error 10054

){ +Memset (G,0,sizeof(g)); -memset (D,0,sizeof(d)); the *scanf"%d",n); $ for(i=1; i){Panax Notoginsengscanf"%d%d",u,v); -g[u][v]++;//here is the input has a heavy edge, so the point of the heavy edge corresponding to the degree of the corresponding plus 1, remember that Hangzhou Electric has a problem to be judged heavy theg[v][u]++; +d[v]++; Ad[u]++; the } + for(i=1; i -; i++){ - if(d[i]%2) Break; $ } $ - if(kase>1) print

Ultraviolet A 10054 The neck.pdf Question: The necklace disperses the front and back ends of each bead. The color is the same as that of the adjacent beads in the necklace. Can the beads be re-bundled with a necklace? Ideas: Solve the problem by comparing the classic Euler's loop question Fleury Algorithm Code: #include #include #includeusing namespace std;#define M 60int n,ans,top,m,t,T;int Edge[M][M],path[M*M],d[M];struct Stack{ int no

Oadrunner default send is sent via sockets (convert HTTP to sockets), while sockets default SSL is SSL2 and SSL3. The HTTPS protocol recorded script will fail the sockets port connection when it is played back in SSL3 version , and the connection will be rejected by the server. Workaround: set Run-time SettingLocate the Internet protocol-preferences-advanced, and tick the "winlnet replay instead of sockets (Windows only)" option.When this option is checked, LR uses the Winlnet engine playback s

Ultraviolet A 10054 The neck.pdf10054 The neck.pdfMy little sister had a beautiful neckw.made of colorful beads. Two successive beads in the neck.pdfShared a common color at their meeting point. The figure below shows a segment of the neck.pdf:But, alas! One day, the neck1_was torn and the beads were all scattered over the floor. My sisterDid her best to recollect all the beads from the floor, but she is not sure whether she was able to collectAll of

--) {init (); Memset (A,0,sizeof(a)); memset (b,0,sizeof(b)); scanf ("%d",N); for(intI=0; i) {scanf ("%s", s); int inch=s[0]-'a'; int out=s[strlen (s)-1]-'a'; a[inch]++; b[ out]++; if(Find (inch)!=find ( out)) P[find (inch)]=find ( out); } inti,j; intflag=1; for(i=0;! a[i]!b[i];i++); for(j=i+1;j -; j + +) { if((a[j]| | B[J]) find (i)! =Find (j)) {Flag=0; Break; } } intCount=0; if(flag) {//printf ("pppp\n"); for(i=0;! a[i]!b[i];i++); for(j=i+1

Topic Link: Click to open the linkTest instructions: n beads, the two halves of each bead are made up of different colors. Only the same color can be joined together, asked whether to form a necklace.Idea: If a bead is regarded as a non-forward edge connecting two vertices, then the subject becomes the existence of the Euler circuit for the non-direction graph. For the graph, if the number of degrees are even and the graph is connected, then there is a Euler loop. Then start at any point and wa

Question: The necklace disperses the front and back ends of each bead. The color is the same as that of the adjacent beads in the necklace. Can the beads be re-bundled with a necklace? Ideas: Solve the problem by comparing the classic Euler's loop question Fleury Algorithm Code: #include Ultraviolet A 10054 the neck.pdf

\Local\Programs\Python\Python35\lib\http\client.py", line 1174, in GetResponseResponse.begin ()File "C:\Users\think\AppData\Local\Programs\Python\Python35\lib\http\client.py", line 282, in beginversion, status, Reason = Self._read_status ()File "C:\Users\think\AppData\Local\Programs\Python\Python35\lib\http\client.py", line 243, in _read_statusline = str (self.fp.readline (_maxline + 1), "iso-8859-1")File "C:\Users\think\AppData\Local\Programs\Python\Python35\lib\socket.py", line 571, in Readint

Pymongo.errors.ConnectionFailure: [Errno 10054] Pymongo.errors.ConnectionFailure: [Errno 10065] Today connection MongoDB suddenly appear this kind of mistake, looked for a half-day also did not find out the problem, Ping IP also appeared several times "general failure" of the display, very depressed, and then found that the QQ is not a successful connection, when the broken link, Then check the router, the lights are normal, simply put the resta

Because of a lot of use of a Web site Urlopen operation, so it will be identified as an attack by the site. Downloads are sometimes no longer allowed. led to Urlopen (), Request.read () had been stuck there. Errno10054 will be thrown at the end. This error is connection reset Bypeer. The legendary remote host has reset this connection. The reason may be that the socket timeout is too long, or it may be after the request =urllib.request.urlopen (URL),

Here we will popularize the knowledge of Euler's loop. Euler's road refers to any point that begins to traverse, and each side passes through exactly once. Such a road is Euler's road. If you can start from any point and return to this point, each

for the first question about Euler's loop, refer to a blog ..... # Include # include using namespace STD; int G [1010] [1010], vis [55]; int count, num [51], colornum, CNT, c; void DFS (int A) {vis [a] = 1; CNT ++; For (INT I = 0; I 0) {colornum

/* Euler's loop * // * the question is that although the AC is a little weak in the data given, there is another situation: you need to determine whether a connected graph is used, for example, if it is better to have two necklaces instead of one,

There are a bunch of scattered beads in the necklace, which may appear repeatedly. If we can connect them into a necklace, we need to meet the requirements of the two beads in each section of the necklace, "The first Bead must be the same as the

I made a water question yesterday, and today it is a relatively water application. The beads of n necklaces are given. There are two colors at both ends of the beads. The adjacent beads on the necklace must match the color to determine whether they

UVA_10054 This question is actually to find an Euler loop and print out the path. You can refer to the code of P112 in Liu rujia's White Book, as long as you make a slight modification on the basis of this Code. Of course, because this topic is an

Loop conditions: 1. The degrees of all points must be an even number. 2. The graph must be connected. 3. The image must be connected at the beginning and end. Idea: First count the number of degrees, and the number of degrees is an even number.

PhenomenonWhen we encode the implementation to request a page, the requested code resembles the following code:HttpWebRequest req = (HttpWebRequest) webrequest.create (strURL);Req. useragent = "MSIE6.0";Req. Method = "GET";HttpWebResponse res = (HttpWebResponse) req. GetResponse ();StreamReader sr = new StreamReader (res. GetResponseStream (), Strencode);strHTML = Sr. ReadToEnd ();Sr. Close ();However, if the page we are requesting is exactly a page with an exception, or a page that does not exi

Topic Link: Http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=105&page=show_ problem&problem=995 Type of topic: Euler loop Topic: My little sister had a beautiful necklace made of colorful beads. Two successive beads

The neck.pdf My little sister had a beautiful neck?made of colorful beads. Two successive beads in the neck?shared a common color at their meeting point. The figbelure ow shows a segment of the neck=: But, alas! One day, the neck1_was torn and the