data structures and algorithms in java 6th edition
data structures and algorithms in java 6th edition
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Title: Define the Fibonacci sequence as follows:/0 N=0F (n) = 1 n=1\ f (n-1) +f (n-2) n=2Enter N to find the nth item of the sequence in the quickest way.#include Data structures and algorithms-string Fibonacci to find the nth item
Package Com.js.ai.modules.pointwall.testxfz;class ordarray{private long[] a;private int nelems;public OrdArray (int max ) {a=new long[max];nelems=0;} public int size () {return nelems;} Insert method public void Insert (Long value) {int j;for (j=0;j Data structures and algorithms: the dichotomy Demo
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Second, collections. Ordereddict: Dictionary with OrderOrdereddict internally maintains a doubly linked list to record the order in which key values are inserted, update the key value does not affect the original order, insert key value is inserted at the end, so its memory consumption is twice times the normal dictionary ,From collections Import ORDEREDDICTD = Ordereddict () d[' a '] = 1d[' c '] = 3d[' b '] = 2print (d, D.items ())
Ordereddict (' A ', 1), (' C ', 3)
-set receives a tree height effect and is less efficient. Therefore, there are two kinds of improved heuristic algorithms.The first is to merge by rank, and for each node to record his height, change the father of the smaller node to the larger one. If both sides are equal, select one as the father, and the rank of the root node plus one.The second is path compression, and each time the find-set is called, the father of the node found on the path is changed directly to the root node.1make-SET (x
1. The principle of hill sorting2. Code implementationdefShell_sort (alist): N=Len (alist)#Initial StepGap = N/2 whileGap >0:#Insert Sort by step forIinchRange (Gap, N): J=I#Insert Sort whileJ>=gap andALIST[J-GAP] >Alist[j]: alist[j-GAP], alist[j] = alist[j], alist[j-Gap] J-=Gap#get a new step sizeGap = GAP/2alist= [54,26,93,17,77,31,44,55,20]shell_sort (alist)Print(alist)Attention:(1) Hill sort uses the idea of splitting up and merging, splitting apart3. Complexity of TimeOp
node is now
Point to the head of the now node's next pointer;
Set the now node to the head of the new rollover completion node header now;
Point to head now, and so on, the next pointer to the previous node of the now node.
3. Two points search common scenes
Finding a number in an ordered sequence;
For example, given an array of arr, determine if the integer m is in arr (Train of thought: Determine the size of the mid-to-m re
efficiency: In a merge sort, the maximum value of this secondary storage space is not more than N, so the spatial complexity of the merge algorithm is θ (n) in order to combine the sub-sequences to use additional storage space.Time efficiency: The merging algorithm is a typical divide-and-conquer algorithm with a time complexity of 0 (n log n). 3. Algorithm examplesMergesort.javaPackage Com.test.sort.merge;public class MergeSort {/** * @param args */public static void main (string[] args) {//TO
" definition of algorithmic time complexity"At the time of the algorithm analysis, the total number of executions of the statement T (N) is a function of the problem size n, which then analyzes the change of T (n) with N and determines the order of magnitude of T (N). The time complexity of the algorithm, which is the time measurement of the algorithm, is recorded as: T (n) = O (f (n)). It indicates that with the increase of the problem size n, the growth rate of the algorithm execution time is
Bucket sortBarrel sequencing has been used since the 1956, and the basic idea of the algorithm is proposed by E.J.ISSAC and R.c.singleton.This algorithm is like having 11 barrels, numbered from 0~10. Each occurrence of a number, in the corresponding number of buckets put aA little flag, and then just count the few small flags in each bucket OK. For example, there are 1 small flags in bucket 2nd, indicating2 appeared once, and in the 3rd barrels there were 1 small flags, indicating that 3 appeare
and J to point to the leftmost and rightmost of the sequence, respectively. At first, the variable I points to the leftmost part of the sequence, which is the number 6, and J points to the far right of the sequence, pointing to the number 8, as shown inFirst J moves from right to left, so long as it finds a number smaller than 6, it stops, and J is in the 5 position. I then start from left to right, as long as I find a number greater than 6 to stop, so it to the position of 7This is where the t
Using system;using system.collections.generic;using system.linq;using system.text;using System.Threading.Tasks; Namespace selectsort{class Program {static void Main (string[] args) {int[] Arry = {1, 4, 5,6,2,9,0,8,3,10}; Selectesort (Arry, Arry. Length); for (int i = 0; i Because of the two for loops, the time complexity is O (n^2), which is a simple but very slow sort.Selection and sequencing of algorithms and
var arraynumber: [Int] = [2,4, 6, 7, 3, 8, 1]Bubble sortfunc Maopao (var array: [int]), [int] { for var i = 0; i count; i++ { for var j = I;j count; j + + {if array[j] > array[j +1] {var temp = Array[j]ARRAY[J] = array[j+1]array[j+1] = Temp}}}return Array} Let array2 =maopao([2,4, 6, 7, 3, 8, 9 , 5])Cond... Copyright NOTICE: This article for Bo Master original article, without Bo Master permission not reproduced. Swift sorting algorithms and
Huashan Big BroSort by: Topological sorting algorithmDictionary ordering algorithmProgramming Zhu Ji Nanxiong: Ordering by bitmapTree: Red and Black tree summaryB + Tree and b* Tree SummaryB-Tree Summary SummaryBalanced binary tree (AVL tree) Summarytrie--Dictionary TreeGraph traversal: Depth-first traversal and breadth-first traversalMinimum spanning tree: minimum spanning tree-prim algorithm and Kruskal algorithmShortest path: Shortest path-dijkstra algorithm and Floyd algorithmCommon classica
, vi belongs to V-S. Then, the shortest path is compared with the source point A to the path length of the node vi, the minimum length is the shortest path from source point A to Node VI. Finally, the end of the shortest path (i.e. VI) is added to the S(3) Repeat step (2) until the shortest path of all endpoints is found, that is, the number of nodes in S is equal to the number of nodes in V.The time complexity of the Dijkstra algorithm is O (n^2), the spatial complexity depends on the storage m
Data structures and algorithms (C # implementation) series-demonstration (II)
Heavenkiller (original)
Public static void ShowGeneralTree_travel ()
{
IEnumerator tmpIEnum;
Tree. TraversalType travelType = 0;
// --------------------- Prompt ----------------------------
Console. WriteLine ("please choose a No. of a item you want to travel :");
Console. WriteLine ("
Data structures and algorithms (C # implementation) series --- tree (2)
Heavenkiller (original)
Public class InOrder: IPrePostVisitor
{
Private IVisitor visitor;
Public InOrder (IVisitor _ vis) {visitor = _ vis ;}
# Region IPrePostVisitor Member
Public void PreVisit (object _ obj)
{
// TODO: Add InOrder. PreVisit implementation
}
Public void Visit (object _ ob
Data structures and algorithms (C # implementation) series --- generalized tree (II)
Heavenkiller (original)
Public override object Key {get {return this. key ;}}
Public override uint Degree {get {return this. degree ;}}
// Public override uint Height {get {return this. height ;}}
Public override bool IsEmpty () // property takes the place of IsEmpty ()
{Return
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