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functions are slightly different from the previous ones. The print function appears virtual before. However, this virtual has played a huge role. It is no exaggeration to say that, without virtual functions, there is basically no design pattern, which cannot reflect the great superiority of the C ++ language in object-oriented design. Let's take a look at how this virtual works? 76: employee p; 0040128D lea ecx, [ebp-10h] 00401290 call @ ILT + 45 (employee: employee) (00401032) 00401295 mov d

, for a loop statement, the%EBX value is increased by 1, and when%EBX is no more than 5 o'clock, repeat the process, i.e.%ebx=%ebx+1;%eax=%ebx+1,%eax=%eax* the value of the previous validated number, comparing the%EAX to the value currently being validatedTherefore the first value is 1, the second value should be (+) *1=2, the third value is (2+1) *2=6, the fourth value is (3+1) *6=24, the fifth value is (4+1) *24=120, and the sixth value is (5+1) *120=720. Phase_3 Phase_3 also cal

And the list of awesome-* series Bayandin/awesome-awesomeness GitHub sqlmap! goagent! Yes, there's shadowsocks!. Open EdX Open EdX is committed to creating a powerful and flexible, open and large-scale online classroom platform. Also used to study learning and distance education After graduation, the most familiar thing is this project. Tall may not be, technically not stunning, after all, is busine

0x10ce28462 Ten: Pushq%r12 0x10ce28464 A: Pushq%rbx 0x10ce28465 -: Pushq%rax 0x10ce28466 -: Movq%rdi,%RBX 0x10ce28469 -: Xorl%eax,%eax 0x10ce2846b +: Testq%rbx,%RBX 0x10ce2846e A:JE0x10ce28534;0x10ce28474 -: Leaq 0x8 (%RBX),%RCX 0x10ce28478 +: Testl $0x1000000, 0x8 (%RBX) 0x10ce2847f the:jne0x10ce284db;0x10ce28481 A: Testl $0x8000000, (%RCX) 0x10ce28487 -:jne0x10ce284f8;0x10ce28489 the: Testl $0x10000000, (%RCX) 0x10ce2848f -:jne0x10ce28531;0x10ce28495 A: Movb 0xbad (%rip),%al;ISG

:00440f2c |. 8b45 FC MOV eax,dword PTR ss:[ebp-4]00440f2f |.BA 14104400 MOV edx,crackme3.00441014; ASCII "Registered User"00440f34 |.E8 F32BFCFF call crackme3.00403b2c; The key is to go with F7.00440f39 |.JNZ short crackme3.00440f8c; This is the end of the jump.00440f3b |. 8d55 FC LEA edx,dword PTR ss:[ebp-4]00440f3e |. 8b83 C8020000 MOV eax,dword PTR Ds:[ebx+2c8]00440f44 |. E8 D7FEFDFF Call Crackme3.00420e

: 0040823co. Text: 00408284. Text: 00408284 m_l_table = dword ptr-58 h. Text: 00408284 m_ B = DWORD PTR-18 h. Text: 00408284 M_a = dword ptr-14 h. Text: 00408284 m_k = dword ptr-10 h. Text: 00408284 m_j = dword ptr-0ch. Text: 00408284 m_ I = DWORD PTR-8. Text: 00408284 l_key = dword ptr-4. Text: 00408284. Text: 00408284 push EBP. Text: 00408285 mov EBP, ESP. Text: 00408287 add ESP, 0ffffffa8h. Text: 0040828a mov [EBP + l_key], eax. Text: 0040828d mov eax, [EBP + l_key]. Text: 00408290 mov ECx, [

program writer's quality decision.The inline assembly is passed in C + +The results of the actual discovery of 500W data are as follows:Algorithm name inline assembly algorithm time C + + algorithm timeBubble sort 5W Data slow dying 5W data slow to deathQuick sort 600ms about 500ms around------------------Why there is a fast sorting algorithm, the results of the assembly is not a C + + efficiency is high, because I write the inline assembly is not automatically generated by the compiler high ef

the quality of the high and low decision. Inline assembly is passed in C + + actually found the 500W data sorting results are as follows: Algorithm name inline assembler algorithm time C + + algorithm time Bubble sort 5W data slow to die 5W data slowly dying. Quick sort 600ms about 500ms around ------------------Why there is a fast sorting algorithm, the compiled results are not as high as C/s + + efficiency, because I write inline assembly without compiler automatic generation of high efficien

body | ---------> @ 2|------> | -------------------- +|| Decryptor || ---------> @ 3+ -------------------- +@ 1 is a call constructed by computation, because the call location must be determined by @ 2.@ 2 is an encrypted virus.@ 3 is an encryptor used to decrypt @ 2, which is transformed by code obfuscation.In this way, every time other files are infected, the re-generated code will no longer have a fixed feature, which will invalidate the feature scanning mechanism. 2.1 random number design:T

