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The first program in the world Programming Competition

39 9d 79 29 3f A F9 36 52 16 FB 5 E8 E5 A6 C2 E9 B0 43 D3 A3 E1e6 CF D3 fd cb D1 4C 5E E0 63 58 86 BB 3E 9 C1 20 bc cc 91 A3 47 81 70 B3 E1ff D6 1A 9e C2 C9 12 E7 4E ad F4 5f E3 30 E9 9 39 D7 E8 F9 F4 D2 44 E8 D7 22 E218 be E2 ce 88 25 CF 30 4A A8 29 AE 3f 47 C6 2D 85 E9 73 54 13 B E6 E0 34 65 E231 E2 50 8A 89 18 5f ce 70 99 3 5f 42 bf eb 7 AE D0 ca 5 22 8d 22 A5 B7 F0 E24a 90 81 BC 7A bc dc 5 dB C0 6a 2 E5 57 38 be 60 Cb AC Ba A5 3B 9d F1 77 38 E263 A6 84 D1 3C af 49 D8 6a 45 A2 76 60 21

Window8.1 64-bit workaround for debug command not available [with bull code]

e19b 3b D0 F7 5f C3 F7 A6 5d 1b CD B2 8 9 A9 c5 ca aa e1b4 4f 3 b4 10 3f AB 6e 9e A8 1d c6 FC E 6a E7 AE BB 5f 7b B8 B4 F7 8 e1cd E2 BF 4e 9d 5 3f a F9 6 FB-E8 e5 a6 C2 e9 B0 for D3 A3 e1e6 CF D3 FD FD CB D1 4c 5e E0 3 3e 9 c1 BC CC A3-9 Bayi B3 e1ff d6 1a 9e C2 C9-E7 4e ad f4 5f e3 E9 D7 E8 F9 f4 D2 E8 D7 e218 be E2 CE 3 CF 4a A8 AE 3f c6 2d-E9-Si-b e6 e0 e231 E2 8a 42 5f CE BF EB 7 AE d0 CA 5 8d A5 B7 f0 e24a-bayi BC 7a BC DC 5 db C0 6a 2 e5-be-cb AC BA A5 3b 9d F1 e263 a6 d1 3c af D8 6a 45

It is said to be the top program in the World Programming contest

E100 f6 Bf 0 B5 f3 A5 8c C8 5 0 2 1 CB E 1f be A1 1 BF 0 1e11b 6 B8 1 BB 7 4b 4b F9 ad E0 8b C8 BD FF FF E8 20e134 0 3d 0 1 1a 7f 3 AA eb f3 2d ff 0 E8 F 0 5a F7 D8 8b D8 8a 1 AAe14f 4a F9 EB de CB (8b C1 F7 F7 F5 8b FB ba 1 4f 4f 4ae168 5 7f F9 8b C5 F7 F7 Notoginseng 2b C8 F7 2 F7 Notoginseng 2b E8 fe e fee181 6 C6 6 fe 7 d0 d1 D1 D1 E5 5a EC B8 one 1 FF 7 4b 4b 48e19b 3b D0 F7 5f C3 F7 a6 5d CD b2 8 9 A9 c5 CA AA 1bE1B4 4f B4 3f AB 6e 9e A8 1d c6 3 FC E 6a E7 AE BB 5f 7b B8 b4 F7 8E1CD E2 BF

Window8.1 64-bit workaround for debug command not available [with bull code]

C3 F7 A6 5d 1b CD B2 8 9 A9 c5 ca aa e1b4 4f 3 b4 10 3f AB 6e 9e A8 1d c6 FC E 6a E7 AE BB 5f 7b B8 B4 F7 8 e1cd E2 BF 4e 9d 5 3f a F9 6 FB-E8 e5 a6 C2 e9 B0 for D3 A3 e1e6 CF D3 FD FD CB D1 4c 5e E0 3 3e 9 c1 BC CC A3-9 Bayi B3 e1ff d6 1a 9e C2 C9-E7 4e ad f4 5f e3 E9 D7 E8 F9 f4 D2 E8 D7 e218 be E2 CE 3 CF 4a A8 AE 3f c6 2d-E9-Si-b e6 e0 e231 E2 8a 42 5f CE BF EB 7 AE d0 CA 5 8d A5 B7 f0 e24a-bayi BC 7a BC DC 5 db C0 6a 2 e5-be-cb AC BA A5 3b 9d F1 e263 a6 d1 3c af D8 6a 45 A2 c0 c2 F2 5e bb

