different graphs

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Three ways to load GIF dynamic graphs

imagenamed:@"8"], [UIImage imagenamed:@"9"], [UIImage imagenamed:@"Ten"], [UIImage imagenamed:@" One"], [UIImage imagenamed:@" A"], [UIImage imagenamed:@" -"], [UIImage imagenamed:@" -"], [UIImage imagenamed:@" the"], [UIImage imagenamed:@" -"], [UIImage imagenamed:@" -"], [UIImage imagenamed:@" -"], [UIImage imagenamed:@" +"], [UIImage imagenamed:@" -"], [UIImage imagenamed:@" +"], [UIImage imagenamed:@" A"],nil]; Gifimageview.animationimages= Gifarray;//animated Image ArrayGifimageview.animat

DFS traversal and BFS traversal of graphs

For such as the breadth and depth of traversal;DFS traversal, (output traversed vertices in turn):Use the adjacency matrix to store the graph (survival up with a two-dimensional array)!The BFS traversal of the graph:DFS traversal and BFS traversal of graphs

hdu2444 Judging two graphs + maximum matching

#include #includestring.h>#includeusing namespacestd;#defineMAXN 210intMAP[MAXN][MAXN],COLOR[MAXN];intVis[maxn],match[maxn],n;intBFsintUintN) { inti; Queueint>Q; Q.push (U); Color[u]=1; while(!Q.empty ()) { intv=Q.front (); Q.pop (); for(i=1; i) { if(color[i]==-1Map[v][i]) {Q.push (i); Color[i]=!Color[v]; } if(color[i]==color[v]Map[v][i])return 0; } } return 1;}intDfsintu) { inti,j; for(i=1; i) { if(map[u][i]!V

Maximum matching of POJ 1466 Girls and Boys binary graphs

) {Vis[e[a][i]]=1; if(match[e[a][i]]==-1||DFS (Match[e[a][i])) {Match[e[a][i]]=A; return 1; } } } return 0;}intMain () { while(SCANF ("%d", n)! =EOF) {memset (match,-1,sizeof(match)); for(intI=0; i) e[i].clear (); M=N; for(intI=0; i) { intx, y; scanf ("%d: (%d)",x,y); for(intj=0; j) { intC=read (); E[x].push_back (c); } } intans=0; for(intI=0; i) {memset (Vis,0,sizeof(VIS)); if(Dfs (i) = =1) ans++; } printf ("%

Double connected components of undirected graphs

Great White Book template, map with forward star storageintPRE[MAXN], ISCUT[MAXN], BCCNO[MAXN], Dfs_clock, Bcc_cnt;vectorint>BCC[MAXN];intEDGE,HEAD[MAXN];structedgenode{intTo,next;} G[MAXM];voidAdd_edge (intXinty) {g[edge].to=y; G[edge].next=Head[x]; HEAD[X]=edge++;}structedge{intu, v;}; StackS;intDfsintUintFA) { intlowu=pre[u]=++Dfs_clock; intChild=0; for(inti=head[u];i!=-1; i=G[i].next) { intv=g[i].to; Edge e=(Edge) {u, v}; if(!Pre[v]) {S.push (e); Child++; intLOWV =Dfs (

POJ 1511 forward reverse structure two graphs

[start]=0; theQue.push (Qnode (Start,0)); + Qnode tmp; A while(!que.empty ()) the { +tmp=que.top (); - Que.pop (); $ intu=tmp.v; $ if(Vis[u])Continue; -vis[u]=true; - for(intI=0; I) the { - intv=e[tmp.v][i].v;Wuyi intcost=E[u][i].cost; the if(!vis[v]dist[v]>dist[u]+Cost ) - { Wudist[v]=dist[u]+Cost ; - Que.push (Qnode (v,dist[v)); About } $ } - } - } - voidAddedge (intUintVintW) A {

Representation of graphs-adjacency matrix representations

vertex number:";Cin>> Graph.ivertexnum;cout"Input vertex value:"; for(inti =0; i Cin>> graph.avertex[i];}intLocat_vertex (Graph graph,intVertex) { for(inti =0; i if(Graph.avertex[i] = = vertex)returnI }return-1;}voidAdd_arcs (Graph graph) {cout"Add Arcs"cout"Input arcs numbers:";Cin>> Graph.iarcnum;intIfirst =0;intIsecond =0;intIRow =0;intIcol =0; graph_weight_t iweight =0; for(inti =0; i cout"Input, ARC and Weight (ex. 1 2)"Cin>> ifirst >> isecond >> iweight; IRow = Locat_vertex (graph,

_datastructure_c_impl: adjacency table storage for graphs

#include Copyright NOTICE: This article for Bo Master original article, without BO Master permission cannot reprint |copyright©2011-2015,supernatural, all rights Reserved. _datastructure_c_impl: adjacency table storage for graphs

Depth-first search and breadth-first search for graphs

Traversegraph (Adjlist *g)//Deep Search{int VI;for (vi = 0; vi VISITED[VI] = False; Initializing an array of flagsfor (vi = 0; vi if (!visited[vi])Depthfirstsearch (G,VI);}void Breadthfirstsearch (adjlist *g, int v0)//Breadth First Search{Linkqueue Q;int V, W;printf ("%c", g->vertex[v0].data);Visited[v0] = True;Initqueue (Q);Enterqueue (Q,V0);while (! Empty (Q)){Deletequeue (q, v);W = Firstadjvertex (g, v);while (w! =-1){if (!visited[w]){printf ("%c", g->vertex[w].data);VISITED[W] = True;Enterq

How to divide a very long large picture into multiple small graphs on average?

