esp m7

*/Task[pid].next= task[pid];/*the next process in the initial process 0 is process 0*/Then three processes were copied, note Task[i].state =-1; / * Initial state of the process, not enforceable */ Task[i].next = task[i-1].next; Task[i-1].next = task[i]; /* */These two lines of code set the way the process is switched, such as process 0 switching to process 1, and process 1 switching to process 2. /*START process 0 by task[0]*/PID=0; My_current_task= Task[pid]; ASMvolatile( "M

Debug versionESP stack top pointerEBP holds stack pointer Empty program: Int main () { 00411360 push ebp, press into EBP 00411361 mov ebp,esp; EBP = ESP, keep esp, wait for function call to resume, ESP is definitely used in a function call. 00411363 Sub esp,0c0h;

Reference :http://blog.csdn.net/hudashi/article/details/7820338http://shitou7630.blog.163.com/blog/static/32699536201342110155436/Http://www.cnblogs.com/52yixin/archive/2011/06/29/2093634.htmlhttp://blog.csdn.net/mniwc/article/details/7993361Http://www.cnblogs.com/coderzh/archive/2008/12/01/1345053.htmlHttp://blog.sina.com.cn/s/blog_6f6769b50100uhzz.htmlHttps://msdn.microsoft.com/zh-cn/library/ms235286.aspx(Owed by: Spring Night rain Http://blog.csdn.net/chunyexiyu reprint please indicate the so

vtbldiamond (); If (pvtblreal1! = NULL) { Pvtblreal1-> F1 (); Vtblrealb * ptempvtbb = dynamic_cast Ptempvtbb-> F1 (); Delete pvtblreal1; } Vtblrealb * pvtbrealb = new vtbldiamond (); If (pvtbrealb! = NULL) { Ivtbl * pvtbl = dynamic_cast Pvtbl-> F1 (); Delete pvtbrealb; } Return 0; } The execution result is as follows: Let's perform disassembly and debugging to see how the compiler helps us implement it? Let's look at the initialization of an

// Big map. Text: 6f3a2060 sub_6f3a2060 proc near; Code xref: sub_6f38d120 + 67 P. Text: 6f3a2060; sub_6f39bca0 + 67 P.... Text: 6f3a2060. Text: 6f3a2060 var_8 = dword ptr-8. Text: 6f3a2060 var_4 = dword ptr-4. Text: 6f3a2060 arg_0 = dword ptr 4. Text: 6f3a2060 arg_4 = dword ptr 8. Text: 6f3a2060 arg_8 = dword ptr 0ch. Text: 6f3a2060 arg_c = dword ptr 10 h. Text: 6f3a2060. Text: 6f3a2060 sub ESP, 8. Text: 6f3a2063 mov eax, [

---restore content starts---Content one: Experimental report related instructions.Real name Chering HelpOriginal works reproduced please indicate the sourceLessons learned: Linux kernel Analysis MOOC courseLinks:http://mooc.study.163.com/course/USTC-1000029000Virtual Lab ExperimentContent two: Analysis of stack changes during the working process of assembler codeThe analysis is divided into two parts: (The label of the stack address is not aligned, please understand)The first part is the stack t

Explains stack changes for MAIN.C assembler codeThe experiment looks like this:The following analysis begins with the main function (three variable values from top to bottom are 4,7,4):Suppose you start with an empty stack, the initial position is 0,EBP=ESP, and the following is marked with a line number18:esp point to position (1), the value of position (1) is the address of the ESP19: Make EBP point to th

Transfer from http://blog.csdn.net/dongtingzhizi/article/details/6680050In-depth analysis of C + + function call processBrotherWeibo:-bing son of the dongting0. Introduction　　The process of a function call is actually a process of interruption, so how does a function call be implemented in C + +? How to implement parameters in the stack, function jump, protection site, reply to the scene? In this paper, the procedure of function call is analyzed and explained in detail, and it is demonstrated in

the contents of RAM inside pull. You can go to "see the snow" to learn a simple assembler command. 004f3b9c/$ PUSH EBX 004f3b9d |. 83C4 F8 ADD esp,-8 004f3ba0 |. 8BDA MOV Ebx,edx; Data Destination address after decryption 004f3ba2 |. 8bd4 MOV Edx,esp; Data Delivery Destination Address 004f3ba4 |. B9 04000000 MOV ecx,4; The number of passes is 4 004f3ba9 |. E8 12eef8ff call client.004829c0; Pass the 4 valu

the number of records replaced 0X2E, that is, ".", the completion of the processing. The function that handles the incoming domain name in Symdns.sys is at the Symdns.sys base address +0xa76, which allocates enough space in the stack (in fact, the last Shellcode execution is not performed on the stack, but in the non-paged pool). The incoming domain name has a maximum length limit and cannot exceed 0x40 bytes, so i shellcode length is 0x3f (63) bytes per paragraph. After overwriting 532 bytes,

Absrtact: Looking back, we found that our interrupt handlers were not written elegantly enough. The interrupt response requires three conditions: the interrupt token in the eflags is open, the interrupt mask register does not block the corresponding interrupt, and the EOI flag is set. 1. Modify the clock interrupt handler: G/kernel/kernel.asm 174 Inc DWORD [K_reenter] 175 CMP DWORD [K_reenter], 0 176 jne. 1; re-entry. 1 177 178 mov ESP