First prize in the world Programming Competition

A5 B7 F0 E24a 90 81 BC 7A bc dc 5 dB C0 6a 2 E5 57 38 be 60 Cb AC Ba A5 3B 9d F1 77 38 E263 A6 84 D1 3C af 49 D8 6a 45 A2 76 60 21 12 C0 C2 44 F2 5E BB E5 37 A9 2B E27b EC 4A 8C 4C F2 F7 A9 58 2B Ba 6D D6 6a E5 60 46 E0 da E5 B9 90 E5 A3 E293 F7 7f 31 60 58 F0 C4 88 10 4E 3C A3 EE 4E 11 55 8f a 92 EB dB ad 7A 9C F E2ac dB 5A 28 96 DA 87 AE 91 91 2D E3 5E EA DF 6 95 71 71 71 40 ce D1 2E 31 6d E2c5 C1 9C D8 6a 76 9B 4A E8 36 44 D6 76 d 30 5 ff D4 1B AC

06th sets of simulated exam for Mathematics Competition Training of Gannan Normal University

\ eeex $ $ A $ reversible. for $ g \ In V ^ * $, take $ \ Bex \ Al = (\ ve_1, \ cdots, \ ve_n) (a ^ {-1 }) ^ t \ sex {\ BA {c} g (\ ve_1) \ vdots \ G (\ ve_n) \ EA} \ In V, \ EEx $ \ beex \ Bea F (\ Al, \ beta) = (G (\ ve_1), \ cdots, g (\ ve_n )) A ^ {-1} \ cdot A \ cdot \ sex {\ BA {L} B _1 \ vdots \ B _n \ EA} \ =\ sum _ {I = 1} ^ n B _ig (\ xi_ I) \\ = g (\ beta), \ quad \ forall \ beta \ In v. \ EEA

A small method for detecting bad points in the screen color.

57 A9 C5 ca AA 1bE1b4 4f 52 B4 92 3f AB 6e 9e A8 1D C6 3 FC e 6a E7 AE BB 5f 7b 10 B8 B4 F7 8E1cd E2 BF 36 4E 39 9d 79 29 3f A F9 36 52 16 FB 5 E8 E5 A6 C2 E9 B0 43 D3 A3E1e6 CF D3 fd cb D1 4C 5E E0 63 58 86 BB 3E 9 C1 20 bc cc 91 A3 47 81 70 B3E1ff D6 1A 9e C2 C9 12 E7 4E ad F4 5f E3 30 E9 9 39 D7 E8 F9 F4 D2 44 E8 D7 22E218 be E2 ce 88 25 CF 30 4A A8 29 AE 3f 47 C6 2D 85 E9 73 54 13 B E6 E0 34 65E231 E2 50 8A 89 18 5f ce 70 99 3 5f 42 bf eb 7 AE D0 ca 5 22 8d 22 A5 B7 F0E24a 90 81 BC 7A bc dc

[3D]-(Open Source) No. 1 in the 1997 World Programming Competition

C2 E9 B0 43 D3 A3E1e6 CF D3 fd cb D1 4C 5E E0 63 58 86 BB 3E 9 C1 20 bc cc 91 A3 47 81 70 B3E1ff D6 1A 9e C2 C9 12 E7 4E ad F4 5f E3 30 E9 9 39 D7 E8 F9 F4 D2 44 E8 D7 22E218 be E2 ce 88 25 CF 30 4A A8 29 AE 3f 47 C6 2D 85 E9 73 54 13 B E6 E0 34 65E231 E2 50 8A 89 18 5f ce 70 99 3 5f 42 bf eb 7 AE D0 ca 5 22 8d 22 A5 B7 F0E24a 90 81 BC 7A bc dc 5 dB C0 6a 2 E5 57 38 be 60 Cb AC Ba A5 3B 9d F1 77 38E263 A6 84 D1 3C af 49 D8 6a 45 A2 76 60 21 12 C0 C2 44 F2 5E BB E5 37 A9 2BE27b EC 4A 8C 4C F2 F7