First use the 360 browser to save the page as a picture, as shown in:Then open the picture with PS, click Start-Open, find the location of the file, and open it.Next, the slicing tool is found, and the default slicing tool and crop tool overlap. The slice tool appears when you move the mouse over the Crop tool by right-clicking the slice tool.After the first good slicing tool, move the cursor to the picture position, point right, choose to divide the slice, come out the following dialog box: Her

On the forward star traversal of graphs

edges of the diagram. Last[i] is used to record an edge that starts with I and is the last input, Front[j] represents the previous edge of The Edge J (the previous edge here is not just the input order in front of J, but also the J-holdHave the same starting point), To[j] represents the node number pointed to by the J Edge. That is: Make Addr=last[i], and then continue to use ADDR=FRONT[ADDR] to get all the node I as the starting point in the list of all "edge set number", whereTO[ADDR] Indicat

Depth-first search and breadth-first search of graphs

graph without Direction Depth-first search and breadth-first search#include "stdafx.h" #include Copyright NOTICE: This article for Bo Master original article, without Bo Master permission not reproduced. Depth-first search and breadth-first search of graphs

POJ 1466 Girls and Boys (maximum independent set of binary graphs)

program should write to standard output a line containing the result.Sample Input70: (3) 4 5 61: (2) 4 62: (0) 3: (0) 4: (2) 0 15: (1) 06: (2) 0 130: (2) 1 21: (1) 02: (1) 0Sample Output52Maximum Independent set = Total number of points-maximum matchesBecause the number is enlarged by twice times, the maximum number of matches should be divided by 2.#include #includestring.h>#include#include#include#defineN 510#defineINF 0x3f3f3f3fusing namespacestd;intG[n][n], vis[n], used[n];intN;BOOLFind (in

Javscript Carousel supports both smoothing and fading effects (only two graphs can be used)

, Customitem); RotatePrivate.timeRun.call (Othis); } }); } }Second, to see the effect of fade-out carouselThis in the original effect, the only comparison has a bright spot is "how to not let the picture white"?Fig. 1 Fig. 2 Fig. 3 Fig. 4Figure 1 CloningFig. 2 Fig. 3 Fig. 4 Fig. 1I used clone to have a current and set position:absolute, so that when the current such opacity becomes 0 o'clock, the bottom figure 2 is shown, so it is less blunt.Ne

Number of fully generated graphs of N-order

test data outputs an integer representing the number of scenarios that satisfy the test instructions. The output may be very large, please output the result of the construction plan number to 10003 after the remainder. Sample Input234Sample Output3 -indicates the number of spanning trees for n-Order complete graphsThe number of spanning trees of the N-order complete graph is n^n-2 specifically why ... And now it's not clear what to do after studying.#include #includeintMain () {intn,m,i,j; whi

Hangzhou Electric 1068--girls and Boys (the largest independent set of two graphs)

{ +scanf"%d: (%d)", q, m); - for(inti =1; I ) the { *scanf"%d", GG); $MAP[Q][GG] =1;Panax Notoginseng } - } the intsum =0; + for(inti =0; I ) A { thememset (Vis,0,sizeof(Vis)); + if(Dfs (i)) -sum++; $ } $printf"%d\n", n-sum/2); - } - return 0; the}1#include 2#include 3#include 4 using namespacestd;5 intmap[1010][1010], dis[1010], vis[1010];6 intN;7 BOOLDfs (inta)8 {9 for(inti =0; I )Te

One way to browse large graphs

transitionwascancelled]]; }]; }- (ID) ToVC {if(Operation = =Uinavigationcontrolleroperationpush) {self.opration=Pushanimationoprationpush; }Else if(Operation = =Uinavigationcontrolleroperationpop) {self.opration=Pushanimationoprationpop; } returnSelf ;}- (void) Start {Self.nav.Delegate=Self ;}/** Add a tap gesture to the target controller to return to the previous controller*/- (void) Tapgesturetopopwithcontroller: (Uiviewcontroller *) TARGETVC {Self.targetviewcontroller=TARGETVC; UITapGe

Sightseeing Tour (Euler circuit for POJ 1637 hybrid graphs)

tour.Sample Input45 82 1 01 3 04 1 11 5 05 4 13 4 04 2 12 2 04 41 2 12 3 03 4 01 4 13 31 2 02 3 03 2 03 41 2 02 3 11 2 03 2 0Sample OutputPossibleimpossibleimpossiblepossibleSourceNorthwestern Europe 2003 Test instructions: To find out if the mixed graph has a Euler circuit.Idea: The first is the base map Unicom (regardless of the degree of 0 points), and then need to rely on network flow to judge.First of all, the non-directed side of the original map to a random direction (initial ori

POJ 1698 (multi-match for binary graphs)

! the { About for(inti1=0; i17; i1++) scanf ("%d", week+i1); thescanf"%d%d", d, W); theDay =Max (Day, W); theEdge[s][i] = D;//The source points to each festival point x to connect a weight to the number of days required to take the movie. +Sum + =D; - the for(intj=0; j//within a W week to complete.Bayi { the for(intk=0; k7; k++) the if(Week[k]) -edge[i][n+j*7+k+1] =1;//Part I movies can be taken at week K within

Dual connected components of undirected graphs (tarjan template)

#include Copyright NOTICE: This article for Bo Master original article, without Bo Master permission not reproduced. Dual connected components of undirected graphs (tarjan template)

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