effective java third edition

check the idea:because the result of f (n) is modulo 7, then the result of f (n) is only possible in {0,1,2,3,4,5,6,}, so that the result of f (n) and F (n-1) is only 7*7 = 49, and the reasonable use of periodicity can greatly improve the program run time. Don't want to say, this question more say a word all make me sick!! Thanks to Kim Yong Qing bo friends answer! http://blog.csdn.net/jinyongqing/article/details/21537175Import Java.io.*;import java.util.*;p ublic class main{public static

48916.3.4 process contains how many steps 49016.3.5 need to control and monitor 4911 6.3.6 when to redefine a project objective 49216.4 law Field 49216.4.1 Royce Methodology 49316.4.2 Extreme Programming (XP) 49616.4.3 Rugby methodology 50016.5 Case study 50516.5.1 XP project: ATRAC T 50616.5.2 Local main customer: FRIEND 50816.5.3 Distributed project: JAMES 51316.5.4 Case Study summary 51816.6 recommended readings 52116.7 Exercise 521 Part 4 Appendix Appendix A design Pattern 525a.1 Abstrac T

; StringBuffer sb = new StringbuffeR (); if (httpent! = null) {BufferedReader BR = new BufferedReader (New InputStreamReader (Httpent.getcontent (), "UTF-8")); while (line = Br.readline ())! = null) {sb.append (line);} Br.close ();} return new string[] {sb.tostring (), Code};}Here are the parameters that are taken with the post:String obj = "r={\" ptwebqq\ ": \" "+ ptwebqq +" \ ", \" clientid\ ":" + ClientID + ", \" psessionid\ ": \" \ ", \" status\ ": \" Online\ "} ";where "r=" can not be lost,

(); } } } returnSingleton; } PrivateSingletonSlacker2 () {}}6. Order reorderingIn fact, creating an object often consists of three processes.For Singleton = new Singleton (), this is not an atomic operation, including three procedures in the JVM.1. Allocating memory to Singleton2. Call the constructor of Singleton to initialize the member variables to form an instance3. Point the Singleton object to the allocated memory space (singleton is not NULL after executing th

servlet_local:8080 "5. Use Php-java-bridge in your projectHere is an example code that needs to be modified with your project requirementsThe code is as follows:6, according to the above five operation, Basic is no problem, if there is a problem, please check your code call is correctAbout official online:if the project is to be formally launched, replace the Payclient.properties file with the khpaymenturl=https://testebank.sdb.com.cn:461/corporbank/

example, a landing page, using the PO mode, will create a LoginPage class, the class will define the user name input box, password input box, login button webelenentFor the corresponding element to implement the corresponding method, the input box is used to input, you need to create a user name and enter the password method, so that the real page consistent, so the design concept is PO mode. The pagefactory belongs to the PO mode, which is used to initialize the page Class of each PO pattern i

The previous period of time to learn appium, today is ready to appium environment to build the process of writing, so that we can take a few detours. 1. Install the JDK and make the environment variable configuration environment variable configuration: Add Java_home variable, value: JDK installation path, such as: D:\Java\jdk1.7.0_45 add Classpath variable, value.;　　%java_home%\lib\tools.jar;%java_home%\lib\dt.jar Modify the path variable, plus this s

described in this article.Note: If the message content has a carriage return, it may fail to send. I do not know the carriage return character how to transcode, anyway, how hair is a failure, easy language forum someone in January 15 wrote a solution was adopted, but I follow the Java way to write or send failed, because I do not understand easy language, so maybe I understand wrong.Say something else a little bit more.At present I have seen 2 kinds

sentence:sentences) {//System.out.println (segmenter.process (sentence, segmode.index). toString ());String uuid =Uuid.randomuuid (). toString (); UUID= Uuid.replace ("-", "" "); Listsegmenter.process (sentence, segmode.index); for(Segtoken segtoken:list) {String name=SegToken.word.trim (); if(Name! =NULL "". Equals (name)) {pstmt.setstring (1, Segtoken.word); Pstmt.setstring (2, UUID); Pstmt.setstring (3, sentence); Pstmt.setstring (4, "0"); Pstmt.setstring (5, Segtoken.word);

final Singleton instance = new Singleton ();p rivate Singleton () {};p ublic static Singleton getinstance () {RE turn instance;}} public class MainClass {public static void main (string[] args) {Singleton S1 = singleton.getinstance (); Singleton s2 = singleton.getinstance (), if (S1 = = s2) {System.out.println ("two instances Same");} else {System.out.println ("Two instances are not the same" );}}}The advantage of using static initialization is thread-safe and does not have to be locked to ensu

