first birthday poster

The method of taking the poj3320 ruler is basically the same as that of the question, but the range of the question is 2 ^ 31.Sort the position of each bead.Maintain a pointer for each type of beads to indicate which beads of this type are used.Therefore, the ruler acquisition method is optimized by the heap. Each time the smallest value is taken from the heap, the head pointer of the ruler acquisition method is moved backward.Then a position (pointer ++) is taken from the back of each bead (whi

No idea ...... However, because each cake has the same area and must be cut into two halves each time, the area of each half is a multiple of the area of each cake. Calculate the number of cut-down cakes, calculate the cut place, divide X and Y, and perform recursive search. Code: #include Bzoj 1024 Happy Birthday scoi2009

wishes me a happy birthday on the text message. The first blessing was received when I did not fully open my eyes. It was so touched, so happy, and so good... I want to sleep for a while... Liu will be here in an hour. I also took off tomorrow's holiday. I went back to get the two packages of the old two and Xue to the North Station and checked them to Suzhou. Then Liu will go to Suzhou on Saturday. I heard that he will not be back for the Chinese Ne

This is a training reference for the solution of small petition violenceTopic Link http://acm.hust.edu.cn/vjudge/problem/19398Thinking of solving problemsA, b from-500 enumeration to 500Note that there is no point on the lineCode#include Const intMaxLen =101; typedefstructPoint {intx, y;} Point; Point Setp[maxlen];voidSearch (intN) { intA, B; for(a=- -; a -; a++) { for(b=- -; b -; b++) { intCount1 =0; intCount2 =0; for(intI=0; i2*n; i++) { intres = a*setp[i

Transmission DoorThinking of solving problemsIt is better to think, with a queue, and then put all the points together in order, in turn queued. Each time you check the type of the team head element is the current queue element type, yes, the words have been \ (pop\), each update answer can be.Code#include Luogu P2564 [SCOI2009] Birthday Gift (queue + simulation)

I guess you have heard that the house hides two elves, I will not tell you, you now in the Chamber of Secrets, hidden 6 numbers, these 6 numbers, in a certain order, enter the following JS program, will get the ultimate answer tips, good luck!JS Program:Now I will give the first hint, the output of this program is:Happy Birthday, wife!

How to develop small functions for iOS (pop-up birthday keyboard is used as an example) 1 # import "ViewController. h "2 3 @ interface ViewController ()

Here we are mainly entangled in the leap year. If there is no birthday, it must be the February 29 of the leap year, right? If it is a leap year this year or 18 years later, we should consider whether it was before or after February 29. # Include

July 1 is Ding's birthday. It was originally planned well. In the afternoon, I took a photo of him. In the evening, I asked my family to have a meal and then I went to see Transformers 2. (Of course, there is no ding ). Who knows that the plan really cannot keep up with the changes? Well, Ding ding suddenly got a little hot in the morning-37.8. It was normal before going home at noon. I was planning to proceed according to the original plan, who knows

I had been using netbeans for more then 1 year. formerly, I had used the Eclipse IDE for development. but, since I had a try for netbeans, I surprised, I feel the netbeans IDE is more for humanbings! This year is netbeans 10th birthday, let's celebrate it! Using netbeans ide I use netbeans ide under Ubuntu Linux for javase/javaee developing. because netbeans UI is based on Java Standard -- swing, so I can mimize netbeans IDE's UI with look feel. t

This is a complete Android Application I wrote, but it is not complete yet. There are still many other functions that have not been added, but yesterday was my girlfriend's birthday, so I gave it to him. This is the first app I used to study Android for half a month. "music player "!It took two days to complete the production process, from conception to completion. There were still many imperfections, the UI was ugly, and the layout was messy! The mai

Deep Search.However, it is possible to cut, so every situation has to be considered.#include #include #include #include #define INF 10000007using namespace Std;int x, y;int n;Double Solve (double x,double y,int N){if (n==1) return Max (x/y,y/x);Else{Double Rt=inf;for (int i=1;i{Rt=min (Rt,max (Solve (x*i/n,y,i), Solve (x* (n-i)/n,y,n-i));Rt=min (Rt,max (Solve (x,y*i/n,i), Solve (x,y* (n-i)/n,n-i));}return RT;}}int main (){scanf ("%d%d%d", x,y,n);printf ("%.6lf\n", Solve (x,y,n));return 0;}Bzoj 1

