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Any axis can be expressed by a starting point and a direction vector. Then, you can first move the axis around any axis to the original point, then rotate it, and then reverse translate the new coordinates. The problem is to calculate the new point after the vector rotates any angle through the origin point. If the unit vector is (RX, Ry, Rz), the rotation matrix is as follows: Void rotate_point3d (float Theta, float NX, float NY, float NZ, float ( p

# Include Stdio. h > # Define Maxn 21 Int Map [maxn] [maxn]; Int Startx, starty; Int W, H, OK, minmove; Int Dr [ 4 ] [ 2 ] = {{ 1 , 0 },{ - 1 , 0 },{ 0 , 1 },{ 0 , - 1 }}; Int Legal ( Int X, Int Y ){ If (X > = 1 Y > = 1 X H Y W) Return 1 ; Return 0 ;} Void In (){ Int I, J; For (I = 1 ; I H; ++ I ){ For (J = 1 ; J W; ++ J ){Scanf ( " % D " , Map [I] [J]); If (Map [I] [

length of the end point, the second is always on the right priority, and four directions in the counterclockwise direction, until the length of the end; The third one is the shortest way.Problem Analysis: Obviously, the first two roads are DFS out, the third is the BFS out.The code is as follows:1# include2# include3# include4# include5# include6 using namespacestd;7 structnode8 {9 intx,y,t;TenNodeint_x,int_y,int_t): X (_x), Y (_y), T (_t) {} One }; A Charp[ -][ -]; - BOOLFlag; - intw,h,ans

once wrote a good C + + version, I added the comment in the key:C code #include #include "LineParamEstimator.h" Lineparamestimator::lineparamestimator (Double delta): m_deltasquared (Delta*delta) {} void Lineparamestimator::estimate (std::vector Std::vector { Parameters.clear (); if (Data.size () Return Double NX = data[1]->y-data[0]->y; Double NY = data[0]->x-data[1]->x;//the slope of the original line is k, the sl

(int I = 0; I {Int nTemp = 1;For (int j = 0; j {NMatrix [I] [j] = nTemp;NTemp = (nTemp * (I + 1) % nP;}}} Int egcd (int nA, int nB, int nX, int nY){If (nA If (nB = 0){NX = 1, nY = 0;Return nA;}Int nRet = egcd (nB, nA % nB, nX, nY );Int nT = nX;NX = nY;NY = nT-(nA/nB) *

); * floatNY =0.01f; $ floatNX = h (TX + NY, TZ)-y0;Panax Notoginseng floatNZ = h (TX, TZ + NY)-y0; - floatnd =1.0f/SQRTF (NX * NX + NY * NY + NZ *NZ); the floatD = (NX + ny-n

(errorcount)/Len (testset)returnVocablist, p0v, p1v4.7.2 Analysis Data: Displays the area-related terms#lexical display functions with the most table featuresdefgettopwords (NY, SF):Importoperator Vocablist, p0v, p1v=locablwords (NY, SF) TOPNY= []; TOPSF = []#Create a list for meta-ancestor storage forIinchRange (len (p0v)):ifP0v[i] >-6.0: Topsf.append ((Vocablist[i], p0v[i]))ifP1v[i] >-6.0: Topny.appe

limit step for the iterative deepening search{ if(flag)return; if(Nowstep>steplimit)return; if(map[x][y]==3) {flag=1; return; } if(Dir==stop) {//when the direction is stationary for(intI=0;i4; i++){ intnx=x+dx[i],ny=y+Dy[i]; if(map[nx][ny]==-1|| map[nx][ny]==1)Continue; DFS (Nx,ny,i,nowstep+1,

", State: "NY"});2.3. > Db.factories.ensureIndex ({metro:1});4.5. > Db.factories.find ({metro:{city: "New York", State: "NY"});//able to query with index6.7. {"_id": ObjectId ("4e244744cac1e3490b9033d2"), "name": "XYZ", "Metro": 8.9. {"City": "New York", "state": "NY"}10.> Db.factories.find ({metro:{$gte: {city: "New York"}});//able to query with index12.{"_id":

Pivot and Unpivot Use a simple SQL spreadsheet-type crosstab report to display information from any relational table and store all the data in a crosstab table in a relational table. PivotAs you know, relational tables are tabular, that is, they appear in the form of column-value pairs. Suppose a table name is CUSTOMERS.Sql> desc Customers Name Null? Type ---------------------------------------------------------------------------- cust_id number

that has already started and put it into an Oracle statspack user_log extension table.UpdatePerfstat.stats$user_logSetElapsed_minutes =Round (To_number (logoff_time-logon_time) *1440)whereuser = user_idandElapsed_minutes is NULL;Find out which days are included in any monthCREATE OR REPLACE FUNCTION get_workingdays (NY in VARCHAR2) RETURN INTEGER is/*------------------------------------------------------------------------------------------Function Na

