data structures and algorithms in java 2nd edition

right) {//Why J plus a 1, and I do not add 1 because the following loop is judged to start with--j and ++i.// The base element is selected Array[left], that is, the first element, so Zoo starts from the second element to compare int i = left;int J = Right+1;int pivot = array[left];//pivot for the selected datum element (head element) int Si Ze = right-left + 1;if (size >= 3) {pivot = medianOf3 (array, left, right);//array range is greater than 3, the datum element selects an intermediate value.

Arrays are the most widely used data storage structures. It is implanted in most programming languages.Basic knowledge of arrays in JavaCreate an arrayThey are treated as objects in Java, so you must use the new operator to create an array:Int[] Intarray;Defines a reference to an array Ingarray = new int[100]; Creates the array, and//sets int array to refer to it

when the display, but, The next time the element is inserted, the new element will replace the position of the last element.3) Find optimization--two points to findpublic int find (int value) { int start = 0; int end = Number-1; while (End>start) { int index = (end + start)/2; if (array[index]==value) { return index; } else if (Array[index] >value) { end = index-1; } else { start = in

to implement, tracking the algorithm is not straightforward.Other interval sequencesThe selection interval sequence can be called a magic. Only the formula h=h*3+1 generation interval sequence is discussed here, but the application of other interval sequences has achieved varying degrees of success. There is only one absolute condition, that is, the gradually decreasing interval must be equal to one at a time, so the last order is a normal insertion sort.The efficiency of the hill sortSo far, n

. The algorithm is then filtered up.Note: Up and down, filtering up is only compared with a parent node and stops filtering when it is smaller than the parent node.　　5. Complete Java Heap CodeFirst we need to know some of the main points of using arrays to represent heaps. If the index of the node in the array is x, then:The left child node of the node is 2*index+1,The right child node of the node is 2*index+2,The parent node of the node is (index-1)/

Java data structures and algorithms (iii) -- simple sorting Data alone is not enough. Data presentation often needs to be arranged in a certain order. The higher the requirement, the more complicated the sorting. This article only

is too small, may be back overflow, if too large, but also cause a waste of performance, and the list is dynamically allocated, there is no problem. Therefore, generally do not use barrels.6. SummaryA hash table is based on an array, similar to the storage form of a key-value, where the keyword value is mapped to an array subscript by a hash function, which is called a conflict if a keyword is Hashiha to an occupied cell. There are two ways to resolve conflicts: The Open Address method and the

Chapter 6 of Robert lafore, Java data structures and algorithms /* 6.1 assume that you have bought a cheap handheld computer, but find that its built-in chip cannot be used for multiplication and can only be used for addition. To get rid of this dilemma, you need to write your own program, write a recursive method mult

("Lookup data does not exist"); the return NULL; the } + -System.out.println ("Find successful, data is:" + This. list[p]); the return This. list[p];Bayi } the the //Sequential Table Size - Public intSizeOf () { - return This. Listlen; the } the the Public voidPrint () { theSystem.out.print ("["); - for(inti = 0; I This. list.length;

if(Head.next.data.equals (key)) { theSystem.out.print ("Query node:" + key + ","); theSystem.out.print ("Query node predecessor node is:" + Head.data + ","); the if(Head.next.next! =NULL) {98SYSTEM.OUT.PRINTLN ("Query node post node is:" +head.next.next.data); About}Else { -SYSTEM.OUT.PRINTLN ("Query node is tail node!"));101 }102 return;103 }104Head =Head.next; the }106System.out.println ("No this node!"));107

(20); Thequeue.insert (30); Thequeue.insert (40); Thequeue.remove (); Thequeue.remove (); Thequeue.remove (); Thequeue.insert (50); Thequeue.insert (60); Thequeue.insert (70); Thequeue.insert (80); while(!Thequeue.isempty ()) { Longn =Thequeue.remove (); System.out.print (n); // Max, Max, Max.System.out.print (""); } System.out.println (""); Priorityq THEPQ=NewPRIORITYQ (5); Thepq.insert (30); Thepq.insert (50); Thepq.insert (10); Thepq.insert (40); Thepq.insert

