determine distance between two points

Calculates the spherical distance between 2 points on the Earth's surface/** * @param $lat 1 * @param $lng 1 * @param $lat 2 * @param $lng 2 * @return int*/functionGetdistance ($lat 1,$LNG 1,$lat 2,$LNG 2){ //turn angle into Fox degree $radLat 1=Deg2rad($lat 1);//the Deg2rad () function converts an angle to radians $radLat 2=Deg2rad($lat 2); $radLng 1=Deg2rad($LNG 1); $radLng 2=Deg2rad($LNG 2); $a=

Baidu map, how to search for a coordinate point in the database near the number of the distance of n coordinate points Environment: Php+mysql The existing database holds some latitude and longitude (100W or more) coordinate points, What if I get all the information within 1 miles of the vicinity based on a coordinate point? The Longitude field in the databa

: This article describes how to calculate the distance between two geographical coordinates in php. if you are interested in the PHP Tutorial, refer to it. Function: calculates the spherical distance between two points based on the circumference rate and the latitude and longitude of the Earth's radius coefficient and the two-point coordinate. Obtain the two-poin

Tags: style blog http ar sp on log efDECLARE @BJ GEOGRAPHYDECLARE @XT GEOGRAPHY/*GET Latitude/longitude from Here:http://www.travelmath.com/cities/beijing,+chinaThe distance unit in SRID 4326 is the meter*/SELECT @BJ = Geography::P oint (' 39.92889 ', ' 116.38833 ', 4326)SELECT @XT = Geography::P oint (' 37.0630556 ', ' 114.4941667 ', 4326)SELECT@BJ as Beijing,@XT as Xingtai,' The distance is ' +CAST (@BJ.

Principle:The Earth's equator orbits around the earth a total of 40075.04 kilometers a week, while the @ lap is divided into 360 °, and each 1° (degree) has 60, the length of each second on the equator is calculated as follows: 40075.04km/360°=111.31955km 111.31955km/60=1.8553258km=1855.3m And each point has 60 seconds, every second represents 1855.3m/60=30.92m Any two-point distance calculation formula is D=111.12cos{1/[sinφasinφb 10 Cosφacosφbcos (λ

Now the application of geo-information is very hot, whether it is from the location of Google map information, or through the iphone or Android, such as mobile terminals with GPS modules to obtain geographical information, are decimal latitude and longitude information. We may need to compute the distance between two points on the Earth's surface when we do the actual application, and here is the example la

Floyd algorithmFloyd algorithm Dijkstra is used to solve the single-source shortest path problem, while Floyd is used to solve the shortest path problem between points. The design strategy of the Floyd algorithm is dynamic planning, while Dijkstra adopts greedy strategy. Of course, greedy algorithms are a special case of dynamic planning.Algorithm IDEA There are only two possible conditions for the shortest path between

children the exact time she'll spend on the roads. Can you help her?InputThe first line contains three integers n, q, S. There was n huts in XX Village, q messages to process, and wind was currently in Hut S. N The following n-1 lines each contains three integers a, B and W. That means there was a road directly connecting hut A and B, time required is W. 1The following q lines is one of the following and the types:Message a:0 uA kid in Hut U calls wind. She should go to hut u from hers current

Distance calculation between two points on Baidu map for php --> $velocityCount--> --> [PHP] code // Business_Latitude_new, Business_Longitude_new is the current coordinate // $ latitude, $ longdistance is the target coordinate distance = 6371.012 * acos (cos (acos (-1)/180 * Business_Latitude_new) * cos (acos (-1)/180 * $ latitude) * cos (acos (-1)/180

This is a good example, directly affixed to the code, first of all to know the latitude value, longitude value /** * @desc calculates the distance * @param float $lat latitude value based on the longitude of two points * @param float $lng Longitude value * /function getdistance ($la T1, $LNG 1, $lat 2, $lng 2) { $earthRadius = 6367000;//approximate radius of Earth in meters/ * Convert thes e de