The best procedure in history

57 38 be 60 Cb AC Ba A5 3B 9d F1 77 38E263 A6 84 D1 3C af 49 D8 6a 45 A2 76 60 21 12 C0 C2 44 F2 5E BB E5 37 A9 2BE27b EC 4A 8C 4C F2 F7 A9 58 2B Ba 6D D6 6a E5 60 46 E0 da E5 B9 90 E5 A3E293 F7 7f 31 60 58 F0 C4 88 10 4E 3C A3 EE 4E 11 55 8f a 92 EB dB ad 7A 9C FE2ac dB 5A 28 96 DA 87 AE 91 91 2D E3 5E EA DF 6 95 71 71 71 40 ce D1 2E 31 6dE2c5 C1 9C D8 6a 76 9B 4A E8 36 44 D6 76 d 30 5 ff D4 1B AC 1f 32 65 31 BF 55E2de 26 B A4 55 E1 5d 5E 16 ed 97 4

Strange code (debug <1.txt)

F1 77 38E263 A6 84 D1 3C af 49 D8 6a 45 A2 76 60 21 12 C0 C2 44 F2 5E BB E5 37 A9 2BE27b EC 4A 8C 4C F2 F7 A9 58 2B Ba 6D D6 6a E5 60 46 E0 da E5 B9 90 E5 A3E293 F7 7f 31 60 58 F0 C4 88 10 4E 3C A3 EE 4E 11 55 8f a 92 EB dB ad 7A 9C FE2ac dB 5A 28 96 DA 87 AE 91 91 2D E3 5E EA DF 6 95 71 71 71 40 ce D1 2E 31 6dE2c5 C1 9C D8 6a 76 9B 4A E8 36 44 D6 76 d 30 5 ff D4 1B AC 1f 32 65 31 BF 55E2de 26 B A4 55 E1 5d 5E 16 ed 97 48 6C 77 FB 81 86 e F9 18 BD D4

Do our ancestors write programs like this?

73 54 13 B E6 E0 34 65E231 E2 50 8A 89 18 5f ce 70 99 3 5f 42 bf eb 7 AE D0 ca 5 22 8d 22 A5 B7 F0E24a 90 81 BC 7A bc dc 5 dB C0 6a 2 E5 57 38 be 60 Cb AC Ba A5 3B 9d F1 77 38E263 A6 84 D1 3C af 49 D8 6a 45 A2 76 60 21 12 C0 C2 44 F2 5E BB E5 37 A9 2BE27b EC 4A 8C 4C F2 F7 A9 58 2B Ba 6D D6 6a E5 60 46 E0 da E5 B9 90 E5 A3E293 F7 7f 31 60 58 F0 C4 88 10 4E 3C A3 EE 4E 11 55 8f a 92 EB dB ad 7A 9C FE2ac dB 5A 28 96 DA 87 AE 91 91 2D E3 5E EA DF 6 95 7

First in the world Programming Competition

E9 73 54 13 B E6 E0 34 65E231 E2 50 8A 89 18 5f ce 70 99 3 5f 42 bf eb 7 AE D0 ca 5 22 8d 22 A5 B7 F0E24a 90 81 BC 7A bc dc 5 dB C0 6a 2 E5 57 38 be 60 Cb AC Ba A5 3B 9d F1 77 38E263 A6 84 D1 3C af 49 D8 6a 45 A2 76 60 21 12 C0 C2 44 F2 5E BB E5 37 A9 2BE27b EC 4A 8C 4C F2 F7 A9 58 2B Ba 6D D6 6a E5 60 46 E0 da E5 B9 90 E5 A3E293 F7 7f 31 60 58 F0 C4 88 10 4E 3C A3 EE 4E 11 55 8f a 92 EB dB ad 7A 9C FE2ac dB 5A 28 96 DA 87 AE 91 91 2D E3 5E EA DF 6 9

World Hacker Programming Competition champion Code, very shocking ~ ~ (_ Programming essay

B3e1ff d6 1a 9e C2 C9 E7 4e ad f4 5f E3 E9 9 D7 E8 F9 f4 D2 E8 22 D7e218 be E2 CE (CF) 4a A8 AE 3f c6 2d e9 34 E6 E0 65e231 E2 8a 5f ce 3 5f bf eb 7 AE d0 ca 5 8d a5 b7 f0e24a BC 7a BC DC 5 db C0 6a 2 e5 to CB AC BA A5 3b 9d F1 77 38e263 a6 D1 3c af D8 6a A2 c0 5e BB c2 notoginseng F2 2be27b EC 4a 8c 4c F2 F7 A9 2b Ba 6d d6 6a e5 e0 da e5 b9 e5e293 F7 7f F0 c4 4e 3c A3 ee 4e 8f A-EB db ad 7a 9c FE2AC DB 5a da E3 AE 2d 5e ea DF 6 m ce D1 2e 6dE2C5 C1

