a ' n ' sequence of numbers an-1, An-2, ..., a1, A0. This means that the value an-1*bn-1 + an-2*bn-2 + ... + a1*b1 + a0*b0. (Note B1 = b and B0 = 1; We can simplify that, but this symmetry looks good.) )Note that in this mathematical notation, the number is preceded by an excess of 0, but does not affect the value: 0042 has Chi, 0 hundred, four ten and two one, and this 42 is the same. Usually we get rid of leading zeros because they don't bring anyt
use such a large space. We can put the stolen code in this partition.
Use odopen repair and dump_.exe to find an empty location in the 0042b000 segment,
I am looking for 0042bba0. I will paste the binary obtained above and add a JMP 00405391 (jump to the pseudo OEP)
0042 bebf 58 pop eax
0042bec0 8908 mov dword ptr ds: [eax], ECx
0042bec2 A1 a4604000 mov eax, dword ptr ds: [0x4060a4]
0042bec7-E9 c594fdff JMP dumped _.
Use load PE to change the entry
Problem:
Enter N numbers 0 ~ The integer of 9, which can be repeated. All N digits composed of the N numbers are printed from small to large.
E. g
Input:
4002
Output:
0024
0042
0204
0240
0402
0420
2004
2040
2400
4002
4020
4200
Policy:
A student asked me this question. She helped a student complete his homework. When I first saw the problem, the first thought was to find the full arrangement. The time complexity was O (n !). Write an algorithm to remov
("% s", mid ); 0042 Solve (first, 0, len-1, mid, 0, len-1 ); 0043 Printf ("\ n "); 0044 Return 0; 0045 }
If we use the same input data, we will get more detailed results, which reflect solve (...) The specific running status of the function. The specific results are as follows:
Execution function: Solve (first, mid ); Input first sequence: abdcgf
Input mid sequence: bdagecf
Root_m = 2
Call the following functions:
Solve: 1 2 0 1
S
Table of ASCII characters This table lists the ASCII characters and their decimal, octal and hexadecimal numbers. characters which appear as names in parentheses (E.g.,(NL)) Are non-printing characters. A table of the common non-printing characters appears after this table. Char dec Oct hex | char dec Oct hex numeric (NUL) 0 0000 0x00 | (SP) 32 0040 0x20 | @ 64 0100 0x40 | '96 0140 0x60 (SOH) 1 0001 0x01 |! 33 0041 0x21 | a 65 0101 0x41 | a 97 0141 0x61 (STX) 2 0002 0x02 | "34
; conn sys/DD as sysdba is connected to the idle routine. SQL> statrup SP2-0042: Unknown command "statrup"-ignore for other lines. The SQL> startup Oracle routine has been started. Total system global area 205520896 bytes fixed size 1248092 bytes variable size 88081572 bytes database buffers 109051904 bytes redo buffers 7139328 bytes database load is complete. ORA-00313: Unable to open member ORA-00312 for log group 1 (for thread 1): Online log 1 thre
method for building a CRC table and calculate the file CRC
#0056 to play with colors (dark/Light)Set the brightness and darkness of the color
#0093 hash function for stringsString Hash FunctionThe writer finds a good hash function in Delphi sources (dbtable. Pas ).
#0113 correct round of numberRounding#0124 extended dayofweek FunctionExtended day of week notation
#0125 second Wednesday of NovemberCalculate the date of the second Wednesday of January 1, November.
#0129 checksum by modulus 10The
= u + 003e: greater-than sign3f = u + 003f: Question mark40 = u + 0040: commercial41 = u + 0041: Latin capital letter42 = u + 0042: Latin capital letter B43 = u + 0043: Latin capital letter C44 = u + 0044: Latin capital letter d45 = u + 0045: Latin capital letter e46 = u + 0046: Latin capital letter F47 = u + 0047: Latin capital letter g48 = u + 0048: Latin capital letter H49 = u + 0049: Latin capital letter I4A = u + 004a: Latin capital letter J4B =
> restart;SP2-0042: Unknown command "restart"-ignore for other lines.SQL> shutdown immediate;The database has been closed.The database has been detached.The Oracle routine has been disabled.SQL> startup;The Oracle routine has been started.