Label:--Create a stored procedure Point_diatance Create or Replace procedure Point_distance Authid Current_User is --Defining variables Net1 float; Net2 float; Net3 int; NET4 int; NET5 int; Lata float; Lona float; LATB float; LONB float; Net6 float; Net7 float; Net8 float; NET9 float; Net10 float; net11 float; net12 float; net13 float; Begin For Net3 in 1..49 Loop--Start loop For Net4 in 1..49 Loop --Read the latitude from the Aa_point table Select Latitude into Lata from aa_point where point

This article mainly introduces how PHP calculates the distance based on the longitude and latitude between two points. The code is very simple, but it is very practical. if you need it, you can refer to this as a good example and paste the code directly, first, you must know the latitude and longitude values. /*** @ Desc calculate the distance * @ param floa

; }else{count[x%width]++;System.out.println ("width" +x%width);IMAGEARRAYTHR[X]=IMAGEARRAYONE[X];imagearraythr[x]=99999999;}} System.out.println (Arrays.tostring (count));for (int x = 0; x if (count[x]>5){System.out.println ("Guess axis coordinates are" +x);Result=x;System.out.println ("Guess axis coordinates are" +count[x]+ "" +count[x+1]);Break}}Imagenew.setrgb (0,0,width,height,imagearraythr,0,width);File OutFile = new file (file3);Imageio.write (imagenew, "JPG", outFile);//write a pictureret

Define (' PI ', 3.1415926535898);d efine (' Earth_radius ', 6378.137);//calculation range, can do search user function GetRange ($lat, $lon, $raidus) {//calculate latitude $degree = (24901 * 1609)/360.0; $dpmLat = 1/$degree; $radiusLat = $dpmLat * $raidus; $minLat = $lat-$radiusLat; Get the minimum latitude $maxLat = $lat + $radiusLat; Get maximum latitude//calculate Longitude $mpdLng = $degree * cos ($lat * (pi/180)); $dpmLng = 1/$mpdLng; $radiusLng = $dpmLng * $raidus; $min

PHP calculates the distance between two points on the map Class GeoHelper { /** * @ Param int $ lat1 * @ Param int $ lon1 * @ Param int $ lat2 * @ Param int $ lon2 * @ Param string $ unit * @ Return */ Public static function distance ($ lat1, $ lon1, $ lat2, $ lon2, $ unit = "K ")

Code Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/--> PublicStaticDoubleDistanceoftwopoints (DoubleLng1,DoubleLAT1,DoubleLng2,Double LAT2, gausssphere GS) {DoubleRadlat1= Rad (LAT1 );DoubleRadlat2= Rad (LAT2 );DoubleA=Radlat1- radlat2; double B = rad (lng1) - rad (lng2 ); double S = 2 * math. asin (math. SQRT (math. pow (math. sin (A / 2 ), 2 ) + Math. Cos (radlat1) *Math. Cos (radlat2)*Math. Pow (math.

From Google Map on the basis of latitude and longitude for the Earth's surface to achieve the distance between two points, slightly adapted for the domestic space distance calculation, the implementation has been sufficient to meters as a unit. net2.0,c# implementation. public static double distanceoftwopoints (double lng1,double lat1, double lng2, double lat2, g

public class closestpair{public static void Main (string[] args) {Float[][] A = new float[][]{{3, 3}, {5}, {4, 6}, {2, 8}, {9, 9},{2, 1}, {7, 2}, {6, 5}, {9, 4} and {5, 9}};Float d = (float) 1e9;for (int i=0; ifor (int j=i+1; jFLOAT dx = a[i][0]-a[j][0];float dy = a[i][1]-a[j][1];d = min (d, math.sqrt (Dx*dx+dy*dy));}}System.out.println (d);}private static float min (float d, double sqrt) {return d = d>sqrt?d= (float) sqrt:d;}}Distance between the las

var childs = var latlng = new Google.maps.LatLng (Value.google_lnglat.lat, VALUE.GOOGLE_LNGLAT.LNG); Value.google_lnglat.lat, value.google_lnglat.lng current position latitude and longitudefunction Getflatterndistance (LAT1, lng1) {var Julichangdu = new Array ();Childs $.each (Childs, function (idx, dest) {//contents of all remaining pointsvar lat2 = dest[' Google_lnglat '][1];var lng2 = dest[' Google_lnglat '][0]var f = Getrad ((number (LAT1) + number (LAT2))/2);var g = Getrad ((number (LAT1)-