January 2015 according to statistics, by the New Year's Day and seasonal factors, commodity prices continue to decline and domestic and foreign market demand overall continued weak, order growth continued to fall in three factors, manufacturing enterprises slowed down production and business activities, February is expected to continue to decline in hardware and electronic market overall sales But in terms of market conditions and confidence, or there
wave of lows. Conversely, the downward trend refers to the development of the market, the wave-like trend of the low point continued to decline, and rebound highs can not travel through the previous wave of highs. For the ascending trend, the length of the ascending wave exceeds the descending wave. In a clear upward trend, prices are mostly in the vicinity of the highest price in the plate. Conversely, in a clear downward trend, the closing price mo
QuestionSay you has an array for which the i-th element is the price of a given-stock on day I.Design an algorithm to find the maximum profit. You are in most of the transactions.Note:Engage in multiple transactions on the same time (ie, you must sell the stock before you buy again).SolutionThis problem can is solved by "divide and conquer". We can use Left[i] array to track maximum profit for transactions before I (including i), and Right[i + 1] to track Maximu M profit for Transcations after
Say you has an array for which the i-th element is the price of a given-stock on day I.Design an algorithm to find the maximum profit. Many transactions as (ie, buy one and sell one share of the stock multiple times) with the FO Llowing Restrictions:
Engage in multiple transactions on the same time (ie, you must sell the stock before you buy again).
After you sell your the stock, you cannot buy the stock on next day. (ie, cooldown 1 day)
Example:Prices = [1, 2, 3, 0, 2]maxprof
An extension of the best time to Buy and Sell Stock III. The idea was still to use dynamic programming (see here for detailed introduction). However, in this problem, some trick (the quickprofit function below) are required to pass the TLE.The code is rewritten below.1 classSolution {2 Public:3 intMaxprofit (intK, vectorint>prices) {4 intn =prices.size ();5 if(k >= N/2)returnQuickprofit (price
of all listed stocks. Therefore, people often choose several representative Stock Samples from listed stocks, and calculate the average price or index of these samples. It is used to indicate the overall trend of stock prices and the increase or decrease of the entire market. When calculating the average or index of the stock price, the following four points are often taken into account: (1) the sample stock must be typical and common. Therefore, sel
Chicago?:" + Cities.contains ("Chicago"));
This is also an imperative style of writing--contains method directly to help us fix it.
where the actual improvement
There are several advantages to writing this code:
1. No more tinkering with that variable.2. Encapsulate the iteration to the bottom3. More Concise Code4. Clearer and more focused code5. Less detours, code and business needs to combine more closely6. Easy to make mistakes7. Easy to understand and maintain
Let's take a more
title :Say you has an array for which the i-th element is the price of a given-stock on day I.Design an algorithm to find the maximum profit. You are in most of the transactions.Note:Engage in multiple transactions on the same time (ie, you must sell the stock before you buy again).Code : runtime:175 ms1 classSolution:2 #@param prices, a list of integers3 #@return An integer4 defmaxprofit_with_k_transactions (self,
column1 FROM t2 );
SELECT * FROM t1 is called Outer Query (external Query or Outer Statement), and SELECT column1 FROM t2 is called
It is a Sub Query (subquery ).2 subqueries
A subquery is nested inside a query and must always appear in parentheses.
A subquery can contain multiple keywords or conditions, such as DISTINCT, group by, order by, LIMIT, and related functions.
The outer query of the subquery can be SELECT, INSERT, UPDATE, SET, or DO.
Therefore, subqueries are nested inside external q
Please help, modify a regular preg_replace replace problem first thanks to master microlab2009, and xuzuning moderator, in the first post enthusiastic answer http://bbs.csdn.net/topics/390720868
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I have used the following code to output the "number" in the article content as an image, which works very well, but there is a problem: some articles contain image tags, such
When you replace an image, replace the number in the
Update Leetcode to solve Java answers on a regular basis.Choose from the pick one approach.Test instructions to allow only one sale, the given array is the price of the item of the day, ask the maximum benefit is how much.Obviously the best way to get the most benefit is to iterate through the array, and in the process of traversal, the price of each day is read, and it is compared with the minimum value obtained by the preceding traversal, which is the maximum benefit to sell a single time on t
Price B
A supplier supports his medium-disk vendors with an attitude of "unchanged" for price fluctuations on the market. But is this really the best price strategy? Are there any worries?
English text
A: You know, I think it's smart to stay with the same low price. Your MERs will be pleased.B: We think that the basis price shocould stay low. It's wrong to raise prices just because market demand is going up fast.A: Right. With such competitive
, we either take a rest, by just using the old decision at I-1, *or buy At/before i-1, then sell at I . *so we get the following formula: *buy[i] = Math.max (Buy[i-1], sell[i-2]-prices[i]); *sell[i] = Math.max (Sell[i-1], buy[i-1] + prices[i]);*/ Public intMAXPROFIT5 (int[] prices) { if(Prices
1.ref:http://blog.csdn.net/linhuanmars/article/details/23164149The difference is that it can be traded infinitely many times (of course we know that the deal will not exceed n-1 times, that is, every day we sell first and buy it). Since there is no limit to the number of transactions, we can see that we can get the maximum profit if we trade for a two-day spread greater than 0. So the algorithm is actually adding up all the spreads greater than 0 can be, very simple. So only a single scan is req
Topic:Say you has an array for which the i-th element is the price of a given-stock on day I.If you were-permitted-to-complete at most one transaction (ie, buy one and sell one share of the stock), design an AL Gorithm to find the maximum profit.Analysis: One-dimensional dynamic programming (hard counting is OK)Dp[i] is the maximum profit for the [0,1,2...i] interval, the one-dimensional dynamic programming equation for the problem is as followsDP[I+1] = Max{dp[i],
Title Description:Say you has an array for which the i-th element is the price of a given-stock on day I.Design an algorithm to find the maximum profit. You could complete as many transactions as (ie, buy one and sell one share of the stock multiple times). However, engage in multiple transactions for the same time (ie, you must sell the stock before you buy again).Problem Solving Ideas:Greedy algorithm: The profit is updated as long as the current value is smaller than the previous value.1 clas
arrays. In the related array, you can associate each variable value with any keyword or index.
1 Initializing related arrays
The code shown below can create a related array with the product name as the keyword and the price as the value:
$prices = Array (' Tires ' =>100, ' oil ' =>10, ' Spark plugs ' =>4);
The symbol between the keyword and the value is just a greater than sign with the equals sign.
2 Accessing array elements
Similarly, you can use v
Php traversal array foreacheach () list () method summary
Foreach ($ array as $ value) {// $ array indicates the array to be traversed. $ value indicates the pointer pointing to the current value of the array. as assigns a value.
Code to executed;
}
The foreach statement can also obtain the key name of the array, as shown below:
Foreach ($ array as $ key => $ value ){
Echo $ key "-" $ value ."";
}
2. the echo () function eac
Personally, this is a relatively difficult DP problem. This link posts a typical DP solution to it. Need some time to get how it works.The code is rewritten as follows.1 classSolution {2 Public:3 intMaxprofit (vectorint>prices) {4 intn = prices.size (), num =2;5 if(N 1)return 0;6vectorint> > dp (num +1, vectorint> (n,0));7 for(intK =1; K ) {8 inttemp = dp[k-1][0]-prices
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