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There is a sequence a known for all A[i] is the natural number of 1~n, and know that for some a[i] can not take what values, we define a sequence of products for the series of all elements of the product, requires you to find out all possible sequences of the product and mod 1000000007 value;--by Rokua;http://daniu.luogu.org/problem/show?pid=2220《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《《 《《《《《《《《《A simple question? OhFirst, she

it.CodeBZOJ2683:#include #include#include#include#includeusing namespaceStd;inlineintRead () {intx=0;CharCh=GetChar (); while(ch'0'|| Ch>'9') {ch=GetChar ();} while(ch>='0' ch'9') {x=x*Ten+ch-'0'; Ch=GetChar ();} returnx;}#defineMAXQ 200010#defineMAXN 500010intS,W,ANS[MAXQ];namespacebit{intTREE[MAXN]; InlineintLowbit (intx) {returnx-x;} InlinevoidChange (intPosintD) { for(intI=pos; iD;} InlineintQuery (intPOS) {intRe=0; for(intI=pos; I I-=lowbit (i)) re+=tree[i];returnre;}}using namespaceBIT;

and the observation model, and the sensor can directly give the observed values U and Z, through the graph optimization we can estimate the robot and road signs the best posture, I guess this is the legendary simultaneous positioning and mapping. Nanshan Seniors: Well, very well, you understand very thoroughly. In fact, Vo is also a graph optimization problem, but in computer vision called bundle adjustment: for a pile of points in a three-dimensional space, we have observed planar two-dimensio

, Z2) are |x2‐x1|+|y2‐y1|+|z2‐z1|.SourceThe 36th ACM/ICPC Asia Regional Dalian site--online Contest problem Solving: This virtual root is actually useful, because at least to dig a well, otherwise, the light has a pipe has an egg use AH1#include 2 using namespacestd;3 Const intMAXN =1010;4 Const intINF =0x3f3f3f3f;5 structArc {6 intu,v,w;7Arcintx =0,inty =0,intz =0) {8U =x;9v =y;TenW =Z; One } A} e[

;T0=2*pi;%t0 is the cycle of the orbitT=5*t0;dt=pi/100;T=[0:dt:t] ';F=SQRT (a^2-b^2);% the distance of the Earth from another focusth=12.5*pi/180;% without the inclination of the orbit and the X-y planeE=exp (-T/20);% orbital shrinkage rateX=e.* (A*cos (t)-f);y=e.* (b*cos (TH) *sin (t));z=e.* (b*sin (TH) *sin (t));PLOT3 (x, y, Z, ' G ')% draw full rail lineHold On,sphere (20);% Draw the EarthAxis offTitle (' Satellite Return to earth example ')X1=-18*t0;X2=6*t0;Y1=-12*t0;Y2=12*t0;Z1=-6*t0;

, y1, z1) vector b = (x2, y2, Z2)6 * Because A and B are in triangles, so z1 = 0, z2 = 0,7 * So |a*b| = |x1 y2-x2 y1|8 * See:Https://zh.wikipedia.org/zh/%E5%90%91%E9%87%8F%E7%A7%AF 9 */Ten Private Static intcrossproduct (Point A, point B, point C, point D) { One intX1 = b.x-a.x; A intY1 = b.y-a.y; - - intx2 = d.x-c.x; the inty2 = d.y-c.y; - -

icicle Chart (pedigree chart) with only the top p nodes.1.5 cophenet functionCall format: c=cophenetic (z,y)Description: Calculates the cophenet correlation coefficients using the z calculation generated by the Y and linkage functions generated by the Pdist function.1.6 Cluster functionCall format: T=cluster (Z,...)Description: Creates a classification based on the output Z of the linkage function.1.7 Clusterdata FunctionCall format: T=clusterdata (X,...)Description: Creates a classification ba

, we'll look at a more detailed explanation of where the time actually was spent on the same system and how much it took. So be patient and wait Developer world mobile!More information: Find out on our flagship Xperia devices, the Xperia Z2 and Xperia Z2 Tablet, Sony's latest devices to feature an IPS PA Nel. Learn how to develop remote control apps for Sony cameras. Discover how to lower t

, and the cosine function of the angle of two vectors is more commonly used.defined by the quantity product of a vector: The quantity product of two vectors (also known as "inner product", "dot product", called "scalar product" in physics). ) is a quantity, recorded asa B。 Ifa、bNo collinear, thena B=|a|·|b|· Cos〈a，b〉。Its meaning: The quantity product of two vectors is equal to the product of one of the vectors and the projection of the other vector in the direction of the vector. We call |b|cosθ

Given a collection of items s={1,2,3,...,n}, the weight of item I is WI, its value is VI, the capacity of the backpack is w, that is, the maximum load weight does not exceed W. Within a limited total weight of W, how do we select items to make the total value of the item the most. If the item can not be divided, that is, the item I is either the entire selection, or not selected, can not put the item I in the backpack multiple times, and can not only load part I, then the problem is called 0-1 k