Oracle table. In this example, we have an off-line (logoff) system-level trigger mechanism to calculate the session time that has already started and put it into an Oracle statspack user_log extension table.UpdatePerfstat.stats$user_logSetElapsed_minutes =Round (To_number (logoff_time-logon_time) *1440)whereuser = user_idandElapsed_minutes is NULL;Find out which days are included in any monthCREATE OR REPLACE FUNCTION get_workingdays (NY in VARCHAR2)

divided by 0 case is also considered;Code:#include #include#include#include#include#include#includestring>#includeusing namespacestd;Const intinf=0x3f3f3f3f;#defineSI (x) scanf ("%d", x)#definePI (x) printf ("%d", X)#defineP_ printf ("")#defineMem (x, y) memset (x,y,sizeof (x))typedef __int64 LL;Const intmaxn= -;CharMP[MAXN][MAXN];intdisx[4]={0,0,2,-2};intdisy[4]={2,-2,0,0};Doublesum;intFlot;intn,m;BOOLIsjs (Chara) { if(a=='+'|| a=='-'|| a=='*'|| a=='/')return true; Else return false;}Double

615 24 25 20 714 23 22 21 813 12 11 10 9Sample Output25 Very simple topic, once over, because the topic is required from the big to the small path, so there is no need to use vist to mark the node has been visited, the road itself is self-carrying property#include #include#include#include#include#include#includestring>#include#include#includeConst intINF = (1 to)-1;Const intMAXN = 1e2+Ten;using namespacestd;intDP[MAXN][MAXN];intVIST[MAXN][MAXN];intA[MAXN][MAXN];intn,m;intmov[4][2]={-1,0,1

! ='-' c'0'|| C>'9'); BOOLSign = c = ='-'; RET= sign?0: C-'0'; while(c = GetChar (), c>='0'c'9') ret = ret*Ten+ C'0'; returnsign?-Ret:ret;}Const intMAXN =305;intG[MAXN][MAXN];intD[MAXN][MAXN];Const intMxT =1001; typedef pairint,int>Node;Const intDx[] = {0,0,1,-1}, dy[] = {1,-1,0,0};BOOLValidintXinty) { returnx>=0x0yMAXN;}intBFs () {QueueQ; Q.push (Node (0,0)); d[0][0] =1; while(Q.size ()) {Node U=Q.front (); Q.pop (); if(g[u.fi][u.se] > MxT)returnd[u.fi][u.se]-1; intStep =d[u.fi][u.se]; fo

= (c). Begin (); I! = (c). end (); ++i) - Const intMax_n = the; - Const intMod = the; intypedef unsignedLong Longull; - Const intDx[] = {0,0, -1,1}, dy[] = {-1,1,0,0 }; to BOOLVis[max_n][max_n]; + CharMaze[max_n][max_n]; - intN, M, Res, fa[max_n][max_n], dir[max_n][max_n]; the structNode { * intx, y, S; $Node (inti =0,intj =0,intK =0): X (i), Y (j), S (k) {}Panax NotoginsengInlineBOOL operatorConstNode a)Const { - returns >A.S; the } + }; A voidBFs () { theCLS (Vis,false), CLS (

intnx=x+Dx[i]; - intny=y+Dy[i]; - if(map[nx][ny]==1)//Can't get through or walk through when you turn - Continue; - while(!map[nx][ny])//It 's a viable way to go until it's 0. - { innx=nx+Dx[i]; -ny=ny+Dy[i]; to } + if(check (Nx,

": "_id_", "ns": "Things.things", "key": {"_id": 1}, "V": 0} {"_id": ObjectId ("4e244382cac1e3490b9033d0"), "ns": "Things.things", "key": {"J": 1}, "name": "J_1", "V": 0} Default IndexFor each collection (except for the capped collection), the default is to create an index on the _id field, and this particular index cannot be deleted. The _id field is mandatory and is maintained by the database.Nested keywordsIn MongoDB, you can even build an index on an embedded document (embedded

, with the right and check set, is to restore and check set for a tree, and then change the FA when changing the good. This tree and the tree, of course, the less the number of the better.　　Weight I record is its horizontal and vertical axis and the difference between the father, change the father's time (that is, when abandoning the original father) to the father's weight added to his body and then modified.　　Then merge two trees, first put a point into that and check the tree with, in fact, do

;}intDfsintXinty) { if(dp[x][y]!=-1)returnDp[x][y]; Dp[x][y]=A[x][y]; intNx,ny; /*for (int i=k;i>=0;i--) {for (int j=k-i;j>=0;j--) {if (i+j==0) continue; for (int w=0;w*/ //every time it's one-way. for(intI=0;i4; i++){ //NX = x+move[j][0]; //NY = y+move[j][1];NX =x; NY=y; for(intj=1; j){ if(i==0) NX = x+J; Else if(i==1)