drawing bag

, i = (dir?1: (S-1)); Dir? (I 1: -1)) - if(MaxSize | |!zero (xmult (Temp[i-1], Temp[i], temp[(i +1)%S] ))) theconvex[n++] =Temp[i]; the Delete[]temp; the returnN;94 } the the intMain () the {98 intN; About DoubleD; - while(Cin >> N >>d)101 {102Memset (P,0,sizeof(P));103memset (Convex,0,sizeof(convex));104 DoubleDist =0.0; the for(inti =0; I )106 {107CIN >> p[i].x >>p[i].y;108 }109 //cout the intsize = Graham (n,

The "test instructions" gives the n points a convex packet."Analysis" to find convex template, here pay attention to the situation of n==2, did not notice WA a back!"AC Code"#include HDU 1392 Surround the Trees (convex bag)

the screen. Let's give an example: "Tcp.dstport xor Tcp.dstport 1025" only if the destination TCP port is 80 orSuch a packet will be displayed only if it originates from port 1025 (but cannot satisfy these two points at the same time).Example:SNMP | | dns | | ICMP Displays the SNMP or DNS or ICMP packets. ip.addr = = 10.1.1.1 Displays packets with a source or destination IP address of 10.1.1.1.ip.src! = 10.1.2.3 or Ip.dst! = 10.4.5.6 shows packets that are not 10.1.2.3 or are not intended for 1

lookup is the path $GOPATH/src defined in the brief. When you use an outsourced function in your code, you need to use the "last package name. Function Name" method, so if you import the following situation, the problem will occur when you use it:Import ( "json" "my/json")Then we need to give a different alias to the package name, such as:Import ( "json" "my/json") This allows you to use Myjson.function () to invoke the function in My/json, and the alias is. , you can use the functi

convert the IP address to host name display, like this: eth0 ntc9.1165> router.domain.net.telnet, using-N has become: eth0 192.168.0.9.1165 > 192.168.0.1.telnet.-nn do not convert port names:The above message was used-nn and became: eth0 ntc9.1165 > router.domain.net.23.-N does not print out the default domain name:Or is this message-N after: eth0 ntc9.1165 > router.telnet.-O do not optimize for matching code.-T does not print the Unix timestamp, that is, the time is not displayed.-tt prints th

[x]].b-a[sta[x-1]].B)/(A[sta[x-1]].K-a[sta[x]].k); - } + - intMain () + { A intn, top; atCIN >>N; - for(inti =1; I i) - { -CIN >> A[I].K >>a[i].b; -A[i].id =i; - } inSort (A +1, A + n +1); -Sta[top =1] =1; to for(inti =2; I i) + { -Sta[++top] =i; the while(Top >1) * if(Fabs (A[i].k-a[sta[top-1]].K) i; $ Else if(Top >2 getx (top)-Getx (Top-1) EPS)Panax NotoginsengSta[--top] =i; - Else Break; the } + for(inti =1; I

This problem is relatively simple, the only problem is that the scope is too large, the method of violence can not be, so it may be useful to borrow a mathematical knowledge, I believe that many people in the primary school competition did such a problem: The boss has a string of seven silver ring, can only cut two times, employees to another silver ring every day how to do? The answer to this question is very simple, divided into one or two or three or 43 paragraphs, we may as well extend the t

Description id= schoolbag name Act=2words[name=key] [gap= characters] [quotes= quotes]> Chinese-English mixed content Example 0:Default participle (no gap and quotes parameters)Output Word Segmentation resultsEffect:Full code(sample file: _samples/2words.html)Just a line of code to implement the Chinese + English mixed intelligent word segmentation. Pretty easy.Download and description of light-open platform resourcesPlatform and Latest Development Brochure free Download: http://download.csdn.ne

Itopologicaloperator.convexhull MethodConstructs the convex hull of this geometry.[C #] igeometry convexhull ();Product availabilityavailable with ArcGIS Engine, ArcGIS Desktop, and ArcGIS Server.descriptionThe convexhull of a geometry is the minimal bounding polygon such, all outer angles is convex. The convexhull of a point are the point itself.RemarksItopologicaloperator methods must is applied on high-level geometries only. High-level geometries is point, multipoint, polyline and polygon. T

: Specifies which AP to listen to (specified by AP's Mac)-C: Specify the channel for this AP-W: Captured package saved to file CapfileNote the selected APS:1. Step 4 in the lower part of the bssid and state to have a Mac, meaning to detect a WiFi bssid, and this wifi is connected by one or more machines (the State bar indicates its Mac), step 6 explains why this is selected.6. Force the re-connection so that the handshake packet appearsAireplay-ng-0 2 -a AP 's Bssid -c phone' s Mac Mon0| |　　　　　　

