db2 rank

s.subjectname= ' math ' then S.subjectscore else 0 end) as mathematical results,SUM (case when s.subjectname= ' English ' then S.subjectscore else 0 end) as English scoreFrom student SGROUP BY S.stunameORDER BY S.stuname Results obtained after implementation: The above practice is also very easy to understand, here is not much to say, but the above is also limited. Because there are some fixed values here. such as "Chinese, maths," in the case. "But when you meet a small business need, you can

A matrix of rank 1 has been specifically discussed, with n-1 linear independent vectors from ax=0 Ax = 0, Lenovo to: Aα=0⋅αa\alpha = 0\cdot \alpha, knowing that 0 must be a eigenvalues of a, and n-1-valued eigenvalues. Such a nature, if examined alone, is too simple. In another article, we summarize the idea that the matrix of rank 1 is exponentiation. http://blog.csdn.net/u011240016/article/details/5280566

(J,n) Sa[r[j]]=J;}intMain () {scanf ("%s", ch+1); N=strlen (ch+1); Rep (i,n) r[i]=Ch[i]; Getsa (); printf ("RANK:"); Rep (i,n) printf ("%d", R[i]); printf ("\nsa:"); Rep (i,n) printf ("%d", Sa[i]); return 0;}However, given the specificity of the rank array (a certain So we can solve the nBut this is quite easy to write wrong and need to master the principle of cardinal sort firstThe cardinality sort is

Rank () sorts data in a table hierarchically.For example, student_resultName number Kemu fenshuLi 0113101 High 90Zhang 0113098 high 80Wang 0113077 High 70Li 0113101 physical 80Zhang 0113098 physical 90Wang 0113077 physical 70 If I want to retrieve the first two names in the table with a high number and the first two names in the physical tableYou can use the rank () method to achieve the goal. -- First sort

I recently encountered one thing at work. I have a user order table, which has an order_id and is a unique constraint. At the same time, there is an order flow table, which is associated with the order table with ser_id. One ser_id corresponds to at least one order flow record. Now I want to summarize the two tables into a table with ser_id as the unique constraint. One of the fields comes from the process table, which is the largest work_id in several workflow records corresponding to ser_id.

My colleague asked a very simple question: how can I retrieve the minimum value of another column in each partition? create table t1 (int c1, int c2); If the partition is based on C2, 0-10, 10-20, 20-30, 30-40, 40-50 insert into t1 values(101, 1);insert into t1 values(102, 2);insert into t1 values(111, 11);insert into t1 values(112, 12);insert into t1 values(121, 21);insert into t1 values(122, 22);insert into t1 values(131, 31);insert into t1 values(132, 32);insert into t1 values(133,

To evaluate the performance of our first year CS majored students, we consider their grades of three courses only:c-C P Rogramming Language, M-mathematics (calculus or Linear Algebra), and E-english. At the mean time, we encourage students by emphasizing on their best ranks – that's, among the four ranks with respect T o The three courses and the average grade, we print the best rank for each student.For example, the grades of C, M, E and A-average of

Rank () Over is the function of finding a rank after the specified condition is detected, but there is a feature. If it is the student rankings, then practical this function, the results of the same two are tied, for example 1 2 2 4. 2Dense_rank () The Role and rank () very much like, the only difference is that brought life student's results tied up, the next

RankTime limit:1000/1000 MS (java/others) Memory limit:32768/32768 K (java/others)Total submission (s): 4160 Accepted Submission (s): 1616Problem Descriptionjackson wants to know he rank in the class. The professor has posted a list of student numbers and marks. Compute Jackson ' s rank in class; That's, if he has the top mark (or was tied for the top mark) his rank