. Indent to a point as the left side of the binary graphPut each row in the adjacent. Indent to a point as the right side of a binary graphThen we can find the maximum matchThis problem is enough for Hungary ... However.. I used the HK ... A little bit overqualified for the feeling//#include #include#include#include#include#include#include#defineMem (A, B) memset (A, B, sizeof (a))using namespacestd;Const intMAXN =10010, INF =0x7fffffff;intDX[MAXN], DY[MAXN], CX[MA

) O.minmousex = E.clientx-x + O.minx; if (O.maxx!= null) O.maxmousex = O.minmousex + O.maxx-o.minx; } else { if (O.minx!= null) O.maxmousex =-o.minx + e.clientx + x; if (O.maxx!= null) O.minmousex =-o.maxx + e.clientx + x; } if (O.vmode) { if (o.miny!= null) O.minmousey = e.clienty-y + o.miny; if (o.maxy!= null) O.maxmousey = O.minmousey + o.maxy-o.miny; } else { if (o.miny!= null) O.maxmousey =-o.miny + E.clienty + y; if (o.maxy!= null) O.minmousey =-o.maxy + E.clienty + y; } D

Cat Share, must boutiqueOriginal articles, welcome reprint. Reprint Please specify: Sanayu's BlogAddress: http://blog.csdn.net/u013357243?viewmode=contentsMultiple ways to create a controller and viewLoad of Controller viewCreate with Storyboard1: Load Storyboard First (test is storyboard's name)UIStoryboard *storyboard = [UIStoryboardstoryboardWithName:@"Test"bundle:nil];2: Initialize the controller in the storyboardInitialize the "Initial controller" (the controller that the Arrow refers to)NY

Python generates calendar instance resolution, python calendar instance This example shows how to generate a calendar in Python. This instance can generate a 5x7 list for a calendar month. No date in the list is of the datetime type and is implemented using the calendar module provided by python. The program running result is as follows: python test.py 2014 09 2014-08-31 2014-09-01 2014-09-02 2014-09-03 2014-09-04 2014-09-05 2014-09-06 2014-09-07 2014-09-08 2014-09-09 2014-09-10 2014-09-11 2014-

This example shows how Python generates a calendar. This example implements a one-month calendar generation 5x7 list, with no date in the table as a datetime type, implemented using the Python-included calendar module. The results of the program run as follows: The Python code is as follows: #coding: utf-8# last modified:2014-08-21 11:08:08 import calendar import datetime import sys def getcal (y, M): # Starting from Sunday Cal = Calendar. Calendar (6) if not isinstance (Y, int.): y = Int (

12{factory method of "Headfirst design mode" Factory mode}3{Product Class}4{compiler tool: Delphi2007 for Win32}5{Contact information: [Email protected]}67unit uproducts;89interface1011type{Abstract Pizza}13Tpizza = Class abstract (TObject)Strict privatefunction getname:string;Strict protectedfname:string;fdough:string;fsauce:string;PublicProcedure Prepare;Procedure Bake;Procedure Cut; VirtualProcedure Box;Name:string read GetName;End;28{NY Style Pizz

; intFlow =0, F; for(inti = Cur[u]; I ) {Edgee =Edges[g[u][i]]; if(D[u] +1= = D[e.to] (f = DFS (E.to,min (a,e.cap-e.flow))) >0) {E.flow+=F; Edges[g[u][i]^1].flow-=F; Flow+=F; A-=F; if(A = =0) Break; } } returnflow;}intMaxflow () {intFlow =0; while(BFS ()) {memset (cur,0,sizeof(cur)); Flow+=DFS (S,inf); } returnflow;} VectorVec;Const intN = -;CharS[n][n];intId[n][n];intDx[] = {1,0,-1,0};intDy[] = {0,-1,0,1};intMain () {//freopen ("In.txt", "R", stdin); intN,m; scanf"%d%d",n,m); int

and save the local according to the given range. void Jianqie (int MinX,int MaxX,int Miny,IntMaxy) {i++;var w = MaxX-MinX;var h = maxy-Miny;var img =NewBitmap (W,H); Graphics g =Graphics.fromimage (IMG); G.pageunit =GraphicsUnit.Pixel; G.drawimage (BMP,new RectangleF (0, 0, W, h), new RectangleF (MinX, Miny, W, h), GraphicsUnit.Pixel ); Img. Save (Bp+ "/" + i + ".png" for (int x = MinX; x for (int y = miny; y ) {BMP. SetPixel (x,y,color.transparent); } } } This is the last more important funct

