calculate distance between two coordinates latitude longitude

The formula is as follows, unit meters:1th latitude and Longitude: lng1 LAT12nd latitude and Longitude: lng2 lat2Round (6378.138*2*asin (sqrt (POW (LAT1*PI ()/180-lat2*pi ()/180)/2), 2) +cos (Lat1*pi ()/180) *cos (LAT2*PI ()/180) * Pow (Sin ((Lng1*pi ()/180-lng2*pi ()/180)/2), 2)) *1000)For example:SELECTSTORE_ID,LngLa

function Getdistancebetweenpointsnew ($latitude 1, $longitude 1, $latitude 2, $longitude 2) { $theta = $longitude 1-$longitude 2; $miles = (sin (Deg2rad ($latitude 1)) * S

PHP Code: Reprint http://www.cnblogs.com/caichenghui/p/5977431.html1 /**2 * Find the distance between two known longitude and latitude, in meters3 * 4 * @param lng1 $, lng2 longitude5 * @param lat1 $, lat2 latitude6 * @return float distance, Unit meter7 * @author www.Alixixi.com8 */9 functionGetdistance ($LNG 1,$lat

Recently, we used the formula for calculating the distance between two points on the earth's surface based on latitude and longitude, and then implemented it using Js. There are two ways to calculate the distance between two points on the Earth's surface. First, the Earth is

The calculation formula from Google Maps:Called by various methods of the math class in Java. Implement the above formulaprivate static Double Earth_radius = 6378.137;//unit kilometer/** * Angular radian Calculation formula RAD: (). Calculation of latitude and longitude distance between Hefei and Hangzhoupublic static void Main (String ar[]) {getdistance (31.86,

SQL SERVER formula for calculating distances based on map latitude and longitude Copy Code code as follows: Go --Create latitude and longitude distance calculation function createfunction [dbo]. [Fngetdistance] --latbegin begins

#region get the distance between two points (latitude and longitude representation)Get the distance between two points (latitude and longitude representation)public static double Getdistance (double P1lat, double p1lng, double P2l

Principle:The Earth's equator orbits around the earth a total of 40075.04 kilometers a week, while the @ lap is divided into 360 °, and each 1° (degree) has 60, the length of each second on the equator is calculated as follows: 40075.04km/360°=111.31955km 111.31955km/60=1.8553258km=1855.3m And each point has 60 seconds, every second represents 1855.3m/60=30.92m Any two-point distance calculation formula is D=111.12cos{1/[sinφasinφb 10 Cosφacosφbcos (λ

By latitude, the database is compared stringbuffer SB = new StringBuffer () sb.append ("Select TimeKey,") Sb.append ("ROUND (6378.138*2*asin ( SQRT (POW (Sin (*pi ()/180-lat*pi ()/180)/2), 2), Sb.append (+cos (? *pi ()/180) *cos (Lat*pi ()/180) *pow (Sin ((? *pi ()/) ); Sb.append ("180-lng*pi ()/180)/2), 2)) *1000) as JL") Sb.append ("From T_news have JL Mysql takes a distance comparison between the specifi

Calculate the distance from GPS coordinates of two pointspublic static double Distance (double n1, double e1, double N2, double E2){Double JL_JD = 102834.74258026089786013677476285;Double jl_wd = 111712.69150641055729984301412873;Double b = Math.Abs ((e1-e2) * JL_JD);Double A = Math.Abs ((n1-n2) * jl_wd);Return Math.sq

This is a known distance between two points. Can you see if it is helpful? Hope it will be helpful to you!'----------------------------------------------------------------------'The known longitude and latitude Distance Function'----------------------------------------------------------------------Function countdist

Calculates the spherical distance between 2 points on the Earth's surface/** * @param $lat 1 * @param $lng 1 * @param $lat 2 * @param $lng 2 * @return int*/functionGetdistance ($lat 1,$LNG 1,$lat 2,$LNG 2){ //turn angle into Fox degree $radLat 1=Deg2rad($lat 1);//the Deg2rad () function converts an angle to radians $radLat 2=Deg2rad($lat 2); $radLng 1=Deg2rad($LNG 1); $radLng 2=Deg2rad($LNG 2); $a=$radLat 1-$radLat 2; $b=$radLng 1-$radLng 2;

/***@desc根据两点间的经纬度计算距离*@paramfloat$lat纬度值*@paramfloat$lng经度值*/functiongetDistance($lat1,$lng1,$lat2,$lng2){$earthRadius=6367000;//approximateradiusofearthinmeters/*Convertthesedegreestoradianstoworkwiththeformula*/$lat1=($lat1*pi())/180;$lng1=($lng1*pi())/180;$lat2 =($lat2*pi())/180;$lng2=($lng2*pi())/180;/*UsingtheHaversineformulahttp://en.wikipedia.org/wiki/Haversine_formulacalculatethedistance*/$calcLongitude=$lng2-$lng1;$calcLatitude=$lat2-$lat1;$stepOne=pow(sin($calcLatitude/2),2)+cos($lat1

Tags: style blog http ar sp on log efDECLARE @BJ GEOGRAPHYDECLARE @XT GEOGRAPHY/*GET Latitude/longitude from Here:http://www.travelmath.com/cities/beijing,+chinaThe distance unit in SRID 4326 is the meter*/SELECT @BJ = Geography::P oint (' 39.92889 ', ' 116.38833 ', 4326)SELECT @XT = Geography::P oint (' 37.0630556 ', ' 114.4941667 ', 4326)SELECT@BJ as Beijing,@X

Java known two locations latitude and longitude distance (very accurate) Package com.lbnet.lzx.util; public class GoogleMap {Private static final Double Earth_radius = 6378.137;private static Double rad (double D){return d * math.pi/180.0;}/*** ????}????????????? /γ???* @param LAT1* @param lng1* @param lat2* @param lng2* @return*/public static double Getdistanc

1 DROP FUNCTION IF EXISTS ' getdistance ';2 DELIMITER;;3 CREATE FUNCTION ' getdistance ' (4Lon1 Float (10,7) 5, Lat1 float (10,7)6, Lon2 float (10,7) 7, Lat2 float (10,7)8 ) RETURNS Double9 beginTen declare d double; One declare radius int; ASet radius = 6378140; -Set D = (2*atan2 (SQRT (SIN (LAT1-LAT2) *pi ()/180/2) -*sin ((LAT1-LAT2) *pi ()/180/2) + theCOS (Lat2*pi ()/180) *cos (LAT1*PI ()/180) -*sin ((Lon1-lon2) *pi ()/180/2) -*sin ((Lon1-lon2) *pi ()/180/2)), -SQRT (1-sin (LAT1-

Earth radius, Unit m Private Const double Earth_radius = 6378137; 　　C # Calculates the distance of two latitude and longitude

Recently do something encountered to be based on the two-point latitude and longitude of the distance between the calculation, on-line looked up the next information. Because this kind of contact is relatively few, directly to find the ready-made code, not how to study. The code is as follows, as a record.Private Const Double Earth_radius = 6378.137;//Earth radiu

C # Two-point distance function for known latitude and longitude calculation Public task Above is the C # latitude and longitude calculated two points distance function content, more relevant content please pay attention to t

The latitude and longitude of a given two point. Calculates the distance between two points. Note that latitude and longitude must be filled in order.1. Use the tools in Android to get the units in metersFloat[] Results=new float[1]; Location.distancebetween (