cognos cubes

CSS3 Practice-Create 3D cubes　In order to achieve the 3D effect, it is very simple, just specify an element as a container and set transform-style:preserve-3d, then its descendants will have the effect of the element. But there are a lot of things to be aware of, here is the way I learn, the process of sharing to everyone. Before the knowledge point, or the first to understand the 3D coordinate system, from the web search a classic coordinate system d

Original: BI project notes creating cubes cube (1)There are two fact tables, so there are two measure groups, and the wizard creates a measure for each numeric column in the fact table for non-dimension keys. Since we don't need that much here, we only select some of the measures. Also note that the name of the measure is derived from the column in the fact table, and all names may be the same. However, in a cube, because the name of the measure must

Sum of cubes Time Limit: 2000/1000 MS (Java/others) memory limit: 32768/32768 K (Java/Others)Total submission (s): 815 accepted submission (s): 182 Problem descriptionaccording to Goldbach's Conjecture, every even number can be expressed as a sum of two odd primes. Which numbers can be expressed as the sum of two cubes? Inputfor each test case, a line will contain a positive integer n which w

To the users of the illustrator software to share a detailed analysis of the use of rectangular tools to draw cubes tutorial. Tutorial Sharing: 1 with the mouse click on the Tools palette, select the Rectangular tool, click on the graphics panel with the Rectangle tool, the Rectangle dialog box appears, enter the same width and height values, and make the rectangle wide and high equal, so you can draw a square. 2 wi

The tutorial teaches us to use Photoshop to make cool ice cubes. There are many ways to make ice cubes, but without the steps of Luo Juan, plastic packaging, Gaussian blur, wave filters, etc., after mastering certain methods, Can be free to play, make a variety of ice, below is a method of my own, I hope you can fully free play after watching. parameter is definitely not a dead number, many steps can be a

1. Run Cognos Framework Manager, find define under menu project languages 2. Add any number of languages Set as active to toggle the display language in current FM 3. At this point in query Subject,namespace or item, there are additional language fields for name,description and screen tip three properties in the Language list of property pages. Set all of them in turn. 4. In the generated package, find languages at the list of attribu

When we test the data source with Cognos, many users encounter errors that cannot be loaded by the database driver. For example, if we're using DB2, that means we can't load com.ibm.db2.jcc.DB2Driver.The solution is simple:1. Place the driver file:Db2jcc4.jarAndDb2jcc_license_cu.jarCopy toAnd2. Then remember to restart the Cognos service to resolve this issue.Solution for

C-Monkey and Banana HDU 1069 (Dynamic Planning + stacked cubes) C-Monkey and Banana Time Limit: 1000 MS Memory Limit: 32768KB 64bit IO Format: % I64d % I64uSubmit Status Practice HDU 1069 Description A group of researchers are designing an experiment to test the IQ of a monkey. they will hang a banana at the roof of a building, and at the mean time, provide the monkey with some blocks. if the monkey is clever enough, it shall be able to reach the ba

into 6 polygons to construct the cube because of the different fill color of each face.So if a cube with all the faces is green, how can it be so troublesome? We understand that position represents vertices, and a cube has 8 vertices. So is it possible to build a cube from these 8 vertices?The view graph in blend is as follows (transformed):Well, the structure of the cube ends here.P.S not easy Ah, the first time to write their own blog, not good do not spray, cost us two hours! I also just lea

Many people seem to think that compiz must have emerland, but in fact, it is not necessary. Compiz + gnome is a good choice, which is practical and gorgeous. Compiz needs a graphics card driver. Generally, this is not a problem (don't forget this is a very new cent). If you have a problem, find another tutorial on your own... Many people seem to think that compiz must have emerland, but in fact, it is not necessary. Compiz + gnome is a good choice, which is practical and gorgeous. Compiz needs

][ the][1010], fa[ One][ the][1010];7 intN, K0, M, N2, N3, sum, ans;8 intP1, Q1, R1, p2, Q2, R2;9 intFINDF (intXintYintz)Ten { One if(Fa[x][y][z]! =z) AFA[X][Y][Z] =findf (x, Y, fa[x][y][z]); - returnFa[x][y][z]; - } the intMain () - { - while(SCANF ("%d%d%d", n, k0, m)! =EOF) - { +N2 = n *K0; -n3= N2 *K0; + for(inti =1; I i) A for(intj =1; J j) at { - for(intK =1; K k) - { -scanf"%d", a[i][j][k]); -FA[I][J][K] =