SQL diagram, tree, hierarchy

Label:UDF: User-defined functions CTE: Common table expressionSET NOCOUNT on;Use ZhubenxiGoIf OBJECT_ID (' dbo. Parts ') is not nullDROP TABLE dbo. Parts;If OBJECT_ID (' dbo. BOM ') is not NULLDROP TABLE DBO. BOM;CREATE TABLE dbo. Parts(PartID int NOT null primary key,PartName varchar (+) NOT NULL);INSERT INTO dbo. Parts (PartID, PartName) VALUES (1, ' Black tea '), (2, ' white Tea '), (3, ' Latte '), (4, ' Espresso '), (5, ' double Espresso '), (6, ' Cup Cover '), (7, ' regular Cup '), (8, ' st

Service-oriented analysis and design principles

Service-oriented analysis and design principles Author/OLAF Zimmermann, pal krogdahl, Clive Gee Experience from the initial Service-Oriented Architecture (SOA) Implementation Project shows that, for example, object-oriented analysis and design (OOAD) enterprise Architecture (EA) framework and business process modeling (BPM) such existing development processes and representations only cover some of the requirements required to support the architecture

On July 6, April 22, a small program for modifying the DACL of the Registry

read-control and write-DACL access rights are granted. if these rights were the only access rights that caller requested, access is granted without examining the DACL. then you have the write-DACL permission ,, However, the program does not have that many functions. Generally, you only need to move the original write-DACL. /*************************************** ******************************* This registry permission is granted with the DACL write permission on the registry.* Writen by uty @

SCAC Connection Microsoftazure

First of all feel the nine uncle this Microsoft Cloud Expert MVP Guide! http://jiushu.blog.51cto.com/After the installation of SCAC, we can link to SCVMM and can also connect windowsazure, how to do it?First we need to apply for a certificate and export the certificate to 2 copies, one copy of a PFX CERThe current domestic azure does not, the international version can be650) this.width=650; "height=" 251 "title=" clip_image001 "style=" border:0px;padding-top:0px;padding-right:0px; Padding-left:0

[Journal of mathematics at home University] 259th Capital Normal University 2013 advanced algebra postgraduate exam reference

1 ($ 15' $) The first coefficient with the lowest number of results is $1 $ real number polynomial $ f (x) $ \ Bex F (0) = 7, \ quad F (1) = 14, \ quad F (2) = 35, \ quad F (3) = 76. \ EEx $ Answer: Set $ f (x) = x ^ 4 + a_3x ^ 3 + a_2x ^ 2 + a_1x + a_0. $ indicates the meaning of the question, $ \ Bex \ sedd {\ BA {rrrrrrrrrrl} a_0 = 7, \ a_0 + A_1 + A_2 + A_3 + 1 = 14, \ a_0 + 2A_1 + 4a_2 + 8a_3 + 16 = 35, \ a_0 + 3a_1 + 9a_2 + 27a_3 + 81 = 76. \

09th sets of simulated exam for Mathematics Competition Training of Gannan Normal University

}}\\ = C ^ tab ^ t + cab. \ EEA \ eeex $ 2. if $ A (t) = (a _ {IJ} (t) $ is set, each $ A _ {IJ} (t) $ is bootable. test certificate: $ \ Bex \ frac {\ RD} {\ RD t} | A (t) | = | A (t) | \ cdot \ tr \ SEZ {A ^ {-1} (t) \ cdot \ frac {\ RD a (t) }{\ rd T }}. \ EEx $ Proof: $ \ beex \ Bea \ frac {\ RD} {\ RD t} | A (t) | =\ sum (-1) ^ {\ Tau (I _1 \ cdots I _n)} \ frac {\ RD} {\ RD t} \ SEZ {A _ {1i_1} (t) \ cdots A _ {ni_n} (t) }\\\=\ sum (-1) ^ {\ Tau (I _1 \ cdots I _n )} \ sum_k A _ {1i_1}

Security Basics for Windows-Access Control

"); Return-1;} else if (brtnbool = true) // print The account name. _ tprintf (text ("account owner = % s \ n"), acctname); // print DACL information if (null = pdacl |! Isvalidacl (pdacl) Return-1; acl_size_information ASI; If (! Getaclinformation (pdacl, ASI, sizeof (ASI), aclsizeinformation) Return-1; for (INT I = 0; I ====================================== Create an object with security attributes-File ====================================== Void createkeywithsecdesc (char * filepath) {D

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