data structures and algorithms in java 6th edition

[low], pivot)) Low++; R[high]= R[low];//move elements that are larger than pivot to the high end} R[low]= pivot;//Set Pivot returnLow//return pivot element position}"Efficiency analysis"Space efficiency: Not sure, worst case is n.Time efficiency: Assuming that the number of elements to be sorted n, then a total of n-1 order, the sub-sequence of j elements to make a trip to the bubble sort needs to be j-1 sub-keyword comparison, bubble sorting time complexity of 0 (n log n).C. Algorithm ex

first 1frequency = [0 forIinchRange (0, 10, 1)] I= 1#do factorial operations, from 1! , 2! , 3! , until 100! The Operation forNinchRange (1, 100, 1): I= n *i m=First_number (i) frequency[m]= Frequency[m] + 1PrintFrequencyResults:/users/liudaoqiang/pycharmprojects/numpy/venv/bin/python/users/liudaoqiang/project/python_project/bat_day17/ 7, 7, 7, 3, ten, 4]process finished with exit code 03. Ben Ford's Law:In life, the probability of the first digit being 1 is nearly 1/3, which is 3 times ti

This is my own written Fibonacci search algorithm, and other ideas on the web slightly different, special posted out:1) There is no pre-stored Fibonacci array, the entire length of the search data can be changed;2) The change of the mid index is dynamic, according to Fibonacci's fallback method;#include #include #define INF 32767#define SIZE 92int Feibinaci (int str[],int n,int key){int F0 = 1;int F1 = 1;int temp;int mid;while (F1 {temp = F1;F1 = F1 +

Data structures and algorithms (C # implementation) series --- tree (1) Heavenkiller (original) First, let's define the tree: A tree is a finite, non-empty node set, T = {r} or T1 or T2 or... Or Tn It has the following properties: 1. the node r specified in the set is called the root node of the tree. 2. The remaining nodes can be divided into n subsets, T1, T2 ,

elements u, and another set R with R relationships. if (b) belongs to r, then elements a and B are equivalent. Equivalence classes refer to the largest set of mutually equivalent elements. In other words, the set U is divided according to the relationship, the elements within the class are equivalent and can be regarded as a kind of clustering.Offline equivalence classes: Known N and R, determine all equivalence classes.Online equivalence class: There are n elements at the beginning, and each e

from its previous element, execute a[count]=a[i],count++;Question 16: How to find the second largest number in an array.Method 1: Sort all the elements and the second largest number in the second positionMethod 2: Use two variables to record the first and second largest number, for the maximum initial value of the primary element, the second largest number is initialized to the smallest negative numbers. Each time the current element is compared with the maximum value, if it is greater than the

Linear table Lookup algorithmSequential LookupBinary lookup (linear table must be already sorted)1 /**binary Find2 * @paramobj3 * @paramvalue4 */5 Public Static voidHalfsort (int[] obj,intvalue) {6 intLen=obj.length;//gets the length of the array7 intMin=0;8 intMax=len-2;9 while(minmax) {Ten intMiddle= (Min+max)/2;//gets the subscript for the middle element of an array One if(obj[middle]==value) { ASystem.out.printl

1#include 2#include 3 voidSelectsort (int*a,intn);//pre-declaring the function to be called4 intMainvoid)5 {6 intK;7 intx[Ten]={2,4,6,8,0,1,3,5,7,9};8 for(k=0;kTen; k++)9printf"%d", X[k]);Tenprintf"\ n"); OneSelectsort (x,Ten); A for(k=0;kTen; k++) -printf"%d", X[k]); -printf"\ n"); theSystem"Pause"); - - return 0; - } + - voidSelectsort (int*a,intN//array elements are pointers, number of arrays + { A intI,j,t;//integer variable at intMin//minimum value, inde

1 classTrietree ():2 def __init__(self):3Self.root = {}4 5 defAddNode (SELF,STR):6 #each node (root node) in the tree that contains the number of words to that node, and the key that appears after the node.7Nowdict =Self.root8 forIinchRange (len (str)):9 ifStr[i] not inchNowdict:#discover new ways to combineTenNowdict[str[i]] = {'Count'70A'prefix': str[:i+1]} OneNowdict = Nowdict[str[i]]#move to the next node. Anowdict['Count'] + = 1 - - defCount

