esp 3250

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Fully analyzes the jump rules between privileged-level and privileged-level code segments in chapter 3 of "writing an operating system by yourself"

the stack. When the RET command is executed, this eip and CS will be popped up from the stack, as shown in: 2. Impact of transition with privilege-level transformation on Stack Stack segments are different under different privileged levels, so each task may be transferred between four privileged levels at most. Therefore, each task requires four stacks. However, we only have one SS and one esp. in case of stack switching, where do we obtain the SS an

IP xfrm configuration example: Use the built-in IPSec Implementation of Linux kernel to manually configure IPSec

1. Topology 192.168.18.101 2. Configure 192.168.18.101 ip xfrm state add src 192.168.18.101 dst 192.168.18.102 proto esp spi 0x00000301 mode tunnel auth md5 0x96358c90783bbfa3d7b196ceabe0536b enc des3_ede 0xf6ddb555acfd9d77b03ea3843f2653255afe8eb5573965dfip xfrm state add src 192.168.18.102 dst 192.168.18.101 proto esp spi 0x00000302 mode tunnel auth md5 0x99358c90783bbfa3d7b196ceabe0536b enc des3_ede 0xf

"Self-written operating system sixth chapter" introduced Minix interrupt processing mode

Absrtact: Looking back, we found that our interrupt handlers were not written elegantly enough. The interrupt response requires three conditions: the interrupt token in the eflags is open, the interrupt mask register does not block the corresponding interrupt, and the EOI flag is set. 1. Modify the clock interrupt handler: G/kernel/kernel.asm 174 Inc DWORD [K_reenter] 175 CMP DWORD [K_reenter], 0 176 jne. 1; re-entry. 1 177 178 mov ESP

Analysis of the template mechanism of C + + compiler function--the essence of function template

Think: Why function templates can be put together with function overloading. How does the C + + compiler provide a mechanism for function templates?Demo 1#include Compile the demo 1 into a compilation file to view:. File "1.cpp". Lcomm __zstl8__ioinit,1,1.def___main;. SCl2;. Type32;. Endef.section. Rdata, "Dr" Lc0:.ascii "x:%d y:%d \12\0" Lc1:.ascii "a:%c b:%c \12\0". def___gxx_personality_sj0;. SCl2;. Type32;. Endef.def__unwind_sjlj_register;. SCl2;. Type32;. Endef.def__unwind_sjlj_unregister;.

Best way to prevent software cracking through distorted transformation Encryption

: * Use JMP to disrupt the code. This is not a new trick, but it still works. * Use JMP to wrap multiple functions together. In this way, the analysts cannot find where the function starts and ends. * Change call. The attacker is extremely sensitive to call, which makes it impossible to find a call. For example, I can change call sub1: Mov eax, offset sub1 + 3Push offset @ 1 sub eax, 3Jmp eax@ 1: * Get rid of ret. The attacker is extremely sensitive to ret, so that he cannot find a ret. For exam

Detailed process of cracking multiple verification and removing functional limitations

exits. If you enter an invalid registration code, you are not prompted to exit directly. We only need to find the fifth place to exit without reason.Double-clickCode:00403B6F |. FF15 30804000 call dword ptr [CopyCode:Call dword ptr [408030]Ctrl + F searchCode:Call dword ptr [408030]A total of 10 locations are found, except the four. There are four more.First look at the last two.Code:00404000. E8 25270000 call 00404005. 8B48 04 mov ecx, dword ptr [eax + 4]00404008. E8 09290000 call 0040400D. 8D

Analysis of New [] and delete [] In vs2013

Compilation mode: DebugCompiling environment: Microsoft Visual Studio ultimate 2013 (12.0.30501.00) Update 2//////////////////////////////////////// //////////////////////////////////////1. New []:C ++ code:Int * lpnum = new int [16]; Assembly code:Push 0x40; new applied space sizeCall XXXXXXXX; call NewAdd ESP, 0x4; _ cdeclMoV dword ptr ss: [EBP-0xD4], eax; returns the return value (address of the applied space) to the temporary variable (guess used

Cisco Easy VPN configuration example

/prot/port): (0.0.0.0/0.0.0.0/0/0) current_peer: required bytes limit 2permit, flags = {origin_is_acl,} # pkts encaps: 26, # pkts encrypt: 26, # pkts digest 26 # pkts decaps: 4, # pkts decrypt: 4, # pkts verify 4 # pkts compressed: 0, # pkts decompressed: 0 # pkts not compressed: 0, # pkts compr. failed: 0, # pkts decompress failed: 0 # send errors 0, # recv errors 0 local crypto endpt.: encryption limit 20.1, remote crypto endpt.: too many connections 2path mtu 1500, media mtu 1500 current outb

Information security technology and application Internet Security protocol

Transport layer (TCP,UDP), so it is transparent to the application.(4) IPSec is transparent to the end user, there is no need to conduct security training for users, to assign a key to each user, or to remove the key when the user leaves the organization.6. Security services provided by IPSec(1) No connection integrity and access control.(2) Identification of the data source.(3) The group that rejects the replay.(4) confidentiality (encryption).(5) Limited amount of traffic confidentiality.7. I