microsecondsFmt6 dB/'================================================ =========== ', 0dh, 0ah ,/'Simple ASM Program to compute PI with invalid digits. ', 0dh, 0ah ,/'Pi/4 = 12 * arctan (1/18) + 8 * arctan (1/57)-5 * arctan (1/239) (Gauss )',/0dh, 0ah, 'by G-spider @ 2010', 0dh, 0ah ,/'Computation of 10000 digits of PI ', 0dh, 0ah ,/'Total computation time :',/'% 6lld Ms', 0dh, 0ah ,/'================================================ ============ ', 0dh, 0ah, 0 . Data?X dd?Y dd?_ Sizechar dd?Lppi

layout is skipped. Next let's take a look at the virtual function calling Pt-> Foo (); Through the pointer. The resulting assembly code is as follows:01 004230f6 mov eax, dword ptr [EBP + fffff900h]02 004230fc mov edX, dword ptr [eax]03 004230fe mov ESI, ESP04 00423100 mov ECx, dword ptr [EBP + fffff900h]05 00423106 call dword ptr [edX]In row 1st, the address directed by PT is moved into the eax register,

the siteCall makefs4gbsegment; the returned FS segment can be 4 GB memory. EBX =.############# Map the code to a linear address of 80000000 H + CS * 4, avoid NTS not mapped to memory reserved by our code ############MoV eax, FS: [EBX + 800 H]; eax = Linear address up to 10 bits 400 h * 4 = 800 H, determine the location of the page Directory table pointed to in S3.And eax, 0fffff000h; remove the obtained Level 2 page table attribute bit. eax = 80000000h linear address Level 2 page table physical

check_03 sub eax, ebx jmp this_exitcheck_03: CMP Cl, '*' jnz check_04 imul ebx jmp limit: CMP Cl, '/'jnz err XOR edX, EDX idiv ebx jmp this_exiterr: XOR eax, eax this_exit: retcalc endp; var_mode: input parameter,; mode = 1, expression analysis completed, 0: there are currently four Arithmetic Operators; Return Value: none; this procedure work on global array num_arr, op_arr, num_count, op_countdo_calc Pro

Tags: Assembly atampt Addition: . Section. DataVAL: . Quad 3481219651 Val1: . Quad 6678934517 Output: . Asciz "the RES is % QD \ n" . Section. Text. Globl _ start _ Start: Movl Val, % eax Movl Val + 4, % EBX Movl val1, % ECx Movl val1 + 4, % edX Addl % eax, % ECx Adcl % EBX, % edX Pushl %

2eac4 2e9c |. 85c test eax, eax // The registration code is converted to hexadecimal 4b235264 2e9e |. 7c 12 JL short China Communications. 4 2eb24 2ea |> 59 pop ECx // false code 787878784 2ea1 |. 31f6 xor esi, ESI // ESI = 1 2fc59 = 169728894 2ea3 | gt; 8932 mov dword ptr ds: [edX], ESI4 2ea5 |. 5f pop EDI4 2ea6 |. 5E pop ESI4 2ea7 |. 5B pop EBX // EBX = 787878784 2ea8 |. C3 retn 4 A |. 8bf mov ESI, eax // ESI = A eax = 4b235264 A A2 |. 833c24 cmp

. Text: 000387c9 call kegetcurrentirql. Text: 000387c9. Text: 000387ce and eax, 0ffh. Text: 000387d3 test eax, eax. Text: 000387d5 jnz short loc_387ef. Text: 000387d5. Text: 000387d7 call sub_37b5f. Text: 000387d7. Text: 000387dc test eax, eax. Text: 000387de JZ short loc_387ef. Text: 000387de. Text: 000387e0 mov dword_4b258, 0. Text: 000387ea call sub_37b9a. Text: 000387ea. Text: 000387ef. Text: 000387ef loc_387ef:; Code xref: sub_38736 + 91 \ u0018j. Text: 000387ef; sub_38736 + 9f \ u0018j. Te

add eax,0x8; Pptr+2 003cc57c; In C language, the operation of pointers is 003cc57c based on pointer type; An int pointer plus 1 means that the address it points to is moved backward in length to a 003cc57c; The distance of the int size, which is 4 bytes. If it's a word type, move backwards by 2 bytes. 003cc57f Push eax003cc580 mov ecx,[local.7]003cc583 add ecx,0x4; Pptr+1 003cc586 push ecx003cc587 mov edx,[local.7]003cc58a push

(MOV) (An immediate number is actually a constant integer.) different operand type combinations supported by the data transfer Directive What is inside the parentheses represents the memory address. (For example,%eax, which represents a memory address.) Simple addressing mode If we have an operand that accesses memory, then how is the memory address calculated or referred to as how it is addressed. (-Indirect addressing Take Movl (%ECX),%eax as an example: The register ECX inside the value a