Well, I admit I'm retarded today. Consecutive n days of continuous stay up late, finally the reaction became dull.Today to guide a little brother mistake, because the younger brother is a novice, did not pay attention to his introduction of the package, the results have been tangled, clearly annotated what is no problem, the field name is not a problem, but is reported low-level Org.springframework.orm.hibernate3.HibernateSystemException:Unknown entity: Error.Finally check the imported package,

In this demo we will add the If/else logic to the workflow to show the different message by customizing the condition.If the number of characters in name is odd, the first word outputs "greeting" otherwise outputs "Hello".1. Add a method to the Sayhelloincode class,2. Create a unit test in SayHelloFixture.cs to verify correctness,Running the unit test results in an error and the result is "Hello", since we have not defined the information that the workflow returns under different conditions.3. C

information, such as ' SSH-1.99. '-Grasping DNS request data# tcpdump-i eth1 UDP DST Port 53Other----The-c parameter is also more commonly used for operation and maintenance personnel, because the traffic is relatively large server, by manual CTRL + C orGrasping too much, so you can use the-c parameter to specify how many packets to catch.# time Tcpdump-nn-i eth0 ' tcp[tcpflags] = Tcp-syn '-C 10000 >/dev/nullThe above command calculates how much time it takes to catch 10,000 SYN packets, and yo

when I only white, J Black, she won the probability. Transfer is similar, but this is high accuracy (unlike I have to add additional?) In fact, I don't understand why ... Anyway, the accuracy will be much better ...1 //CF 148D2#include 3#include 4#include 5#include 6#include 7#include 8#include 9 #defineRep (i,n) for (int i=0;iTen #defineF (i,j,n) for (int i=j;i One #defineD (i,j,n) for (int i=j;i>=n;--i) A #definePB Push_back - using namespacestd; - intGetint () { the intv=0, sign=1;CharCh

Portal: Surround the TreesTest instructions: To find the perimeter of the convex hull.Analysis: Convex hull template problem, first ordered by the pole angle, and then determine the convex hull according to the cross product positive and negative.#include #include#include#includestring.h>#includeusing namespacestd;Const DoubleEPS = 1e-8;Const intN = the;intSgnDoublex) { if(Fabs (x) return 0; if(X 0)return-1; Else return 1;}structpoint{Doublex, y; Point () {}, point (Double_x,Double_y) {x= _x;

The main topic: give some hash point and then the initial point is the coordinates of the bottom of the leftmost point, and then only go to the left, to find out the maximum number of points can pass, the serial number output. Analysis: First find out the initial point, and then constantly sort out the nearest bump .... Complexity is N^2*log (n) .... Not a little more, so feel free to play. The code is as follows:===================================================================================

"modules="Isapimodule"Scriptprocessor="%windir%\microsoft.net\framework\v4.0.30319\aspnet_isapi.dll"precondition="Classicmode,runtimeversionv4.0,bitness32"responsebufferlimit="0"/> "Extensionlessurlhandler-isapi-4.0_64bit"Path="*."verb="get,head,post,debug,put,delete,patch,options"modules="Isapimodule"Scriptprocessor="%windir%\microsoft.net\framework64\v4.0.30319\aspnet_isapi.dll"precondition="Classicmode,runtimeversionv4.0,bitness64"responsebufferlimit="0"/> "extensionlessurlhandler-integrated-

-bb_bb60/execute/medialog?cmd=videoendplay"; Xml.open (' POST ', url,true); Xml.setrequestheader ("Content-type", "application/x-www-form-urlencoded"); Xml.onreadystatechange=function () { if(Xml.readystate = = 4) { if(Xml.status = = 200) {console.log (xml.responsetext); }}} xml.send ("Videolog_id=" +res.logid+ "video_id=" +res.videoid); }}} xml.send ("Video_id=_144_1");//Brush the first video fill _144_1, the second video is filled _144_2 so onUnwind Co

Beforerequest in the Software menu-rules-automatic breakpoints Options, Or when these request or response properties match the target's criteria, fiddler can pause HTTP traffic, allowing the request and response to be modified. This functionality is useful for security testing and can also be used for general functional testing, as all code paths can be used for drills. users can join a Inspector plug-in object to write Fiddler extensions using any language under. Net. Requestinspectors and Re

Links: Poj 1113Test Instructions : n vertices of a given polygon castle. Build a fence around the castle, surround all points,and the distance between the wall and all points is at least L. ask for the smallest length of the wall.Ideas : Minimum length = The total edge length of the convex hull consisting of the castle vertices + the circumference of the circle with a radius of LFirst, the convex hull is obtained by the Graham algorithm. Then enumerate its vertices to find the length of the edg