The essence of function call in C language from the perspective of Assembly

Write a blog this afternoon, analysis and analysis of the nature of the function call in C, first we know that the essence of the function in C is a piece of code, but give the code a name, this name is his code of the beginning of the addressThis is also the essence of the function name, in fact, the label in the assembly. Below we will be exposed to some things such as the EIP is what we often say the program counter, as well as EBP and ESP (here ar

Linux and Security second week summary--20135227 Huang

Process 0*/Task[pid].pid = pid;//Initialize process # No. 0Task[pid].state = 0;/*-1 unrunnable, 0 runnable, >0 stopped *///state is runningTask[pid].task_entry = Task[pid].thread.ip = (unsigned long) my_process;//entrance is myprocessTASK[PID].THREAD.SP = (unsigned long) task[pid].stack[kernel_stack_size-1];//stack stack topTask[pid].next = task[pid];//just started it itself, so next also points to its own/*fork more process *///create more processesfor (i=1;i{memcpy (task[i],task[0],sizeof (TP

"Write your own operating system" chapter sixth: from the system kernel to process a ring0>>ring1 (a)

, and it is cumbersome to save each register using push, Intel provides an instruction Pushad to hold the values of all common registers IRET and iretdis the mnemonic for the same opcode. The iretd mnemonic (interrupt return double word) is used to return an interrupt that uses a 32-bit operand size, but most assemblers use the IRET mnemonic interchangeably for both operands. 3. Process scheduling Approximate process PCB:The PCB is used to describe the process, it is independent of the proc

Anti-virus attack and defense: Exploitation of simple program vulnerabilities

that it is behind the fscanf function in the source program, so in the disassembly, its position is also behind the fscanf. It is necessary to briefly describe the call implementation principle. It is divided into two steps. The first step is to push the current instruction location to the stack in the memory, that is, to save the return address (the address saved by the EIP, that is, the next instruction of the call, the second step is to jump to the entrance of the called function. Go to this

What the hell did 7.switch_to do?

bar ~)./* * Saving eflags is important. It switches notonly IOPL between tasks, * It also protects other tasks from NT Leakingthrough sysenter etc. */#defineswitc H_to (prev, Next, last) do { /* * Context-s Witching clobbers All registers, Sowe clobber * them explicitly, via unused outputvariables. * (EAX and EBP are not listed because EBP issaved/restored * explicitly for Wchan access a

Function call conventions and stacks

_ stdcall is the same when it first enters the subfunction. The top of the stack pointed to by ESP is the return address. This is pushed into the stack by the call command. The following are the parameters, the left parameter is on the top, and the right parameter is on the bottom (first on the stack ). As shown in the previous table, the difference between __cdecl and _ stdcall is: __cdecl is the stack occupied by the caller to clean up the paramete

Assembly language basics-framework pointer omitted (FPO)

Frame pointer omission (FPO) FPO is an optimization that compresses or omits the process of creating framework pointers for the function on the stack. This option accelerates function calling because you do not need to create or remove the framework pointer (ESP, EBP. At the same time, it also freed up a register to store frequently used variables. This optimization is available only in the intelcpu architecture. Any call convention that has be

C ++ (class inheritance) 11 from the perspective of Assembly

-4] 00401273 call @ ILT + 0 (Manager ::~ Manager) (00401005) 00401278 pop EDI 00401279 pop ESI 004020.a pop EBX 004010000b add ESP, 44 h 0040da-e cmp ebp, ESP 00401280 call _ chkesp (00408760) 00401285 mov ESP, EBP 00401287 pop EBP We found that the manager structure and analysis structure are also simple. A constructor is constructed

Mutual calls between C and assembly languages

program can return the correct position of the main program and continue execution. For example, call the main function named add assembler module: Main (){...... add (DEST, OP1, OP2, flages );......}. In this example, the main function is de-assembled, and the main function automatically organizes the stack before calling the Add function....Lea 0xfffffffe8 (% EBP), % eax # The first address of the flages array into the stackPush % eaxPushl 0xfffffff8 (% EBP) # OP2 inbound StackPushl 0 xffffff

How the computer Works (based on X86/linux)

memory address for the value of the Register8. variable addressing: Changing the value of a register when indirectly addressing9. The Linux kernel uses the/T assembly format10. EIP registers cannot be directly modified and can only be modified indirectly by special instructions11. The function call stack is superimposed on a logically multiple stack.12. The return value of the function is returned to the upper-level function by default using the EAX register storePre-execution stack, both

It also talks about the impact of inline script location on performance.

Document directory Test Results I read two articles (the impact of inline script location on performance) ,Positioning inline scripts ), I'm a little excited about my regular habits and will be skeptical. To solve the problem, I did a test. The test code is as follows: Test Results Time required for page loading (excluding images), in milliseconds: Put the script behind the style IE6: 3250 3266 3141 3140 3250

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