feiyue 03

:/var/ftp:/sbin/nologin Polkitd:x:999:997:user for Polkitd:/:/sbin/nologin [[EMAILN bsp;protected] sed]# sed ' 1,18 ' d test.txt bacula:x:133:133:bacula Backup system:/var/spool/bacula:/sbin/nologin Apache:x:48:48:apache:/usr/share/httpd:/sbin/nologin [[emailprotected] sed]# head-3 test.txt|sed-r ' s/ roo/aaa/' Aaat:x:0:0:root:/root:/bin/bash bin:x:1:1:bin:/bin:/sbin/nologin Daemon:x:2:2:daemon:/sbin:/sbin/nologin [[emailprotected ] sed]# head-3 test.txt|sed-r ' s/roo/aaa/g ' Aaat:x:0:0:a

Tags: blog change log local image lips ref reference runOne, change the default maven configuration for EclipseWindow->preferenceSelect Local Maven Directoryhas been determined afterSecond, change the MAVEN default settingsWindow->preferenceSelect the settings under the directory you built in the previous chapter.Third, create a new MAVEN projectAnd thenProjects that were successfully built:Run the project:Next:For example, we want to compile this directory, then in goals fill in:compile, corres

1. Start the system and select the second option and press the E key to enter edit mode2. Edit add at end of Linux16/vmlinuzinit=/sysroot/bin/sh3. Press CTRL +x to start the shell4. Mount the file system in writable mode:mount+o remount，rw /sysroot5. Change the rootchroot /sysroot6. Run and passwd root follow the prompts to change the password7. If you have previously enabled the system selinux , you must run the following command, or the system will not start normally:touch /.autorelabel8. exit

.fbtermrc里设置input-method=fcitx-fbtermAutomatically run scripts on boot创建一个脚本文件： *** .sh编写内容，开头一定要是#!/bin/sh 或者 #!/usr/bin/fish 等表示在哪个shell下执行命令然后下面必须有LSB描述信息：### BEGIN INIT INFO# Provides: *** .sh# Required-Start: $syslog $remote_fs $network# Required-Stop: $syslog $remote_fs $network# Default-Start: 2 3 4 5# Default-Stop: 0 1 6# Short-Description: starts the *** .sh daemon# Description: starts *** .sh using start-stop-daemon### END INIT INFO执行如下指令：sudo chmod 755 ***

间是“主从”关系，如果B被删除了，A仍然存在（因为两个是不同的文件），但指向的是一个无效的链接。硬链接(hard link)：文件A是文件B的硬链接，则A的目录项中的inode节点号与B的目录项中的inode节点号相同，即一个inode节点对应两个不同的文件名，两个文件名指向同一个文件，A和B对文件系统来说是完全平等的。如果删除了其中一个，对另外一个没有影响。每增加一个文件名，inode节点上的链接数增加一，每删除一个对应的文件名，inode节点上的链接数减一，直到为0，inode节点和对应的数据块被回收Description of the use limit:硬链接：a：不能对目录创建硬链接，原因有几种，最重要的是：文件系统不能存在链接环（目录创建时的”..”除外，这个系统可以识别出来）,存在环的后果会导致例如文件遍历等操作的混乱(du，pwd等命令的运作原理就是基于文件硬链接，顺便一提，ls -l结果的第二列也是文件的硬链接数，即inode节点的链接数)b：不能对不同的文件系统创建硬链接,即两个文件名要在相同的文件系统下。c：不能对不存在的文件创建硬链接，由原理即可知原因。软链接：

1. What are the commands with R parameters now?Cp-rRm-rfLs-r2. Colleagues said, open the Computer XXX Service Web interface, which of the several ways you think you can try to know?Ifconfig--Find IPPs-ef|grep xxx--Find PIDNetstat-nlp|grep PID--Find portPS can also view the path address of the XXX service, locate the configuration file, view the configuration file3.MV and CP who fastMV Fast4. Personal environment variable file where, general what file, what command to view, how to take effect~/.b

If the built MAVEN project local repository does not have a corresponding dependency package, then it will go to the Nexus to download, then if the Nexus does not have this dependency package, go back to the Remote central repository download dependency, the Nexus download to the local MAVEN library for project reference.650) this.width=650; "src=" Https://s2.51cto.com/wyfs02/M00/8F/5F/wKioL1jcetqx8g7rAADmTRxSj4E202.png "title=" 1111. PNG "alt=" Wkiol1jcetqx8g7raadmtrxsj4e202.png "/>Installation

add: New change/rename: Modified deprecate: Obsolete. It is likely to be deleted later. Remove: Delete the The last version increases were:libavcodec:2015-08-28 libavdevice:2015-08-28 libavfilter:2015-08-28 libavform at:2015-08-28 libavresample:2015-08-28 libpostproc:2015-08-28 libswresample:2015-08-28 libswscale:2015-08-28 L Ibavutil:2015-08-28 API changes, most recent First:2017-03-31-9033e8723c-lavu 55.57.100-spherical.h Add a V_spherical_pr

