cipher encoder

Transmission DoorKind of a template.The topic says loop, then copy a bunch of stitching on it.Then we can find the suffix array, and then we'll do it.Although it is the suffix, there will be more strings in the back, but the topic is that the loop, but there is no effect.--code1#include 2#include 3#include 4 #defineN 2000055 6 intm ='Z'+1;7 intLen, Buc[n], x[n], y[n], sa[n];8 CharS[n];9 TenInlinevoidBuild_sa () One { A intI, K, p; - for(i =0; I 0; - for(i =0; i ; the for(i =1;

string.Sample InputJSOI07Sample OutputI0o7sjHINTThe length of the data string for 100% does not exceed 100000.Idea: a template title for the suffix array.We just need to copy this string to the back, and then handle the SA, which in turn outputs the starting point in the ranking.#include #include #include #include using namespace STD;#define N n*2-1Const intm=200100;CharCH[M];intn,m=0, Sa[m],t1[m],t2[m],c[m];voidBuild_sa () {intI,p,k,*x=t1,*y=t2; for(i=0; i0; for(i=0; i for(i=1; i1]; for(i=n-1;

]]--]=i; intln=1, p=0; while(pN) {intk=0; for(inti=n-ln+1; ii; for(intI=1; iif(sa1[i]-ln>0) sa2[++k]=sa1[i]-Ln; memset (Rsort,0,sizeof(Rsort)); for(intI=1; i; for(intI=1; i1]; for(inti=n;i>=1; i--) sa1[rsort[rank[sa2[i]]]--]=Sa2[i]; for(intI=1; iRank[i]; rank[sa1[1]]=1;p =1; for(intI=2; i) { if(tt[sa1[i]]!=tt[sa1[i-1]]|| tt[sa1[i]+ln]!=tt[sa1[i-1]+LN]) p++; Rank[sa1[i]]=p; } LN*=2; m=p; }}intMain () {scanf ("%s", A +1); intN=strlen (A +1); for(inti=n+1; i1; i++) a[i]=a

\ (S[sa[i] + n-1] (s=input+input,sa[i]#include #include #include #include #include #include #include using namespaceStd#define N 200001#define REP (I, A, b) for (int i = A; I #define DRP (i, A, b) for (int i = A; I >= b; i--)#define LL Long Longinline intRead () {intx =0, flag =1;Charch = getchar (); while(!isdigit (CH)) {if(! (ch ^'-')) flag =-1; ch = getchar (); } while(IsDigit (ch)) x = (x 1) + (x 3) + CH-' 0 ', ch = getchar ();returnx * FLAG;}intNCharIn[n];intS[n];intSa[n], T1[n], t2[n], c[

]~/MNT # Touch Txt[email protected]~/mnt # VIM txt [email protected]~/mnt # cat txt123456[email protected]~/mnt # ls123Txt[email protected]~/MNT # lltotal4-rw-r--r--1Root root0June2 on: $ 123-rw-r--r--1Root root7June2 on: $Txt[email protected]~/MNT # CD.5. Uninstall shutdown[Email protected] ~~ ~ # ll/dev/0crw1236 June 1:Third, encrypt the whole systemHttps://wiki.archlinux.org/index.php/Dm-crypt/Encrypting_an_entire_systemThere are various ways to include boot partition encryption and so on.

First, Reason:Before because the server can only login, and limit the root account login, so ssh through all the server, to achieve the public key forward SCP free password, etc., greatly facilitate the management of the server.Recently there is a need to do offsite backup of data. The simplest use of SCP script, but script manual execution is OK, put crontab does not work properly.Second, the solution:Script execution failed, immediately thought to print verbose log debug, that scp-v then read

http://www.lydsy.com/JudgeOnline/problem.php?id=1031It is easy to think of this as copying the string to its end and then the suffix array out of the SA and output by the interval.Then change the template and put the cardinal sort outside#include Suffix array of the original: #include 　　 DescriptionLike to delve into the problem of JS classmate, and recently fascinated by the encryption method of thinking. One day, he suddenly came up with what he thought was the ultimate encryption: to

Because it is a ring, it can be reproduced in the back again.#include 　　bzoj1031: [JSOI2007] character encryption cipher suffix array

other system's user name and password calculation, import ucenter uc_members table, to achieve user migration. For example, if the original system uses an algorithm such as MD5 (password) to save the password, then the program randomly generated salt, and then calculate the cumulative MD5, so it is easy to calculate the user in the Ucenter user password hash value, so as to achieve seamless user migration. However, if the original system is using MD5 (Password+salt) to save the password, it wil

