class 2 div 2 enclosure

Codeforces Round #277 (Div. 2) --- A. Calculating Function (regular) Calculating Function Time limit per test1 secondmemory limit per test256 megabytesinputstandard inputoutputstandard output For a positive integerNLet's define a functionF: F(N)? = ?? -? 1? +? 2? -? 3? + ?..? +? (? -? 1)NN Your task is to calculateF(N) For a given integerN.Input The single line c

): = i-1 break print(n)PYD-taxesThe minimum number of answers that can be decomposed into prime numbers is three kinds of 1 2 3 We first consider the ANS = 1 of Prime Numbers.Not prime but an even number goldbach guess ans = 2It's not prime, but it's odd. if he can have two prime numbers, then one of them must be 2. You need to determine if n-2 is a

]; -Val_max[cur] =-INF; theVectortemp; - for(Auto to:g[cur]) - { - if(to = = FA)Continue; + dfs (to, cur); -Val_max[cur] =Max (Val_max[cur], val_max[to]); +Sum[cur] + =Sum[to]; A Temp.push_back (Val_max[to]); at - } -Sort (Temp.begin (), Temp.end (), greater()); - if(Temp.size () >=2) - { -ans = max (ans, temp[0] + temp[1]); in } -Val_max[cur] =Max (Val_max[cur], sum[cur]); to + } - the intMain () * { $ intN;Pan

Codeforces #264 (Div. 2) D. Gargari and Permutations, Gargari got bored to play with the bishops and now, after solving the problem about them, he is trying to do math homework. In a math book he have foundKPermutations. Each of them consists of numbers1, limit 2, limit..., limit ,...,NIn some order. Now he shocould find the length of the longest common subsequen

yellow cards = a red card = Sent off the game. Asking you to be sent off as time increases. The following:Do not repeat the output sent off the same person the situation is that the violence///Meek#include using namespaceStd;typedefLong Longll;#defineMem (a) memset (A,0,sizeof (a))#definePB Push_backinline ll read () {ll x=0, f=1;CharCh=GetChar (); while(ch'0'|| Ch>'9'){ if(ch=='-') f=-1; ch=GetChar (); } while(ch>='0'ch'9') {x=x*Ten+ch-'0'; ch=GetChar (); }returnx*F;}//************

][j]= ((n-j)/n) *dp[0][j]+dp[0][j-1]*j/n+1; Transfer: dp[i][j]=dp[i][j]* (n-i) (n-j)/n^2+dp[i-1][j]* (i* (n-j))/n^2+dp[i][j-1]* ((n-i) *j)/n^2+dp[i-1][j-1]* (i *J)/n^2+1;#include #includeusing namespacestd;Doubledp[ .][ .];intn,m,a[ .],b[ .];intMain () {CIN>>n>>m; intx, y; intL=n,r=N; for(intI=0; i) {cin>>x>>y;

indicates red. G indicates green. B indicates blue.Sample InputCopy23 12 3Sample OutputCopyRrggrMain topic:is a row of bulbs, the initial time each bulb color is red, at the same time there is a button, each point once, will be the right side of the light bulb color will change,The rule of change is r->g->b->r, cycle by loop, but when the bulb is from b->r, the color of the bulb on its left will change accordingly.Thinking Analysis: Long time did not knock code, rusty not, was so a water proble

Test instructionsgives a sequence of n numbers. There's a m instruction below.1 Instructions: The original sequence from L to R and2 directives: sorted sequences from L to R andIdeasLine tree can do .... Sweeping through the record sum array can alsoCode#include #include #include using namespace STD;#define LL Long LongConst intMAXN =100010;intNintS[MAXN];intSs[maxn];ll segtree[maxn2];ll ssegtree[maxn2];voidBuildintLintRintnode) {if(L = = r) {Segtree[node] = s[l];return; } Build (L, (l+r)/

spanning tree can get out /* Test instructions: The K point is connected to the minimum weight, and the output diagram order Dp[i][j] is currently the first I point, has been connected to the J state required to connect the minimum number of connected weights so there are two dynamic transfer Equation 1: According to the edge dp[i][j] = min (Dp[k][j] + maze[k][i]) Same state, connection point transfer 2: Based on status dp[i][j] = Min (dp[i][j1] + dp

/*Make full use of the two theorems of the Fibonacci series:① definition f[1] = A, f[2] = b, f[n] = f[n-1] + f[n-2] (n≥3).F[n] = b * fib[n-1] + A * fib[n-2] (n≥3), where Fib[i] is the first term of the Fibonacci sequence.② definition f[1] = A, f[2] = b, f[n] = f[n-1] + f[n-2

; $ } $ans=ans-C; - if(ans0) Break; - } theprintf"%i64d\n", TMP); - }Wuyi}View CodeD. Vanya and Computer GameTest instructions: Give n monsters, Vanya play Strange frequency for X times per second, the damage to the monster is 1/x Vova play the frequency of Y times per second, to blame for the damage is 1/y give each monster the maximum number of times to be hurt asked the first monster who was defeated by WHOSee the Puzzle = =Can be converted to Vanya every

contains n numbers a1, A2, ..., an (1≤ai≤105)-the elements of the array to guess. Source Technocup 2017-elimination Round 1 (unofficially Open for Everyone, rated for Div. 2) My Solution Test instructions: Interaction problem + solution N-ary equations Interaction problem + solving n-ary equations First Ask ? 1 2 ? 2