_ (self, color): rgb = matplotlib. colors. colorConverter. to_rgb (color) im = np. empty (self. original_image.shape, self. original_image.dtype) im [:,:,: 3] = self. B _and_h [:,:, np. newaxis] im [:,:,: 3]-= self. color [:,:, np. newaxis] * (1. -np. arr Ay (rgb) im [:,:, 3] = self. alphaself. im = imdef get_stretched_image (self, stretch_factor): stretch_factor = max (stretch_factor, 1) ny, nx, nch = self. im. shapeny2 = int (

1#include 2#include 3#include 4 using namespacestd;5 6 intd[9][9];//Mark whether this point accesses and records distances7 intmaze[9][9]={8 1,1,1,1,1,1,1,1,1,9 1,0,0,1,0,0,1,0,1,Ten 1,0,0,1,1,0,0,0,1, One 1,0,1,0,1,1,0,1,1, A 1,0,0,0,0,1,0,0,1, - 1,1,0,1,0,1,0,0,1, - 1,1,0,1,0,1,0,0,1, the 1,1,0,1,0,0,0,0,1, - 1,1,1,1,1,1,1,1,1}; - Const intinf=1Ten; -typedef pairint,int>P; + intN,sx,sy,gx,gy; - intdx[4]={1,0,-1,0},dy[4]={0,1,0,-1}; + A intBFS () at { -mems

(); Q.pop (); -ret++; - for(inti =0; I 4; i++) - { - intNX = P.first + dx[i], NY = P.second +Dy[i]; - if(NX >=0 NX 0 NY Vis[nx][ny])) in { -Vis[nx][ny] =true; to Q.push (P (NX, NY)); + } - } the }

⊙) Well, the same as the example, from the @, search all the places you can go to, change it to a value (@ or what is true), and finally go through the map.1#include 2 Charch[ -][ -];3 voidSolveintHintW);4 voidFind1 (intHintW);5 voidDfsintXintYintHintW);6 intMain ()7 {8 inth,w,i;9 while(SCANF ("%d%d", w,h)!=eofh!=0w!=0)Ten { One GetChar (); A for(i=0; i) - gets (Ch[i]); - Find1 (h,w); the solve (h,w); - } - return 0; - } + - voidSolveintHintW) + { A intA=0; at

]); - for(intI=fr[t];i;i=Fr[fro[i]]) - { Av[i]-=MX; +v[i^1]+=MX; theans+=mx*W[i]; - } $ return; the } the intMain () the { the Charch[ -]; -scanf"%d%d",n,m); int=n*m*2+1; the for(intI=1; i) the { Aboutscanf"%s", ch+1); the for(intj=1; j) the { the if(ch[j]=='L') +mp[i][j]=0; - if(ch[j]=='R') themp[i][j]=1;Bayi if(ch[j]=='D') themp[i][j]=2; the if(ch[j]=='U') -mp[i][j]=3; - } the

Common Maze:Enter the end point of the maze and find the shortest path BFS exampleUse dist[][] array to record the shortest path of the start point to each point1#include 2#include 3#include 4#include string.h>5#include 6 using namespacestd;7 8 Const intMaxSize = -;9 Const intINF =0XFFF3;Ten intM,n; One intd[2][4] = { {-1,0,1,0}, {0,1,0, -1} }; A intDist[maxsize][maxsize];//Book Method: Use Dist[m][n] to store the shortest path initial INF indicates unreachable - structPos - { the intx, y; -

namespacestd;Const intMAXN = the;structnode{intx, y; intTime ; FriendBOOL operator//Time -Small priority high { returnA.time >B.time; }};p Riority_queue//Priority Queuestructcmap{intNX, NY;//record precursor, used to record the path CharC;} MAP[MAXN][MAXN]; //Record MapintN, M;intFIGHT[MAXN][MAXN], MARK[MAXN][MAXN];intBFS ()//start the search from the target point and search for the starting point. Record the search's precursor, and reco

uppercase Latin letter.OutputOutput "Yes" if there exists a cycle, and "No" otherwise. Examplesinput3 4AaaaAbcaAaaaOutputYesinput3 4AaaaAbcaAadaOutputNoinput4 4YyyrBybyBbbyBbbyOutputYesinput7 6AaaaabAbbbabAbaaabababbbAbaaabAbbbabAaaaabOutputYesinput2 13AbcdefghijklmNopqrstuvwxyzOutputNoNoteIn first sample test all 'a ' form a cycle.In second sample there is no such cycle.The third sample is displayed on the picture above ('Y ' = Yellow, 'B ' = Blue, 'R ' = Red). The main is to use DFS to dete