Method Public BooleanDeleteLongvalue) { intj =find (value); if(j==Nelems) { return false; } Else { for(intK=j; k) {A[k]= A[k+1]; } nelems--; return true; } } //Binary Method Search Public intFindLongSearchkey) { intlowerbound = 0; intUpperbound = nElems-1; intCurin; while(true) {Curin= (lowerbound + upperbound)/2; if(a[curin]==Searchkey) { returnCurin;//found it } Else if

the left to find an element that is larger than the base element, stop, the two elements are exchanged until two pointers meet, the end of the cycle * pointer point to the The position is where the datum element should be located in the collection * eg * {8,-2, 3, 9, 0, 1, 7, 6} * Benchmark * First bm=8 * end = Lengt h-1 = 7 * start=0 * End--, We found 6:8 small, end pointer stopped, current index is j=7 * start++, until element 9 stops, current index i=3 * Exchange the elements corresp

; 1){ - if(Peoples[index]) { incount++; - if(Count = = 3){ toPeoples[index] =false; +Count=0; -leftcount--;//minus 1 for the rest of the population. the } * } $ Panax Notoginseng //put the element under the label -index++; the + //If you have counted to the end of the array, start the number A if(Index > Len-1){ theindex = 0; + } - } $ $ for(i

List operation code is small but more error-prone, is more suitable for the interview place. Code implementation /** * Source Name: Mylinklist.java * Date: 2014-09-05 * program function: Java list operation * Copyright: [emailprotected] * A2bgeek */import Java.util.Sta Ck;public class Mylinklist {class Linknode"Data structures and

; J ) {System.out.print (A[j]+ " "); } System.out.println (""); } //Bubble Sort Public voidBubblesort () {intOut , in; for(out = nElems-1, out > 1; out--) { for(in = 0; in ) { if(A[in] > a[in + 1]) {swap (in,+ 1); } } } } //Insert Sort Public voidInsertionsort () {intin, out; //Out are dividing line for(out = 1; out ) { //Remove marked item Longtemp =A[out]; //start shifts at outin =Out ; wh

) { +Temp[i] =key; -}Else { theTemp[i] = This. table[i-1];Bayi } the } the - This. Table =temp; - } the the Public intSearchindex (intkey) { the intn = key/m-1; the intStart =-1; - intLength =-1; the //Find index location the for(inti = 0; I This. Indextable.size (); i++) { the if(n = = This. Indextable.get (i). Index) {94Start = This. Indextable.get (i). Start; theLength = This. Indextable.get (i). len

Stacks and queuesStack (last in, first out)Stack, which allows access to only one data item: The last inserted data item.Stacks can be used to check the matching problems of parentheses and parse mathematical expressions, similar to those used in the compilation principle.The operation of the picture is actually summed up: 1. Read the left delimiter into the stack, 2. The right delimiter is read to match th

) + (N-2) +...+1 = N (N-1)/2When the value of N is very large, the algorithm compares the number of N2/2 times, ignoring minus 1.Assuming that the data is random, it is possible to swap locations each time, possibly without swapping, assuming a probability of 50%, then the number of interchanges is N2/4. However, if the worst-case scenario is that the initial data is reversed, the position is swapped for ea

(6321/101)-Ten * (int (6321/102)) = 632-630 = 2;K3 = Int (6321/102)-Ten * (int (6321/103)) = 63-60 = 3;K4 = Int (6321/103)-Ten * (int (6321/104)) = 6-0 = 6;A: Example: Radixsort.javaQ: What is the efficiency of cardinality sequencing?A: All you have to do is copy the original data items from the array to the list and copy them back. If there are 10 data items, there are 20 copies. The number of copies is p