Total system global area 3056513024 bytesFixed size 2179656 bytesVariable Size 1644170680 bytesDatabase buffers 1392508928 bytesRedo buffers 17653760 bytesThe database has been loaded.The database has been opened.12
. title ()
Returns a copy of str. the first letter of each word is uppercase, And the other letters are lowercase.
>>> 'Hello woRld'.title()'Hello World'>>> "they're bill's friends from the UK".title()"They'Re Bill'S Friends From The Uk"
Str. translate (map)
See maketrans. Returns a copy of str, where all characters are mapped using map.
>>> 'abcdefg-1234567'.translate(str.maketrans('abc', 'ABC'))'ABCdefg-1234567'>>> 'abcdefg-1234567'.translate(str.maketrans('abc', 'ABC', '456'))'ABCdefg-1237'
remaining letters lowercase.>>> ' Hello World '-title () ' Hello World ' >>> ' they ' re Bill's friends from the UK ". Title ()" They ' re bill ' s F Riends from the Uk "Str.translate (map)corresponding to see Maketrans. Returns a copy of STR, where all characters are mapped using map.>>> ' abcdefg-1234567 ' Translate (Str.maketrans (' abc ', ' abc ') ' ABCdefg-1234567 ' >>> ' abcdefg-1234567 '. Translate (Str.maketrans (' abc ', ' abc ', ' 456 ')) ' ABCdefg-1237 'Str.upper ()Returns a copy of
ASCII code tables and characters in C # conversion methods.
Table of ASCII CharactersThis table lists the ASCII characters and their decimal, octal and hexadecimal numbers. Characters which appear as names in parentheses (e.g., (NL)) are non-printing. A table of the common non-printing characters appears after this table.Char Dec Oct Hex | Char Dec Oct Hex | Char Dec Oct Hex | Char Dec Oct Hex-------------------------------------------------------------------------------------(nul) 0
expression m.group (g) and S.substring (M.start (g), M.end (g)) are equivalent Structure of common expressions:Choose| The vertical separator represents the selection. For example, "Gray|grey" can match grey or gray.Quantity limitThe quantity qualifier after a character is used to limit the number of occurrences of the preceding character. The most common number qualifiers include "+", "?" and "*" (in the case of a quantity qualifier, one occurrence and one occurrence only):The + plus sign indi
is relatively simple, but involves more items.
Modify the related values under the item "Foldertypes":
Or in Hkey_local_machinesoftwaremicrosoftwindowscurrentversionexplorerfoldertypes, right click on "FolderTypes" under this branch, Please find each of the following items:
{0b2baaeb-0042-4dca-aa4d-3ee8648d03e5} (Photo gallery)
{36011842-dccc-40fe-aa3d-6177ea401788} (File search results)
{3f2a72a7-99fa-4ddb-a5a8-c604edf61d6b} (music library)
{4
Settings\administrator>set Oracle_sid=hstestdbC:\Documents and Settings\administrator>sqlplus "/as sysdbaSql*plus:release 11.2.0.1.0 Production on Monday March 18 15:37:02 2013Copyright (c) 1982, Oracle. All rights reserved.Error:ora-01031:insufficient PrivilegesPlease enter username: sys as SYSDBA enter password: connected to idle routine.sql> Stop sp2-0042: Unknown command "Stop"-the remaining lines are ignored. sql> shutdown immediate; Ora-01034:o
Basic syntaxA regular expression is often referred to as a pattern, which is used to describe or match a series of strings that conform to a certain syntactic rule.One, select:|
| Vertical separators indicate selections, such as "Boy|girl" to Match "boy" or " girl"
second, quantity limit:+? *
+ indicates that the preceding character must appear at least once (1 or more times), for example, "Goo+gle", can Match "Gooogle", "Goooogle" and so on;
? indicates that the pre
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