The code puts this aside for backup.#include Des cipher algorithm

given:07jsoi-->07+......+i7jsoi0-->7+......+0I07jso-->i07+......+ojsoi07-->jsoi07+ (7)Oi07js-->oi07+......+sSoi07j-->soi07+jyou can see that 07,7,i07,jsoi07,oi07,soi07 is all the suffixes of the original string, so we only need to sort these suffixes when sorting. This will use the suffix array. Note: Because it is annular, it is necessary to first copy the multiplication string, get the new string, and giveNew StringThe first half of the sequence, and then output each in the multiplication aft

306-cipher Time limit:3.000 seconds Http://uva.onlinejudge.org/index.php?option=com_onlinejudgeItemid=8category=115page=show_ problemproblem=242 http://poj.org/problem?id=1026 Bob and Alice started to use a brand-new encoding scheme. Surprisingly it is isn't a public Key cryptosystem, but their encoding and decoding are based on the secret keys. They chose the secret key at their's last meeting into Philadelphia on February 16th, 1996. They chose

Error Laravel Access No supported Encrypter found. The cipher and/or key length is invalid Go to project directory, enter commandBuild configuration file PHP Artisan Key:generate Tips [Errorexception] File_get_contents (/USERS/WXX/PHPSTORMPROJECTS/XXLARAVEL/.ENV): Failed to op en stream:no such file or directory Tip No. env fileGo

Public Static voidMain (string[] args) {Try{String plaintext= "Duwenlei"; Keypairgenerator Keypairgenerator= Keypairgenerator.getinstance ("RSA"); Keypairgenerator.initialize (2048); KeyPair KeyPair=Keypairgenerator.generatekeypair (); //SignatureMessageDigest MD = messagedigest.getinstance ("SHA1"); byte[] Enchash =md.digest (Plaintext.getbytes ()); Pkcs8encodedkeyspec KeySpec=NewPkcs8encodedkeyspec (Keypair.getprivate (). getencoded ()); Keyfactory keyfactory= Keyfactory.getinstance ("RSA"); K

This article introduces two methods of cipher encryption, these two are very common can be found at random Baidu. 1. Morse Code; Say password encryption has to be put to the method. It's a classic. First of all, tell him the comparison table, directly above the picture. The core idea is to replace the plaintext cipher and replace the characters with the. two symbols; 2, fence password; The so-

In cryptography, Caesar's code (or Caesar's encryption, Caesar's transformation) is one of the simplest and most widely known cryptographic techniques. It is a technique for replacing encryption, in which all letters in plaintext are replaced by a fixed number of Cheng Mi-wen (or forward) after the alphabet is offset. For example, when the offset is 3, all the letters A will be replaced with D,B into E, and so on. This method of encryption was named after Caesar, who had used this method to comm

1654. Cipher MessageTime limit:1.0 SecondMemory limit:64 MBMüller tried to catch Stierlitz red-handed many times, but alwaysfailed because Stierlitz could ever find some excuse. Once Stierlitz waslooking through his email messages. At this moment, Müller enteredsecretly and watched a meaningless sequence of symbols appear on the screen. " A cipher message, "Müller thought." UTF-8, "Stierlitz thought. It is

Topic: Given a string, the starting position of the loop string, you can get a different string length, ask to sort these strings after the first bit of each string is what.Idea: The suffix array is bare, just multiply the entire string and then ask the SA.CODE:#include Bzoj 1031 Jsoi 2007-character encryption cipher suffix array

IMail all post office information, such as users, passwords are actually stored in the computer registry, so you only need Open the registry to see all the information in the IMAIL, including the user's password. Details: IMail stores All enterprise Post office information in: Hkey_local_machine\software\ipswitch\imail\domains\In such a key, where DomainName is the name of the post office, USERNAME is the username, and under 1. Read the username and convert it all to lowercase 2. Convert user na

password, the wrong password will be prompted to error, this is the characteristics of the password, passwords are generally the wrong password, and passwords generally do not prompt, of course, is not absolute, such as the previous winrar will be prompted, or my own design of the password key tool ( Keymanager), the password error will also prompt, this does not mean that it is a password, the reason is prompted because the clear text of the one-way hash value and the original plaintext of the