Objective-C learning 03-inheritance, objective-c03 inheritanceOutline:Basic concepts of InheritanceCustom Initialization MethodConstructor MethodOverride description 1. inherit Basic Concepts The objects in the program are the same as those of "human". Gao fushuai inherits his parents and naturally owns all the resources of his parents, subclass inherits all attributes and methods of the parent class, except for the parent class. When defining a new

How do I turn the 2007-04-24-03:19:32 format time into a timestamp? Echo strtotime ("2007-04-24 03:19:32"); echo Time ("2007-04-20 03:19:32"); I can't do this. The first one has no output, and the second becomes the timestamp of the current time. ------Solution-------------------- $datetime =split ("", "2007-04-24 03

Document directory Version 1.4.2 _ 03 of the JVM not suitable for this product. version1.5 or geeater is required Version 1.4.2 _ 03 of the JVM not suitable for this product. version1.5 or geeater is required suddenly reported this error when eclipse was started this morning. The translation is: "The JVM virtual machine version 1.42 _ 03 is no longer suitable

# Calls the Native C ++ class Library. You only need to verify that the C # language can manipulate the memory. Then, you can use the C # language to call the Native C ++ Library function. The experiment has proved that the memory can be operated by C # using the unsafe and fixed keywords, And the C # function can be called by using the Import C ++ Dll and C. However, when calling the Native C ++ library, there will be some new problems due to the complexity of the actual data structure. 4Refer

Time: 2016-03-19-13:24:23 Saturday Title Number: [2016-03-19][uvalive][3027][corporative Network] The main topic: given n nodes, I u v means the parent node of the U node is set to V, the distance is |u-v|%1000,e u to ask u to the root node distance, given a number of I-E operations, output the corresponding answer Analysis: Take right and check the set Method: D[MAXN] Maintenance to the par

Interview preparation series 03 ---- Summary of Binary Tree questions in the interview Interview preparation series 03 ---- Summary of Binary Tree questions in the interview This article is the first article in the interview preparation series. The binary tree is the same as the linked list. First, we should think of recursion. Therefore, we recommend that you use recursion and non-recursion to complete eac

Recently I was learning androidui design, found a UI menu interface open Source code example, follow the steps to import the project, run when the console results reported the following error:[2016-04-03 20:38:02-dex Loader] Unable to execute Dex:multiple Dex files define Lcn/w/song/widget/navigation/rollnavigationbar$navigationbarlistener;[2016-04-03 20:38:02-usewidgetdemo] Conversion to Dalvik format fail

This article is a course series document for the Dubbo-based Distributed System Architecture video tutorial, for more information about the course, please follow: http://www.roncoo.comDubbo Video Tutorial--Basic--No. 03 Section--zookeeper Registration Center installation detailed steps (single node)installation Dubbo Registration Center (Zookeeper-3.4.6)Dubbo Recommended Use Zookeeper as the registry for the service. Registration Center Server (192.1

Time: 2016-03-27-22:37:37 Sunday Title number: [2016-03-27][hdu][1260][tickets] Problems encountered: Minute number, divided by 60 after the model T/60% 60 #include #include using namespace std; typedef long long LL; const int maxk = 2000 + 10; int s[maxk],d[maxk]; int dp[maxk]; int main(){ int t; scanf("%d",t); while(t--){

Time: 2016-03-27-14:51:35 Sunday Title Number: [2016-03-27][hdu][1257][minimum interception system] Analysis: greedy, whenever unable to intercept the addition of an interception system, you can find that each interception system interception of the height of the comparison and the order of occurrence. That the second system is always higher than the first one. #include using namespa

Time: 2016-03-29-15:53:01 Tuesday Title number: [2016-03-29][hdu][2859][phalanx] Analysis: dp[i][j] means (i,j) as the lower left corner #include #include using namespace std; const int maxn = 1000 + 10; char a[maxn][maxn]; int dp[maxn][maxn],ans,n; void func(int x,int y){ int maxl = min(x,n - y); int i; for ( i = 0 i Maxl ;++ i

Time: 2016-03-22-20:13:36 Tuesday Title number: [2016-03-22][479][a][expression] Title: Given three integers, with a symbol (parentheses or operators) between 3 numbers, the maximum value after the output operation Analysis: $ab-a+b = (A-1) (b-1)-1, when A\GEQ2 and B \geq 2 o'clock ABC > (A+B) C $ So when numbers are greater than 2, multiplication is bigger than additio