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H3C-VPN Configuration

H3C-VPN ConfigurationTopology Configure IP addresses[R1] interface e0/1[R1-Ethernet0/1] ip address 192.168.100.254 255.255.255.0[R1] interface e0/0[R1-Ethernet0/0] ip address 192.168.13.1 255.255.255.0[R2] interface e0/1[R2-Ethernet0/1] ip address 192.168.200.254 255.255.255.0[R2] interface e0/0[R2-Ethernet0/0] ip address 192.168.23.2 255.255.255.0[R3] interface e0/0[R3-Ethernet0/0] ip address 192.168.13.3 255.255.255.0[R3] interface e0/1[R3-Ethernet0/1] ip address 192.168.23.3 255.255.255.0PC1

Optimization of memcpy by VC

From: http://blog.codingnow.com/2005/10/vc_memcpy.html In many compilers, memcpy is an intrinsic function, that is, this function is implemented by the compiler. It is easier to be optimized during compilation than the inline function. The compiler can make multiple versions based on whether the memcpy parameter is a constant or a variable to achieve optimal performance. This cannot be done using inline or template. Let's take a look at the optimization of memcpy by VC. (Vc6) Void Fo

Parsing function call conventions

conventions; (PS: although many compilations are listed later, I have made detailed comments. I hope those who are "afraid" of compilationIt can also be smoothly read, and provide some help for those who want to use the Assembly in VC A:Test code: Int X;Int _ cdecl add (int A, int B) {return a + B;} // call convention using _ cdeclInt main (INT argc, char * argv []){X = add (1, 2 );Return 0;} Compiled assembly code in debug mode Public? X @ 3ha; x_ BSS segment? X @ 3ha dd 01 h dup (?) ; X vari

The first week of Linux kernel analysis-how computers work

address in the register EBX and adds 4 points to the memory;A few important assembly instructions Example instruction What it does PUSHL%eax Subl $4,%ESP//stack top pointer minus 4, stack grows down one positionMovl%eax, (%ESP)//The memory location where the value in the EAX is placed on the top of the stack pointer POPL%eax MOVL (%

Linux 3.5.4 system call analysis __linux

, unsigned short seg) { gate->a = (seg A careful analysis of Pack_gate's code will show that it is consistent with the definition in the picture above. Through the above analysis we found that: int $80 the execution of the program to the kernel function System_call. Before we analyze this function, we first introduce the concept of the kernel stack. For each user process, there is a kernel stack and a user stack. Used to store function call parameters, local variables, and other secondary da

Simple kingftp Simplified Chinese version 1.2 Registration Algorithm

it, I couldn't understand it even though it was "kingftp Simplified Chinese version 1.1. Take care of him. This software Icon has not been changed. You can see that it is VC. There is no shell. That's exactly what I want to do. Then I will look at it. After my analysis, this software did not even detect the input. So I entered the Email: B Registration Code: 1 because there is a loop in it, so try to save The string looks for "incorrect registration code. Please register again !". Get: 00414C80

Riijj crackme 10 anniversary algorithm analysis

= OPEN_EXISTING0012FD40 00000080 | Attributes = NORMAL0012fd4400000000 hTemplateFile = NULL0012FD48 00424552 riijjcm1.000000552 Here we know that the key file name is dinner. bin. Create a blank text file, enter some text, name it dinner. bin, and copy it to the folder where Crackme is located.Ctrl + F2 run the program again, and then run the breakpoint bp ReadFile and F9. Stack after disconnection: 0012FD20 0041F9C5/CALL to ReadFile from riijjcm1.0041F9BF0012FD24 00000080 | hFile = 00000080 (w

In-depth analysis of GCC function call stack changes

From: http://stackoverflow.com/questions/2515598/push-ebp-movlesp-ebp When we analyze the att Assembly statements generated by GCC through disassembly, we often find that there are always the following two Assembly statements at the beginning of function calling: Push % EBP Movl % ESP, % EBP At the end of the function call, you can see: Leave RET Here I searched for some instructions on the Internet. tenfy simply translated the corresponding Englis

C function call mechanism and stack frame pointer

programs on the CPU use stacks to support function call operations. Stack is used to pass function parameters, store returned information, temporarily save original register values for recovery, and store local data. The stack used by a single function call operation is called the stack frame structure. The stack frame structure is generally 3-4. The two ends of the stack frame structure are specified by two pointers. The register EBP is usually used as a frame pointer, while

Function call problems

Note:The address of the next instruction to be executed in the EIP register;MoV eax and EBX move the eax content of the register to EBX. The machine instruction is 2 bytes.The operation performed by the Leave command is equivalent to mov EBP, ESP, and pop EBP. The machine command is 1 byte.The operation performed by the RET command is equivalent to pop EIP, and the machine command is 1 byte.The operation performed by the call ADDR command is equivalen

