data structures and algorithms coding interview questions

all cases:650) this.width=650; "src=" Http://files.jb51.net/file_images/article/201211/2012110120523847.png "/>void Clear (); empty queue; Initial conditions: queue exists; operation result: Leave the queue empty.void in (T item); Queued Initial conditions: queue exists; action Result: Adds a new data element with a value of item to the end of the queue, and the queues are changed.650) this.width=650; "Width=" 620 "height=" 437 "src=" http://files.jb

Binary tree node:/** Binary tree node*/public class Node {Data itempublic Long data;Left Dial Hand nodePublic Node Leftchild;Right child nodePublic Node Rightchild;/*** Construction Method* @param data*/Public Node (Long data) {This.data = data;}}Binary Tree class:/** Two-fo

(recorded as n) should be equal to the sum of 0 degree nodes, 1 degree nodes (recorded as N1) and 2 degree nodes:N=NO+N1+N2 (Formula 1)On the other hand, 1-degree nodes have a child, 2-degree nodes have two children, so the total number of child nodes in the binary tree is:Nl+2n2Only the root node in the tree is not a child of any node, so the total number of nodes in the binary tree can be expressed as:N=n1+2n2+1 (Formula 2)obtained by the Formula 1 and the 2:No=n2+1"

filtering is the Bloom filter (Bron filter). The Bron filter principle is simply: Create a large bit array, then hash the same URL with multiple hash functions to get multiple numbers, and then position the digits in the bit array at 1. Next time a URL, the same is used to hash the hash function, to get multiple numbers, we only need to determine the bit array of these numbers corresponding to is all 1, if all is 1, then the URL has appeared. This completes the URL-heavy issue. Of course, this

smaller than their own elements can stop the comparison, because the left is already an orderly state, find smaller than their own elements, there is no further comparison.　　 ? The number of rounds to be inserted is the same as the bubbling sort, but I start with 1 because we assume that the first element is already in an orderly state.? The inner loop starts from the current position, compares it to the previous element, and if it finds a smaller element than itself, stops the comparison

= mid#determine the starting subscript for the post-half string - Else: -Next = mid + 1 the -top = Mid-1 - forIinchRange (Next,len (A)): - ifStack[top]! =A[i]: + returnFalse -Top-= 1 + A returnTrueTest:if __name__= ="__main__" := List ("Hahahahahahahahaha ") print is_plalindrome_demo1 (q)Manual implementation Stack1 #simple filo stack category2 classStack:3 def __init__(self):4Self.top = None#point to top of stack5Self.end = None#Point to the bo

field to delete*/Public Node Delete (Long value) {Node current = first;Node previous = first;while (current.data! = value) {if (Current.next = = null) {return null;}previous = current;current = Current.next;}if (current = = first) {first = First.next;} else {Previous.next = Current.next;}return current;}}Test:public class Testlinklist {public static void Main (string[] args) {linklist linklist = new linklist ();Linklist.insertfirst (34);Linklist.insertfirst (23);Linklist.insertfirst (12);Linkli

string into the object.Remove removes the character from the StringBuilder object. Two parameters: The starting position and the number of characters to remove. ‘Replace: Replaces the character of the StringBuilder object. Two parameters: The old string to replace and the new string to replace.When working with StringBuilder objects, it is often necessary to convert them into strings, which can be implemented using the ToString method. Returns a string instance in the StringBuilder instance.C #

does not support the comparison size.-priority the priority counter, ensuring that the smallest element function in the queue (the most important) is always placed in _queue[0]. heapq.heappush()and the first element is heapq.heappop() inserted and deleted separately on the queue, the _queue first element of the _queue is always the smallest, ensuring that the queue _queue the first element with the highest priority.Reference: "Python Cookbook" 3rd EditionHttp://python3-cookbook.readthedocs.io/z

