fantage unblocked

#include #include #include #include #include #include #include #include #include #include #include #include using namespace STD;structdata{intU,v;DoubleW;} e[ the];BOOLCMP (data A, data b) {returnA.WDoublex[ -+5],y[ -+5];intn,m,bin[ the];intFind (intx) {intS for(s=x;bin[s]>=0; s=bin[s]); while(s!=x) {intT=BIN[X]; Bin[x]=s; x=t; }returns;}voidUnion (intX1,intX2) {intF1=find (x1), F2=find (x2);intT=BIN[F1]+BIN[F2];if(Bin[f1]>bin[f2]) {bin[f1]=f2; bin[f2]=t; }Else{bin[f2]=f1;

Topic Links: http://acm.hdu.edu.cn/showproblem.php?pid=1874Thinking Analysis: The problem is given a graph, the starting point and the endpoint, the minimum distance from the starting point to the endpoint is required to find out;The shortest-circuit length from the starting point to all other points is calculated using the Dijkstra algorithm, if the shortest-circuit length is int_max, indicating that no path is connected from the starting point to the point;The code is as follows:#include #incl

Analysis: template problem, direct template can be.#include HDU ACM 1874 unblocked Project continued

Three levels of violence have been wrong for a long time ...It is a tragedy to think of the non-direction graph as a graph.#include #include #include #include #include #include #include #include #include #include #include #include #include using namespace STD;Const intn= $+5;Const intinf=100000;intG[n][n],n,d[n][n];voidFloyd () {intI,j,k; for(i=0; i for(j=0; jif(I==J) d[i][j]=0;Else if(g[i][j]==0) D[i][j]=inf;ElseD[I][J]=G[I][J];//printf ("%d%d:%d\n", I,j,d[i][j]);} for(k=0; k for(i=0; i for(j=0

Finding or thinking is the most important to understand the code of thought is easy to understand.#include nyoj608 unblocked project and check set

other n-1. - { - intbig=Long_max; - for(intj=1; j//The least right edge, and the corresponding point + { - if(!vis[j] low[j]big) + { Apos=J; atbig=Low[j]; - } - } -Ans+=big;//Long Statistical path -vis[pos]=1; - for(intj=1; j//update weights to each point in if(!vis[j]) low[j]=min (low[j],v[pos][j]); - } to returnans; + } - the * $ Panax Notoginseng intMain () - { theFreopen ("Input.txt","R

http://acm.hdu.edu.cn/showproblem.php?pid=1232and check Set#include hdu-1232 unblocked Project

= x, e[k].y = y, e[k].d =D; atk++; - } - - intGet_head (intx) - { - while(x! = fa[x]) x=Fa[x]; in returnx; - } to + BOOLUnion (intXinty) - { the intfa_x =get_head (x); * intFa_y =Get_head (y); $ if(Fa_x! =fa_y) {Panax NotoginsengFa[fa_x] =fa_y; - return true; the } + return false; A } the + intMain () - { $ //freopen ("a.in", "R", stdin); $ intN, M, a, B, D; - while(SCANF ("%d", N), N) - { theK =0; -m = N (n1) /2;Wuyi the for(int

continue to smooth the project Time limit:2000/1000 MS (java/others) Memory limit:32768/32768 K (java/others)Total submission (s): 16631 Accepted Submission (s): 7149The goal of the problem Description provincial government's "unblocked project" is to enable road traffic between any of the two villages in the province (but not necessarily directly connected roads, as long as they can be reached indirectly via highways). A table of urban roads is avail

PermissionsMaintityDetermine if the network is unblocked plus permissions if (networkutil.isnetavailable (mainactivity.this)) {//Net unblocked //Start request data }else{ Toast.maketext (Mainactivity.this, "Currently no network Check network permissions", 0). Show (); 　　Networkutilpublic class Networkutil {public static Boolean isnetavailable (context cont

Permissions:"android.permission.INTERNET"/> "android.permission.ACCESS_NETWORK_STATE"/> Mainactivitydetermine if the network is unblocked plus permissions if (networkutil.isnetavailable (mainactivity). This) {// network unblocked//Start request data }else{toast.maketext (mainactivity.") currently no network Check network permissions 0). Show (); NetworkutilPublicClass Networkutil {pu

HDU1863-unblocked Project: http://acm.hdu.edu.cn/showproblem.php?pid=1863This question I use and check the method at noon AC once, afternoon learned prim. Another pose, one more time = =!And the method of checking the set: http://blog.csdn.net/p_rogrammer/article/details/47979073Code:#include Copyright NOTICE: This article for Bo Master original article, without Bo Master permission not reproduced. Prim minimum spanning tree algorithm for HDU1863-

unblocked Works continuedTime limit:1000MS Memory Limit:32768KB 64bit IO Format:%i64d %i64 U DescriptionA province has been building a lot of roads since the implementation of many years of smooth engineering projects. But the road is not good, every time from one town to another town, there are many ways to choose, and some programmes are more than others to walk the distance is much shorter. This makes pedestrians very troubled.Now that you know

Unblocked Works continuedTime limit:3000/1000 MS (java/others) Memory limit:32768/32768 K (java/others)Total submission (s): 41849 Accepted Submission (s): 15463Problem description a province since the implementation of many years of smooth engineering plans, finally built a lot of roads. But the road is not good, every time from one town to another town, there are many ways to choose, and some programmes are more than others to walk the distance is m

Unblocked Works continuedTime limit:3000/1000 MS (java/others) Memory limit:32768/32768 K (java/others)Total submission (s): 36543 Accepted Submission (s): 13423Problem description a province since the implementation of many years of smooth engineering plans, finally built a lot of roads. But the road is not good, every time from one town to another town, there are many ways to choose, and some programmes are more than others to walk the distance is

Unblocked Project Continuation time limit:3000/1000ms (Java/other) Memory limit:32768/32768k (Java/other) total submission (s): Accepted s Ubmission (s): 37Problem description A province has finally built many roads since it has implemented many years of smooth engineering projects. But the road is not good, every time from one town to another town, there are many ways to choose, and some programmes are more than others to walk the distance is much sh

Unblocked Works continuedTime limit:3000/1000 MS (java/others) Memory limit:32768/32768 K (java/others)Total submission (s): 36946 Accepted Submission (s): 13591Problem description a province since the implementation of many years of smooth engineering plans, finally built a lot of roads. But the road is not good, every time from one town to another town, there are many ways to choose, and some programmes are more than others to walk the distance is m

Unblocked Works continuedTime limit:3000/1000 MS (java/others) Memory limit:32768/32768 K (java/others)Total submission (s): 53806 Accepted Submission (s): 20092Problem description a province since the implementation of many years of smooth engineering plans, finally built a lot of roads. But the road is not good, every time from one town to another town, there are many ways to choose, and some programmes are more than others to walk the distance is m

Smooth Project ContinuationTime limit:3000/1000 MS (java/others) Memory limit:32768/32768 K (java/others)Total submission (s): 28356 Accepted Submission (s): 10275Problem DescriptionA province has built up a lot of roads since it implemented a project plan that has been unblocked for many years. Just a lot of road is not good, every time from a town to a town, there are many ways to choose the path, and some of the programmes are more than some of the

It took 1 days to write a script to detect whether an IP network is unblocked, but to detect whether the network is unblocked is easy to implement, but it is not good to add some restrictions. Copy Code code as follows: #!/bin/bash #################################################################################### #本脚本放于异机, the use of timed tasks to detect whether the network 192.168.10.231, i