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the kernel shellcode and the user shellcode. The kernel shellcode is responsible for returning and executing the user shellcode. The user shellcode is a common function. You must add the firewall-based code. The following is the kernel shellcode Code, which does not provide complete shellcode, because first, it is only for technical research, but not to be used by people who do not know nothing about the technology but only want to destroy it. The machine code to be converted is only 230 bytes

" _asm _emit (0x48) _asm _emit (0x65) _asm _emit (0x6c) _asm _emit (0x6c) _asm _emit (0x6f) _asm _emit (0x20) _asm _emit (0x57) _asm _emit (0x6f) _asm _emit (0x72) _asm _emit (0x6c) _asm _em It (0x64) _asm _emit (0x21) _asm _emit (0x00) Tag_shellcode:call tag_next; Tag_next: Pop ebx; Get critical module Base address mov esi, DWORD ptr fs: [0x30]; mov esi, [esi + 0x0c]; mov esi, [esi + 0x1c];

: = ttest.create;Test1: = Test;Test2: = Test;If Integer (Test1) ShowMessage (' It is not eqeual ');End;Finally, a dialog box appears stating that Test1 and Test2 are not equal, and that the two variables are equal only if the property is the same interface type, such as Test1 and Test2 are iinterface, then their "values" are equal.OK, look back at the previous code snippet, set a breakpoint in line 4th, run the program and make the above code execution, the program executes to the breakpoint, ab

_emit (0x6f) _asm _emit (0x72) _asm _emit (0x6c) _asm _em It (0x64) _asm _emit (0x21) _asm _emit (0x00) Tag_shellcode:call tag_next; Tag_next: Pop ebx; Get critical module Base address mov esi, DWORD ptr fs: [0x30]; mov esi, [esi + 0x0c]; mov esi, [esi + 0x1c]; mov esi, [esi]; mov edx, [esi + 0x08];

: Baiyun district .. 1. dib32-bit, pre-multiplication alpha proc AlphaPreMul uses ebx edi, pBitDst,pDstRect,dwDstWight local dwWight:DWORD,dwHight:DWORD ;--------------------------------------- mov edi,[pBitDst] mov edx,[pDstRect] ;(p,q) mov eax,[edx+RECT.right] test eax,eax jz .exit mov [dwWight],eax mov eax,[

// Big map. Text: 6f3a2060 sub_6f3a2060 proc near; Code xref: sub_6f38d120 + 67 P. Text: 6f3a2060; sub_6f39bca0 + 67 P.... Text: 6f3a2060. Text: 6f3a2060 var_8 = dword ptr-8. Text: 6f3a2060 var_4 = dword ptr-4. Text: 6f3a2060 arg_0 = dword ptr 4. Text: 6f3a2060 arg_4 = dword ptr 8. Text: 6f3a2060 arg_8 = dword ptr 0ch. Text: 6f3a2060 arg_c = dword ptr 10 h. Text: 6f3a2060. Text: 6f3a2060 sub ESP, 8. Text: 6f3a2063 mov eax, [esp + 8 + arg_4]. Text: 6f3a2067 push EBX. Text: 6f3a2068 push EBP. Text

showwindow, hwnd, sw_restore Invoke setforegroundwindow, hwnd . Endif . Endif . Elseif umsg = wm_timer . If Hd = 0 Invoke findwindow, 0, ADDR targettitle . If eax! = 0 Invoke getwindowthreadprocessid, eax, ADDR PID Invoke OpenProcess, process_all_access, false, PID MoV HD, eax . Endif . Endif . If flag1 = 1 Invoke writeprocessmemory, HD, addr1, ADDR value1, sizeof value1, null . If eax = 0 MoV HD, 0 . Endif . Endif . If flag2 = 1 Invoke writeprocessmemory, HD, addr2, ADDR value2, sizeof value2,

In Windows 7x86, the implementation of the kernel module NT (that is, the ntkrpamp module: Offset machine code command nt! Memset: 83c8ce40 8b54240c mov edX, dword ptr [esp + 0ch] 83c8ce44 8b4c2404 mov ECx, dword ptr [esp + 4] 83c8ce48 85d2 test edX, edx83c8ce4a 744f je nt! Memset + 0x5b (83c8ce9b) 83c8ce4c 33c0 XOR eax, eax83c8ce4e 8a442408 mov Al, byte PTR [esp + 8] 83c8ce52 57 push edi83c8ce53 8bf9 mov E