Brief Introduction to NAT penetration technology principles

after NAT, perform Test2. If the STUN Client can receive a response from the STUN Server, it indicates that the STUN Client is Full Cone NAT; otherwise, further testing is required. 1.2.1. Perform Test1 #2. STUN Client compare whether the IP-m1 and IP-m1 #2 are the same, if not the same, it means that the STUN Client is the sort Ric NAT type; otherwise, further testing is required. 1.2.1.1 Test3. If the STUN Client can receive a response from the STUN Server, it indicates that the STUN Client i

Assembly language function call process)

Today I read the chapter on calling functions from the ground up (page 53) in programming, and I have some knowledge about function calls in assembly language. Call this function name when calling a function in assembly language. The function execution process is as follows: Prepare for execution In the masterProgramIn each call to a function, the parameters are first pushed to the stack in reverse order;Then call func_name. Here, call will do two things: first, put the return address of the

Memory protection (i)--"x86 assembly language: From the actual mode to the protection mode" Reading notes 18

; the bounds of the descriptor Lgdt [cs:pgdt+0x7c00]43] in al,0x92 ; The port in the South Bridge chip is al,0000_0010b46 out 0x92,al; open A204748 CLI Interrupt mechanism has not yet worked 4950 mov eax,cr051 or eax,152 mov cr0,eax ; set PE bit 53 54; The following enters the protection mode ... JMP DWORD 0x0010:flush; 16-bit Descriptor Selector Sub: 32-bit offset 56 57 [ bits [] flush:59 mov eax,0x0018 DS,EAX61 mov mov

"Linux kernel Analysis" experiment one

can work with each other and execute the code in step.The current experiment requires disassembly of a simple C program, direct reading of the assembly code to understand the core working mechanism of computer hardware (stored program computer and function call stack) has some help, the following is my experimental process.experimental Environment: Experimental Building1. Create a C file exp.cThe EXP.C code is as follows:2. Enter the following instructions to compile the assembly code:

A brief introduction to cache overflow problems

store, you can connect to it after you execute the command. But for local ret, I'm afraid you are not easy to find its storage address, then the RET space where? Don't worry, we'll go on. # objdump–d OVERFLOW1.O Over3.o:file format elf32-i386 Disassembly of section. Text: 00000000 0:55 Push%EBP 1:89 e5 mov%esp,%ebp 3:83 EC Sub $0x10,%esp 6:c7 FC Movl $0x0,-0x4 (%EBP) D:8B FC Mov-0x4 (%EBP),%

The realization of the variable parameter function of the small secret of C language

type of pointer. In order for Arg to point to the first variable parameter, we use the address of NR with the data type size of NR, which can be achieved by using the following definition.#define VA_START (ARG, start) arg = (va_list) ((char*) (start) + sizeof (start)). By ((char*) (start) + sizeof (start), you can get the address of the first variable parameter and cast it to the va_list type. After the first variable parameter is successfully removed, the next task is to continue to remove t

7.ida-creating a struct body

; void Fun () { g_st.f1 = ten; G_ST.F2 =; G_ST.F3 = +; G_ST.F4 = +; G_st.f5 = 50.0; } The corresponding assembly is: it can be seen that in this disassembly code list, access to struct members does not require any arithmetic calculations, if there is no source code, you simply cannot conclude that the program uses the structure. Push EBP mov EBP, esp mov dword_403018, ten; int f1 = ten mov eax, mov word_ 40301C, Ax; Word F2 =

On the difference between __stdcall and __cdecl _c language

this is the most important point. The __cdecl rule requires the caller to be responsible for the stack's recovery, and in the assembly's perspective, the location of the recovery stack is within the calling function, considering such a C + + code (in VC Debug) Copy Code code as follows: #include void __cdecl func (int param1, int param2, int param3) {int var1 = param1;int var2 = param2;int var3 = PARAM3; printf ("%ld\n", Long (param1));printf ("%ld\n", Long (param2));prin

Firefox memory release Reuse Vulnerability advanced exploitation (Pwn2Own2014, CVE-2014-1512)

MaybeScheduleMemoryPressureEvent()//Enable The"memory-pressure" state If the memory size is less than 0 × 08000000 bytes, the memory-pressure status is automatically activated. When firefox enters this state mode, the constructor of the BumpChunk object will be created: // In "js::detail::BumpChunk * js::LifoAlloc::getOrCreateChunk()" / mozjs.dll 0x00BFEF3E push edi ; Size 0x00BFEF3F call ds:__imp__malloc 0x00BFEF45 add esp, 4 0x00BFEF48 test eax, e

"Turn" profiling of ROP attacks on Android

of data from the Badfile file, but the buffer is only 20 bytes long, so it is possible to find the stack overflow.Here is the compilation code compiled in the context of Cygwin (I have removed some details that are irrelevant to the logical understanding):_main:PUSHL%EBPMOVL%esp,%EBPAndl $-16,%espSubl $32,%espCall ___mainMOVL $LC 0, 4 (%ESP)MOVL $LC 1, (%ESP)Cal

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