Thinking in Java 4th Edition source codeinstructions for downloading, installing and testing the source code Download The source code zip file from this link. Create a directory in which to install the code. For these instructions, we'll refer to the This directory as C:\TIJ4\code. Using Winzip or some other zip utility, extract the zip file into the C:\TIJ4\code directory. When you ' re done, you s

E51duplicationinarray {Publ IC Boolean duplicate (int[] arr) {if (arr== null | | arr.length . In the code, although there are one or two repetitions, but each number can be exchanged up to two times to find their own location, so the total time complexity is O (n), in addition, all the operation steps are on the input array, do not need to allocate additional memory, so the space complexity is O (1). Copyright NOTICE: This article for Bo Master original article, without Bo Master permission not

15, because of 1+2+3+4+5=4+5+6=7+8=15, so the result prints out 3 sequential sequence 1--5,4--6,7--8.With previous experience, we also consider using two tree small and big to represent the minimum and maximum values of the sequence respectively. First initialize the small to 1,big to 2. If the sequence from small to big and greater than s, we can remove the smaller value from the sequence, that is, increase the value of the small. If the sequence from small to big and less than S, we can enlar

and update the T2 every time we generate new ugly numbers. For times 3 and 5, the same T3 and T5 are present.Java Code Implementation:public int getuglynumber_solution2 (int index) {if (index Compared with the first idea, the second way of thinking does not need to do any calculation on the integer of the non-ugly number, so the time efficiency is obviously increased. However, it is also necessary to point out that the second algorithm needs an array because it needs to save the ugly numbers t

data container, a hash table is the purpose.To solve this problem, we can define that the hash table's key value (key) is a character, and the value is the number of occurrences of that character. We also need to scan the string two times from the beginning. When a string is scanned for the first time, the number of occurrences in the hash table is added 1 per scan to a character. The next time a scan is made, the number of occurrences of that character can be obtained from the hash table for e

following:Class X { reentrantlock lock = new Reentrantlock (); // ... public void M () { assert lock.getholdcount () = = 0; Lock.lock (); try { //... method body } finally { lock.unlock ();}} }return:The number of times the current thread holds this lock, assuming that the lock has not been persisted by the current thread. Then returns 010. DeadlockA deadlock occurs when two or more thread waits for two or more two locks to be released. and the program'

. * For example, a linked list has 6 nodes, starting from the beginning their values are 1,2,3,4,5,6. The bottom 3rd node of the list is a node with a value of 4 */package swordforoffer;import utils. listnode;/** * @author Jinshuangqi * * August 1, 2015 */public class E15kthnodefromend {public ListNode findkthtotail (listnode Head,int k) {if (head = = NULL | | k Test cases, functional tests (K-nodes in the middle of the list, K-nodes in the head node of the linked list, K-nodes in the tail node

as 16 times put on the basis of the square once on it. and 16 times the square is 8 square. So and so on, we ask for 32 times only need 5 times of the powers: first squared, on the basis of the square of 4, on the basis of 4 to seek 8 square, on the basis of 8 to seek 16, and finally on the basis of 16 on the side of 32.That means we can use the following to find the n-th side of a:This formula is the formula that we discussed when we first used O (LOGN) time to find the Fibonacci sequence, and

JAVA programming ideology (Fourth Edition) Study Notes ---- 11.10 Map, programming ideology ---- 11.10 Previously, we learned the List interface at the Collection level. The List hierarchy is relatively simple. Except for the CoppyOnWriteArrayList class related to multi-thread security, this class is used to learn more when it involves multi-thread-related knowledge, in addition to outdated Vector In norma

The so-called "Narcissus number" refers to a three-digit number, whose numbers are cubic and equal to the number itself.The Java program code is as follows: Public classArithtest { Public Static voidMain (string[] args) {arithtest at=Newarithtest (); //Print all the daffodils numberSystem.out.println ("Narcissus number:"); for(inta=100;a){ BooleanBL =AT.FK (a); if(BL) {System.out.println (a); } } /*Number of Daffodils * the so-ca