Implementation of the collectionfunction Set () {this.datastore = []; This.add = add; This.remove = remove; this.size = size; this.union = Union; This.intersect = intersect; This.subset = subset; this.difference = difference; This.show = Show; This.contains = contains;} function Add (data) {if (this.dataStore.indexOf (data) Practice one. Modify the collection class so that the

issue. It is great article to use relational databases to access or to use NoSQL, or to design specific file formats for storage.6) Inter-process communicationDistributed crawler, it is necessary to rely on inter-process communication. We can interact with data in the specified data format to complete interprocess communication.7) ...Nonsense said so much, the real problem comes, the problem is not to lear

) { +Temp[i] =key; -}Else { theTemp[i] = This. table[i-1];Bayi } the } the - This. Table =temp; - } the the Public intSearchindex (intkey) { the intn = key/m-1; the intStart =-1; - intLength =-1; the //Find index location the for(inti = 0; I This. Indextable.size (); i++) { the if(n = = This. Indextable.get (i). Index) {94Start = This. Indextable.get (i). Start; theLength = This. Indextable.get (i). len

Data structures and algorithms in JavaScript (2): queue This article mainly introduces the data structure and algorithm in JavaScript (2): queue is a linear table that allows only one end to be inserted and the other to be deleted, A queue is a First-In-First-Out (FIFO) data

This is my third side of the question summary.To see the previous content, please visit:http://zhweizhi.blog.51cto.com/10800691/1763237(Some data structure algorithm surface question "One" (update completed))http://zhweizhi.blog.51cto.com/10800691/1775780(Some data structure algorithm surface question "Two" (update completed))http://zhweizhi.blog.51cto.com/10800691/1787562(Some

| | j>1)//If to the end, return prompt{return ERROR;}S= (linklist) malloc (sizeof (Node));S->data =e;//Value AssignmentThe following two sentences can not be written anti-ohS->next = p->next;P->next = s;return OK;}Single-linked list delete operationDelete the A2 in the single-linked list a1,a2,a3650) this.width=650; "Width=" 518 "height=" 242 "title=" 11.jpg "style=" width:342px;height:143px; "src="/HTTP/ S3.51cto.com/wyfs02/m00/57/13/wkiol1sq75iic-u

Stacks and queuesStack (last in, first out)Stack, which allows access to only one data item: The last inserted data item.Stacks can be used to check the matching problems of parentheses and parse mathematical expressions, similar to those used in the compilation principle.The operation of the picture is actually summed up: 1. Read the left delimiter into the stack, 2. The right delimiter is read to match th

) + (N-2) +...+1 = N (N-1)/2When the value of N is very large, the algorithm compares the number of N2/2 times, ignoring minus 1.Assuming that the data is random, it is possible to swap locations each time, possibly without swapping, assuming a probability of 50%, then the number of interchanges is N2/4. However, if the worst-case scenario is that the initial data is reversed, the position is swapped for ea

node without any child nodes.The number of layers in the two-ary tree is L, and the node points are N, then N=2L-1;L=LOG2 (n+1).5. Complete binary TreeConcept: In addition to the last layer, each of the other layers of the number of nodes are full, the last layer if also full, is a full two fork tree, is also a complete binary tree. If the last layer is dissatisfied, the missing nodes are all concentrated on the right, and that is a tree full of two forks.As below, are completely binary tree!!!

algorithm is executed on different computers, and the execution time is not the same.Therefore, the operational efficiency should be related to the execution steps, which will be the time complexity of the execution steps.In the first algorithm: T (n) = n^3 * 2In the second algorithm: T (n) = n^2 * 3If the system and bias items are not considered, then the progressive function, using the progressive function representation, is the large O notation:In the first algorithm: T (n) = O (n^3)In the s

judge the case as false. if the match is not modified after the child match ends, it indicates that the match is a full match. The above two methods all use subloops. can we change them to a loop body? In fact, we can see that the primary string will only increase by 1 each time, and the child string will be matched from the beginning each time. so we can change it to a while to control the subscript pointer. Optimization algorithm (2) Function BF_Optimize_2 (sourceStr, searchStr) {var I = 0,