]; the build (i); -now[i]:=J; in End; them:=K; the fori:=1 toN Do About begin thelc[i]:=heap[1].c; theln[i]:=heap[1].x; theSwap (heap[1],heap[m]); + Dec (m); -Update1); thenow[lc[i]]:=Next[now[lc[i]];Bayi ifNow[lc[i]]0 Then the begin the Inc (M); -heap[m].x:=Q[now[lc[i]]; - build (m); the End; the End; theh:=1; theFillchar (sum,sizeof (sum),0); -t:=1; theans:=Maxlongint; thesum[lc[1]]:=1; the fori:=2 toN Do94 begin the Inc (Sum[lc[i]); the ifsum[lc[i]]=1 ThenInc

]);}voidUpdateintP, LL Val,intLintRintRT) { if(L = =R) {Sum[rt]=Val; return ; } intm = l+r>>1; if(pm) Update (p, Val, Lson); ElseUpdate (P, Val, Rson); Pushup (RT);} ll query (intLintRintLintRintRT) { if(rL)return 0; if(lr) {returnSum[rt]; } intm = l+r>>1; LL ret=0; if(lm) Ret=query (L, R, Lson); if(r>m) Ret=Max (ret, query (L, R, Rson)); returnret;}intMain () {intN, R, H; CIN>>N; for(inti =0; i) {scanf ("%d%d", r, h); V[i]= B[i] = 1ll*r*r*h; } sort (b, B+N); intnum = unique (b, b+n

A year of Sichuan province election.Enumerate each bead and look for all the kinds of beads in front of it and its maximum distance (this distance must include all the beads) and then update the answer.For convenience, we sort the beads and form the list of links (also in reverse order).However, this water problem ziliuziliu still not very good to think out. I don't know what's going on. This problem is actually quite simple ah.#include #include #include #include #define INF 0X7FFFFFFF#define MA

"Topic link"http://www.lydsy.com/JudgeOnline/problem.php?id=1037Test instructionsA row of n male m female, the number of men and women to meet any number of consecutive segments of the difference does not exceed K.IdeasDpSet f[a][b][c][d] to indicate a male m female, the maximum number of male and female students is C, the maximum number of girls and boys is the program number of D, there is a transfer equation:F[a+1][b][c+1][max (d-1,0)]F[a][b+1][max (c-1,0)][d+1]Too hot-Code1#include 2#include

()) Update (Rson,l,ans); ElseUpdate (Lson,l,ans); A[R]. Max=Max (A[lson]. Max,a[rson]. Max);}intMain () {intN; while(SCANF ("%d", n)! =EOF) { Doubler,h; Met (b,0); Met (S,0); for(intI=0; i) {scanf ("%LF%LF",r,h); S[i]=b[i]=pi*r*r*h; } sort (B,b+N); intLen=unique (B,b+n)-b; Buildtree (1,0, len-1); Doublesum=0; for(intI=0; i) { intPos=lower_bound (B,b+len,s[i])-B;///Find your subscript DoubleAns=qurry (1,0, pos-1) +s[i];///find the maximum value beforeUpd

Topic Links:This topic is very good, has difficulty, can do well to do more;#include Copyright NOTICE: This article for Bo Master original article, without Bo Master permission not reproduced. poj-1190-Birthday cake-dfs (Deep Search)-enumeration-Multiple pruning

This year's Arbor Day (March 12, 2012), Xiao Ming and his uncle and his small friends to plant trees together.Rest, Xiao Ming's classmate asked his uncle how old, his uncle said: "I said a topic, see you who first guess!" ”"The day I was born together to spell a 8-digit number (month, day less than two before 0) just can be today's year, month, day evenly divisible! ”He thought, adding: "Give another hint, I was born in June." ”According to this information, please help Xiao Ming to calculate hi

.... is not completely self-made out of the topic, although very violent, as if the scope for [-500,500], but the question is why mustn ' t in , I also idiot with a point to the distance of the line to find the number, judging is in the straight line or should be directly brought into the OK!!! See is greater than 0 or less than 0, but through this I know the point to the straight line distance formula, before to forget, D = ABS (AX+BY+C)/sqrt (a*a+b*b)Paste the code: Copyright NOTICE: This art