computer algorithm book

The Setstack computerTime limit:3.000 secondsThe topic is this:There is a "collection stack" computer designed specifically for set operations. The machine has a stack that is initially empty and supports the following operations:Push: Empty set "{}" into the stackDUP: Copy the top element of the current stack and then into the stackUNION: Stacks up to two sets, and then sets the combination of the two into a stackINTERSECT: Two sets of stacks, and th

Original title Link: http://acm.hunnu.edu.cn/online/?action=problemtype=showid=11656courseid=0Simple simulation, the final judgment to compare the two ways to get the maximum value is equal, not the maximum value of the coordinates!!!AC Code:#include Hnnu 11656 Error Algorithm "The 11th session of Hunan Province College students computer Program design contest, simulation"

1#include 2#include 3#include 4#include 5#include 6#include Set>7#include 8 using namespacestd;9 /*int next1 (int n,int k)Ten { One StringStream SS; A ss - string S=ss.str (); - if (s.length () >n) s=s.substr (0,n);//result too long, take only the first n bits the int ans; - StringStream SS2 (s); - ss2>>ans; - return ans; + }*/ - intbuf[ -]; + intNEXT2 (intNintk) A { at if(!k)return 0; - Long LongK2= (Long Long) k*K; - intL=0; - while(k2>0){ -buf[l++]=k2%Ten; k2/=Ten; - } in

: Press the number in array B to 0->a, 1->b, 2->c, ..., 24->y, 25->z, convert the rules to ciphertext For example: Encryption July, Matrix A=[11 8;3 7] (semicolon denotes another line) Step1: Convert July to an array a={9, one, one, and one}; STEP2: Divide a into {9, 20},{11, 24} two parts Step3: Because [9,] * [one 8;3 7] = [159, 212] [11, 24] * [11 8;3 7]=[19 3, []] b=[159%, 212%, 193%, [3, 4, one,] Step4: Ciphertext is DELW Your task is: give you ciphertext and matrix A, the ori

Preface When learning computer algorithms, I know that the time complexity of insertion sorting is O (n2). What does OSN mean? This article describes the tags used in algorithm analysis.Odo Definition: O (g (n) = {f (n ):Normal countC and n0, so that all n> = n0 has 0 Can be expressed as f (n) = O (n2 ). Proof: To make 0 The existence of c = 9/2, n0 = 1, so that all n> = n0 has 0 O (g (n) and the

, int radius, int color){int x = 0;int y = radius;int delta = (1-radius);int direction;while (y >= 0) {Putpixel (centerx+x, centery+y, color);Putpixel (centerx-x, centery+y, color);Putpixel (centerx-x, centery-y, color);Putpixel (centerx+x, centery-y, color);if (Delta if ((delta+y)-1) Direction = 1;}else {Direction = 2;}}else if (Delta > 0) {if ((delta-x)-1) Direction = 2;}else {Direction = 3;}}else {direction=2;}switch (direction) {Case 1:x + +;Delta + = (2*x+1);BreakCase 2:x + +;y--;Delta + =

4.3 lines4.3.1 successive approximation Linear simplification (line simplification): piecewise linear polyline or B-spline curve 4.3.2 Hough Transform A way to vote on a possible straight position based on the edge: each edge point votes for all possible lines through it (using local direction information for each boundary primitive), checking those lines that correspond to the highest accumulator or interval to find possible line matches. Using the point-line duality (duality):

can be estimated using the area around each pixel. Combining edge feature Clues 4.2.2 Edge Connection If the edge is already detected by over 0 points of a function, then connecting the boundary element with the common endpoint is very straightforward (with a sequence table, a 2D array). If the edge is not detected at 0, you will need some tricks, such as looking at the direction of the adjacent boundary element when there is ambiguity. Threshold processing with lag: A

The program is written in the scheme language and will be implemented in other languages later.#lang Racket;Fibonacci Logarithm Method;Filter(define (fib N) (Fib-iter1 0 0 1N)) (define (square x) (* x x)) (define (Fib-iter a b p q count) (Cond (= count 0) b);count = 0 o'clock, fib (1) = 0(even. Count);if it is an even number, then the value of P,q is ;p = p^2 + q^2 ;q = 2pq + q^2 ;the number of count is halved( Fib-iter a B (+ (square p) (square Q)) (+ (*2p Q)

Source: Encrypted transmission of data--tea encryption and decryption algorithm implemented on single chip microcomputerHeroes in doing data transmission, have not considered the data encryption for transmission, if the serial or wireless data to be transmitted in the encryption, it is not to increase the security of communications. Commonly used encryption and decryption algorithms such as DES, RSA, limited by the single-chip memory and operation spe

This article is to Zhao Ming teacher "computer graphics" MOOC course part of the Chapter Small Summary.The straight line is the basis of composing the graph, its algorithm is often called many times, its good or bad directly affects the graph display effect and the speed. Here are some common algorithms for drawing straight lines.1. DDA algorithm:This algorithm i

This article is to Zhao Ming teacher "computer graphics" MOOC course part of the chapter small summary.Polygons are represented in two ways: vertex representation and dot matrix representation.X-Scan line algorithm:　　　　　　The algorithm steps are summarized as follows:　　　　　　　　Attention:　　　　　　　　Improved:　　　　　　　　To avoid intersection operations, a special set of data

DC) Const{cview::D UMP (DC);} cedgetabledoc* cedgetableview::getdocument ()//Non-debug version is Inline{assert (M_pdocument->iskindof (RUNTIME_ CLASS (Cedgetabledoc)); return (cedgetabledoc*) m_pdocument;} #endif//_debug///////////////////////////////////////////////////////////////////////////////CEdgeTableView Message handlersvoid Cedgetableview::onmenufill () {CCLIENTDC DC (this); CColorDialog CCD (RGB); if (CCD. DoModal () ==idok)//Call the palette to select the foreground color {RGB=CC

Computer Common algorithm------second Zhang Yi (1) enumeration overviewEnumeration method, also known as enumerating and exhaustive methods, makes the concrete manifestation of brute force strategy, also known as brute force method.Enumeration is a simple and straightforward way to solve a problem.(2) The basic idea of enumeration is:逐一列举问题所涉及的所有清醒，并根据问题提出条件的条件检验哪些是问题的解，那些应予以排除。枚举法常用于解决“是否存在”或“有多少种可能”等问题。(3

as mkdir SHAREVM under/home3 command: sudo mount-t vboxsf SHARE/HOME/SHAREVM can be sharedThird, installation CCV1 git clone https://github.com/liuliu/ccv.git2 git checkout stable # switch to stable branch3 Downloading some dependent librariessudo apt-get install clang libjpeg-dev libpng-dev libfftw3-dev libgsl0-dev libblas-dev liblinear-dev Libblas-dev 4 cd Lib./configure Force5 CD. /binMake6 You can see a lot of executable files in the bin after make is finished.Iv. using ICF DPM for pedestri