The recent schoolwork is heavy, which was inscribed for two days. Last night when I went to bed, I suddenly thought of the final solution.I don't know if it should be called topology. It feels quite like it. The title is called the class topology. The method of the problem is to use a map to mark the existence of the state, and then using a similar topology method to constantly find the remaining stable after the block, I used two priority queue to maintain, respectively, take the maximum and mi

. AddEventListener (event.enter_frame,onmove); the } + Private functionOnMove (e:event):void A { the for(varI:int = 0;i){ +_facearr[i].transform.matrix3d.appendrotation ((mousex-_container.x)/50,vector3d.y_axis); -_facearr[i].transform.matrix3d.appendrotation ((_container.y-mousey)/50,vector3d.x_axis); $ } $_facearr.sorton ("Z", 18); - for(i=0;i){ - _container.setchildindex (_facearr[i],i); the } - }Wuyi Pr

Test instructionsThere is a graph in the two-dimensional plane consisting of n (10^5) labeled 0~n-1 blocks to ensure that it is stable, that is, each block falls either on the ground or below (edge or point intersection) with at least one block support now two people take turns to dismantle the graph. The number on the block that the graphic is still being removed during the disassembly process will form a The number of the system to let this number of the largest down to the minimum to ask the

(maxn,ns.se+1); Conn (Cur,pii (X,MAXN)); } if(y!=m)//R { intminn=m; intId=upper_bound (rs+1, rs+1+rn,cur)-rs; PII NS=Rs[id]; if(ns.fi==x) minn=min (minn,ns.se); ID=upper_bound (ss+1, ss+1+sn,cur)-SS; NS=Ss[id]; if(ns.fi==x) Minn=min (minn,ns.se-1); Conn (Cur,pii (X,minn)); }} sort (ss+1, ss+1+SN,CMP2); Sort (rs+1, rs+1+RN,CMP2); for(intI=1; i) { intx=ps[i].fi,y=ps[i].se; PII cur=PII (x, y); if(x!=1)//U { intmaxn=1; intId=lower_bound (r

Test instructionsGive a mLet you find a maximum number that is not greater than M and this number is the number of subtraction timesIdeas:Each time there are two cases, one is to subtract the first cubic number that is not less than the current valueThe other one is subtracting the second cubic number from the current value.But at this point the current number should change to the next cubic number-1-current cubic numberThe solution of the DFS seeking optimal/************************************

vertex you want to use in an arrayStatic ConstGlint index_list[][4] = { 0,2,3,1, 0,4,6,2, 0,1,5,4, 4,5,7,6, 1,3,7,5, 2,6,7,3,};intI, J;//the code is simple when you draw it.Glbegin (gl_quads); for(i=0; i6; ++i)//There are six faces, loops six times for(j=0; j4; ++J)//four vertices per face, loop four timesGLVERTEX3FV (Vertex_list[index_list[i][j]); Glend ();In this way, we get a more mature version of the drawing cube. Its data and program code are basically separate

work.8. Synchronize Filters synchronous filter, similar to the function of slicer slicer, but the Slicer has its functional limitations, it is not as flexible as this way.As shown below three PivotTable filter different country respectively, modify the filter name of a and C to country AC, modify the filter name of B to country BThen clicking "Synchronize Filters" in the menu will create a PivotTable for you to set the global filter, add a country filter and modify the filter name to country AC

Title Link: Http://codeforces.com/problemset/problem/525/ETest instructionsGiven n number, K exclamation mark, constant sThe number of these n is given below.Goal:Arbitrarily give some of these numbers into factorial, at most change to K.And then arbitrarily take a few numbers so that these numbers and exactly sAsk how many methods.Ideas:Three-step pressure, 0 for non-fetching, 1 for factorial, 2 for direct fetching;Search halfway, save space;The code is as follows:#include Copyright NOTICE: Th

The cube is sorted by weight from big to small, then it turns into a problem similar to the longest ascending subsequence;The definition state Dp[i][j] represents the maximum height when the J face of the first cube is the top face.Then Dp[i][j]=max (Dp[k][d]+1;1Note In order to facilitate the subsequent state of the decision, we enter the time to make the relative surface coordinates and a constant of 5.For path output, we can take a method that records the parent node.The code is as follows:#i