, card): Table.append (Card)ifTable.count (Card) >=2: whileTable.count (Card) >0:person.append (Table.pop ()) whileLen (hen)!=0 andLen (haa)! =0:#print "tab:", List (table)i = Hen.popleft ()#hen the cards first#print "Hen put", IRefreshtable (hen, i)#Hen Action#print "hen:", List (hen) #print "tab:", List (table)j = Haa.popleft ()#Haa after the card#print "Haa put", JRefreshtable (Haa, J)#haa Action#print "Haa:", List (HAA)#print "tab:", List (table)#print "Next Turn"

One, simple demopublic class Recursion {public static void Main (string[] args) {Test (100);}public static void Test (int n) {if (n = = 0) {Return}SYSTEM.OUT.PRINTLN (n);Test2 (n-1);}}Two, triangle numberpublic class Triangle {public static int GetNumber (int n) {int total= 0;while (n > 0) {Total = Total + N;n--;}return total;}public static int getnumberbyrecursion (int n) {if (n = = 1) {return 1;} else {return n + getnumberbyrecursion (n-1);}}}Test:public class Testtriangle {public static void

Quick sort:/** Quick Sort*/public class QuickSort {/*** Divide arrays*/public static int partition (long arr[],int left, int. Right,long point) {int leftptr = left-1;int rightptr = right;while (true) {Loop, will be smaller than the keyword left in the left sidewhile (Leftptr Loop, will be larger than the keyword left on the right sidewhile (Rightptr > Leftptr arr[--rightptr] > point);if (leftptr >= rightptr) {Break} else {Long tmp = arr[leftptr];ARR[LEFTPTR] = arr[rightptr];ARR[RIGHTPTR] = tmp;

Data structures and algorithms (C # implementation) series --- generalized tree (II) Heavenkiller (original) Public override object key {get {return this. Key ;}} Public override uint degree {get {return this. degree ;}} // Public override uint height {get {return this. Height ;}} Public override bool isempty () // property takes the place of isempty

1#include 2#include 3 4 intBinsearch (intXintV[],intn);//function Declaration5 6 intMain ()7 {8 intarr[]={1,2,3,4,5,6,7,8,9,Ten};9 intas a result, num;Tennum=7; OneResults =binsearch (Num,arr,Ten); A - if(Results 0) -printf"I didn't find!\n ."); the Else -printf"find%d\n in arr[%d]", as a result, num); -System"Pause"); - + return 0; - } + A intBinsearch (intXintV[],intN//function Definition at { - intLow,high,mid;//min, max, Middle - -low=0; -high=n-1; - in

Data structures and algorithms (C # implementation) series --- AVLTree (II) // --------------- Override -------------------- Public override void AttachKey (object _ obj) { If (! IsEmpty ()) Throw new Exception ("My: this node must be a empty tree node! "); This. key = _ obj;

) { returnNULL; } TreeNode* node =NewTreeNode;//noice that [new] should is written out.Node->elem = * (aftorder+length-1); Std::coutStd::endl; intRootindex = 0; for(; rootindex //a variation of the loop { if(Inorder[rootindex] = = * (aftorder+length-1)) Break; } node->left =binarytreefromorderings (inorder, Aftorder, Rootindex); Node->right = binarytreefromorderings (inorder + rootindex + 1, Aftorder + rootindex, Length-(Rootindex + 1)); returnnode;}intMainintarg

Data structures and algorithms (C # implementation) series --- tree (III) Heavenkiller (original) // Overwrite Object. Equals () --- reference type realization Public override bool Equals (object _ obj) { If (_ obj = null) Return false; // this cannot be null If (! (This. GetType () = _ obj. GetType ())) Return false; // The type is not equal. Tree tmpObj = (Tre

Public classSelectionsort { Public Static voidsort (integer[] array) {if(Array = =NULL|| Array.Length = = 0) { return; } Integer mininum=NULL; Integer Miniindex=NULL; for(inti = 0; i ) {Miniindex=i; Mininum=Array[i]; for(intj = i + 1; J ) { if(Array[j] mininum) {Miniindex=J; Mininum=Array[j]; } } if(Miniindex! =i) {swap (array, I, miniindex); } } } Private Static voidswap (integer[] array, integer i, Integer j) {Integer temp=Array[i]

1 Sequence decompression: through * to pass the match*a, B = somelist, First, *mid, last = Somelist, a, *b = Somelist2 using bidirectional queues: From collections import dequeQ = deque (maxlen=5) can be fixed lengthQ = deque () can also be any lengthcan be inserted and removed from both ends, append, Appendleft, pop, popleft3 finding the largest or smallest n elements: using heapq (heap queue)HEAPQ. nlargest (N, Alist) heapq. nsmallest (n, alist) is suitable when n is relatively smallYou can al

The maximum value in the output array A and its subscript#include Data structures and algorithms-maximum values in a string output array