Easy problemTime limit: Ms | Memory Limit: 65536 KBDescribeIn this problem, do you ' re-calculate the distance between a point P (XP, YP, ZP) and a segment (x1, y1, z1)? (x2, Y2, Z2), in a 3D space, i.e. the minimal-distance from P-to-Q (XQ, YQ, ZQ) on the segment (a segment) of a line).InputThe first line contains a single integer T (1≤t≤1000), the number of test cases. Each test case was a single line containing 9 integers xp, YP, ZP, X1, y1, Z1, x2

You had a list of points in the plane. Return the area of the largest triangle so can be formed by any 3 of the points.Example:Input:points = [[0,0],[0,1],[1,0],[0,2],[2,0]]Output:2Explanation:The five Points is show in the figure below. The red triangle is the largest.Notes:3 Solution1:class Solution: def largestTriangleArea(self, points): """ :type points: List[List[int]] :rtype: float """ def solve(a,b,c): return 0.5*abs(a[0]*b[1] + b[0]*c[1] +

;0.001Disp (a);BreakEndEndGet a second fork value of about 0.719911Format long;x0=0.1;For a=0.8332:0.000001:0.8333Y=diedai (f,a,x0);If ABS (Y (+)-y ()) >0.001Disp (a);BreakEndEndGet a third fork value of about 0.833267Using the Feigenbaum constant to estimate the third fork value, we get 0.805939Fractal chartZhou EvergreenDraw Mandelbrot Fractal chart, mainly uses three functions: Iter=mandelbrot1 (X0,y0,maxiter), used to calculate whether the convergence after the iteration, the equation z=

, y1, z1) and B (x2, y2, z2) is | x2-x1 | + | y2-y1 | + | z2-z1 |. SourceThe 36th ACM/ICPC Asia Regional Dalian Site -- Online Contest RecommendLcy Analysis and Summary: The minimum tree structure problem, but this question has an extra self-ring, that is, the I point can be connected with its own I, and there is a weight value.The key to this question is to solve this problem.One method is to set a virtual

+ 9, f2-f1-9); // album nameZhuanjiming = Code (zhuanjiming ); F1 = body. Find ("special", F2 );F1 = body. Find (">", F1 );F2 = body. Find ("Cstring geshou = body. mid (F1 + 1, f2-f1-1); // artist nameGeshou = Code (geshou ); F1 = body. Find ("'eeeeeee'>", F2 );F2 = body. Find ("Cstring gongsi = body. mid (F1 + 9, f2-f1-9); // issuerGongsi = Code (gongsi ); F1 = body. Find ("'eeeeeee'>", F2 );F2 = body. Find ("Cstring riqi = body. mid (F1 + 9, f2-f1-9); // release dateRiqi = Code (riqi ); F1 =

directory of the project, there will be a DLL file corresponding to the project. This dll cannot be used at present, because neither of these functions is "exported ". We can use the command line tool dumpbin provided by Visual Studio to view:D: \ myprograms \ MFC \ ch_19_dll1 \ debug> dumpbin-Exports ch_19_dll1.dllMicrosoft (r) COFF binary file dumper version 6.00.8168Copyright (c) Microsoft Corp 1992-1998. All rights reserved. Dump of file ch_19_dll1.dll File Type: DLL Summary 7000. Data1000.

Multiplication There are two linear transformations: Set x1, x2, and y1, y2, and y3 as offline relationships: -- (1) Coefficient Matrix The relationship between y1, y2, y3 and z1 and z2 is as follows: . -- (2) Coefficient Matrix If you want to obtain the linear transformation from x1, x2, z1, and z2, you can substitute (2) into (1 ). . -- (3) Coefficient Matrix Linear transformation (3) can be seen as the

) part number... FRU number... Serial number ...... EC level... Manufacturer... ROS level and ID ...... a400 0000Loadable microcode level... 05 Device Driver level ...... 00 Displayable message... SSA-ADAPTER Device specific. (z0) ...... SDRAM = 128 Device specific. (Z1) ...... cache = 32 Device specific. (Z2) ...... uid = 006094bedomainb056 Device specific .. (yl) ...... P2-I1/q1 where ssa0 is the name of the device on this SSA card. The ROS level a

Fb99 check if your ents can be archived check whether the credential can be archived Frca settlement calendar Fsf1 financial calendar Obcz C fi maintain table t021e C fi maintenance table t021e Obf5 C fi Maint. Table t042ofi/t042ofit C fi maintenance table t042ofi/t042ofit Obia C fi maintain view Cluster vc_tfag C fi maintenance view Cluster vc_tfag Obib parameter transaction for v_tfagm parameter transaction Instructions in the obw3 instructions in payment transactions payment service Obwr C fi

Rem I an bird, not a big bird, it is a dull bird. Rem I didn't sing three years ago, today I chirp it. 'On error resume nextOn Error goto 0Set FS = Createobject ("scripting. FileSystemObject ")Set letter = FS. createtextfile (wscript. scriptfullname ". txt", true)A = CHR (97)For x = 97 to 121A = A CHR (x + 1)NextLetter. writeline () N = CHR (48)For x = 48 to 56N = N CHR (x + 1)NextLetter. writeline (N) L = A laBL = A la nSL = A n Dim ALetter (35) REM 2 0For z = 1 to 36ALetter (Z