class dojo parent code

1, the Mytank class inherits the tank, then the public part of Mytank inside is the common member and the method in Mytank can call and assignment, and do not have the new member variable in Mytank and the public member name in the tank, this will occur the call disorder, such as:Tank Tank = new Mytank ();int c = TANK.A;If public a= 3 is in the tank class, and the new definition public A = 2 in the Mytank s

Learning Java in the school, the access modifier has been stuck in public is publicly available, accessible outside, protected is visible to the child, external is not accessible, private is only visible in this class. After work, the access to the Java code is much, the understanding is not the same. Public, is the interface, protected is used to give others inherited, call back more, private internal oper

A car company has a new car on the market, but the company requires that the car must be driven by internal staff, that's it. The code is as follows:Copy code Public class NewCar {Protected void drive (){// Drive the car}} However, if you say that I have bought a car, you cannot let people in this car company drive for me. Therefore, the driving function

2014-12-0313:57:481 /** 2 * @authorNlee3 * @version1:09:38 PM Dec 3,4 */5 Packagetest;6 7 Public classTextendsT18 {9 intb;Ten One PublicTintS1) A { - Super(S1); -b = 111; the } - - Public voidfun2 () - { +System.out.println ("T===fun2"); - } + A Public Static voidMain (string[] args) at { -T t =NewT (5); - t.fun1 (); - t.fun2 (); - System.out.println (t.b); - System.out.println (T.A); inT1 T1 =T; - t1.fun1 (); to t1.fun2 (); + System.out.pri

the code above. We have a new [] pointer of the derived * type, and then implicitly converted it to base *. Finally, we use his Delete [] Because Delete [] needs to call the destructor, however, the base * type pointer cannot correctly calculate the position of the this pointer required by the ten destructor of the derived array. Therefore, the code is finished at this time (if it is not enough, that's jus

Android.widget.ArrayAdapter class Mobjects as private property:privatelistmobjects; To get this property: You can define a property in a subclass, assign this property to mobjects,The code is as follows:GetObjects () Gets the private property of the parent class1 ImportAndroid.content.Context;2 ImportAndroid.view.View;3 ImportAndroid.view.ViewGroup;4 ImportAndroi

The constructor cannot be a virtual function, because the constructor must be definite when calling the constructor to create an object. Therefore, the constructor cannot be a virtual function. The Destructor can be a virtual function. 1. Parent Father. h:Copy codeThe Code is as follows: # pragma onceClass Father{Public:Father (void );Virtual ~ Father (void );Virtual int getCount ();Public:Int count;}; Fat

A simple piece of code that explains why the destructor uses a virtual function, and a function call relationship between the parent class and the subclass #include

class Base{ Public: inti,j; Base() {i=j=0; } Base(intAintb) {i=a;j=b; } };classDeried: Public Base{ Public: Deried (intAintb) { Base(A, b); } }; intMain () {deried D (3,1); cout" "Endl; return 0;}What does this piece of code output?! The correct answer is to output "0 0". My understanding is that although the base (A, A, a, b) is called, but the operation of a is

Extensions.swift =Import FoundationImport UIKitmark:-UIViewextension UIView { func Updateview () { for view in self. subviews {view. Updateview ()}}}Basicallyview.swift =Import UIKitclass Basicallyview: UIView { override func Updateview () { Super. Updateview ()}}Custom View-= override func Updateview () { Super. Updateview ()Write the code you need, as follows self. BackgroundColor = Uicolor . Clear}Swift: Generally inherit

Code Public classTest { Public Static voidMain (string[] args) {shape shape=NewCircle (); System.out.println (Shape.name); Shape.printtype (); Shape.printname (); }} classShape { PublicString name = "Shape"; PublicShape () {System.out.println ("Shape Constructor"); } Public voidPrinttype () {System.out.println ("This is shape"); } Public Static voidPrintname () {System.out.println ("Shape"); }} classCircleextendsSha

In JS we want to get the parent node there are many ways, such as 1) Parentobj.firstchild: This method can be used if the node is the first child node of a known node (parentobj). This property can be recursively used, that is, support parentObj.firstChild.firstChild.firstChild ... The form so that you can get deeper nodes. (2) Parentobj.lastchild: Obviously, this property is the last child node to get a known node (parentobj). As with FirstChild, i