extract month from date in sql

system time -the type that needs to be changed , the quantity that needs to be changed, the time and date to changeSelect DATEADD (hh,5, ' 2015-12-12 ')--datediff Calculate the time difference, different different, difference--the type that needs to be changed, the start date, the end time dateSelect DateDiff (MM, ' 2013-12-31 ', ' 2014-1-3 ')DECLARE @startday varchar--you need to add a data type when decl

SQL queries by a value of the date. -- Take 12:56:55 as an Example-- Convert (nvarchar (10), CreateDate, 120) => 2013-12-10-- DATEPART (month, CreateDate) => 12-- DATEPART (year, CreateDate) = gt; 2013 -- This is also possible-- YearSelect datepart (YEAR, '2017-06-08 ')Select datepart (yyyy, '2017-06-08 ')Select datepart (yy, '2017-06-08 ')-- MonthSelect datepar

, see the following blog:Http://www.jb51.net/article/33330.htmNow, I am using this knowledge to solve my problem. The first is to count the reported volume by day, accurate to the daily time limit: CONVERT (varchar (11), ReportTime, 20) that is, yyyy-mm-ddThen the group by problem is solved. The SQL code is:Copy codeThe Code is as follows:Select ReportPerson, CONVERT (varchar (11), ReportTime, 20) as 'reportime', count (*) as reportTotal from PCR_Cons

examples, see the following blog:Http://www.jb51.net/article/33330.htm Now, I am using this knowledge to solve my problem. The first is to count the reported volume by day, accurate to the daily time limit: CONVERT (varchar (11), ReportTime, 20) that is, yyyy-mm-ddThen the group by problem is solved. The SQL code is:Copy codeThe Code is as follows: select ReportPerson, CONVERT (varchar (11), ReportTime, 20) as 'reportime', count (*) as reportTotal fr

The SQL statement in mysql increases the date by one year. Some fields in the mysql table display dates. Due to various needs, it needs to be adjusted one year later. The statement for updating the statement added by one year on the mysql date is as follows: UPDATE table SET date = DATE_ADD(

,-1, GETDATE ()),111)//111 is the style number, (100-114)Query first day of the month Date: Select DATEADD (mm, DATEDIFF (mm,0, GETDATE ()),0) asfirstday Query Last day of the month Date: Select DateAdd (MS,-3, DATEADD (mm, DATEDIFF (M,0, GETDATE ()) +1,0)) asLastday//change-The value of 3 changes accordinglyHow many d

// It is inconvenient to process dates in PHP, for example, to find the month with a different date? What should I do? // File name: date. inc. php3 // before using these two functions, convert the date or date to the timestamp type. // For example: // $ todaymktime (0, 0, 0

SQL query of date fields // Query all the data generated at every daySelect * from table where datepart (HH, Date Field) = 8// Query all records whose dates are 2006-7-6Select *From cstrecordWhere (datepart ([Day], optime) = 6) and (datepart ([year], optime) = 2006) and(Datepart ([month], optime) = 7)1) Remove

Transferred from: http://www.cnblogs.com/zhangq723/archive/2011/02/16/1956152.htmlOne, SQL Server date-time functionsDate and time functions in SQL Server1. Current system date, timeSelect GETDATE ()2. DateAdd returns a new datetime value based on adding a period of time to the specified dateExample: Add 2 days to the

The database tutorial design must note that the Time field is int (11) so that the database is stored in a digital date-time stamp, we can use the Mktime function to find the current date of the timestamp to add and subtract on OK, see the example below One month Copy Code code as follows: $lastMonth = mktime (

Tags: composition highlight char Data time interception Introduction Group SeleIn this article, the date GetDate () is made up of two parts, namely today's date and time of day: Select GetDate ()With Datename () you can get the corresponding year, month, day, and then connect them together: Select Datename (Year,getdate ()) + '-' +datename(

Function Use Northwind Go CREATE FUNCTION Getstar (@ datetime) RETURNS varchar (100) As BEGIN --just one sentence of SQL Return ( --declare @ datetime --set @ = getdate () Select Max (Star) From ( --the constellation, the starting date of the constellation, the day of the constellation start Select ' Capricorn ' as star,1 as [month],1 as [day] UNION ALL select '

The job needs to query the data of this month and this month for ranking. Take a closer look at the date format saved in the database as 2010-02-2314: 2: 3, in this way, I thought that the query method of the database by second would not work. I found a date addition and subtraction