Kindle will never start File Download:Http://pan.baidu.com/s/1jG3RaGADouble-click it to open it. (460.cd8): Access violation - code c0000005 (!!! second chance !!!)*** ERROR: Symbol file could not be found. Defaulted to export symbols for F:\Program Files (x86)\Amazon\Kindle\Kindle.exe - eax=000000dd ebx=000004e4 ecx=00000000 edx=0022ed44 esi=0022ed68 edi=000000ddeip=0197383f esp=0022ed14 ebp=05920448 iopl=0 nv up ei pl nz na po nccs=0023 s

test ecx,3 jne short str_misaligned add eax,dword ptr 0 ; 5 byte nop to align label below align 16 ; should be redundantmain_loop: mov eax,dword ptr [ecx] ; read 4 bytes mov edx,7efefeffh add edx,eax xor eax,-1 xor eax,edx add

package as the boundary symbol.Let's take a look at the assembly code it handles:. Text: 74cb72a1 loc_74cb72a1:. Text: 74cb72a1 mov edX, [EBP + var_4]. Text: 74cb72a4 mov eax, [EBP + var_104c] Number of existing loops in the ebp-0x104c. Text: 74cb72aa CMP eax, [edX + 8] edX + 8 storage Total number of packages received. Text: 74cb72ad jge loc_74cb70f2. Text: 74c

? Do you want to know?To learn more, go to the function:Let's first look at the situation 1: Unit1.pas. 46: B: = Copy (s, 1,400); lea eax, [ebp-$14] push eaxmov ecx, $ 0000020.mov edx, $ 00000001mov eax, [esi + $00000308] call @ LStrCopy // follow in ------------- @ LStrCopy --------- push ebxtest eax, eaxjz + $2 dmov ebx, [eax-$04] test ebx, ebxjz + $ 26dec edxjl + $1 bcmp edx, ebxjnl + $1 fsub ebx, edxtes

nop00B60072 90 nop00B60073 90 nop00B60074 90 nop00B60075 90 nop00B60076 90 nop00B60077 90 nop00B60078 90 nop00B60079 90 nop00B6007A 90 nop00B6007B 90 nop00B6007C 90 nop00B6007D 90 nop00B6007E 90 nop00B6007F 90 nop00B60080 90 nop00B60081 90 nop00B60082 90 nop00B60083 90 nop00B60084 90 nop00B60085 90 nop00B60086 90 nop00B60087 90 nop00B60088 90 nop00B60089 90 nop00B6008A 90 nop00B6008B 90 nop00B6008C 90 nop00B6008D 90 nop00B6008E 90 nop00B6008F 90 nop00B60090 90 nop00B60091 90 nop00B60092 90 nop0

better in some old cases than in cdecl/stdcall (because of the pressure on small stacks ). However, using this call method in modern CPUs may not necessarily achieve better performance. Fastcall is not standardized, so the implementations of different compilers can be different. This is a well-known warning: if you have two DLL, the first of which calls the second DLL function, they are compiled by different compilers using the fastcall call method, there will be unpredictable consequences. Bot

Obtain the dialog box data and determine the length: 004011b5 |. 6a 14 push 0x14;/COUNT = 14 (20 .) 004011b7 |. 51 push ECx; | buffer = 0018f8b8004011b8 |. 66: 894424 2D mov word PTR [esp + 0x2d], ax; | 004011bd |. 68 e8030000 push 0x3e8; | controlid = 3e8 (1000 .) 004011c2 |. 52 push edX; | hwnd004011c3 |. c64424 20 00 mov byte PTR [esp + 0x20], 0x0; | 004011c8 |. 884424 37 mov byte PTR [esp + 0x37], Al; | 004011cc |. 33ed xor ebp, EBP; | 004011ce |.

CauseBy default, a registered user of studio can create a course that does not appear to be the usual usage scenario, and the platform owner prefers a review to allow the user to publish the courseIdeasRead the wiki!!For the novice who is tossing edx, I think the first job is two points:1. Let the platform run up2. Read through the wiki (configuration wiki and edx-platform wiki)If you read through the wiki,

hBswap eax;; X = (X | (x> 3) 0x03030303; // 0000 00ab 0000 00cd 0000 00ef 0000 00ghMoV edX, eax;SHR edX, 3;Or eax, EDX;And eax, 03030303 h;; X = (X | (x> 6); // 0000 00ab 0000 ABCD 0000 00ef 0000 efghMoV edX, eax;SHR edX, 6;Or eax, EDX