frog vector

Title: A frog can jump up to 1 steps at a time, or jump up to level 2. Ask the frog to jump on an n-level step with a total number of hops. My train of thought: At first my idea was to think of this as a mathematical problem, n=i*1+k*2 all the I and k that might satisfy the formula. Then in pairs I and k do permutation combinations. It is clear that the range of I should be 0public int Jumpfloor (int target

There are n lotus leaves. On the top of a convex polygon, there is a little frog standing at the point of the 1 lotus leaf. The little frog can jump from the lotus leaf to any other lotus leaves, and the coordinates of N points are given. The path traversed by the frog does not overlap.It is easy to prove. Draw a graph and use the sum of the two sides of the tria

very important thing. They did not know the characteristics of the other party, nor agreed on the specific location of the meeting. However, frogs are optimistic. They think that as long as they keep jumping in a certain direction, they will always meet each other. However, unless the two frogs jump to the same point at the same time, they will never be able to meet each other. To help the two optimistic frogs, you are asked to write a program to determine whether the two frogs can meet and whe

Function wawa_recordxml (SQL)'*************************'Function: converts A recordset to a string in XML format.'Return value: String'Parameter: SQL (string)'Provider: Frog Prince (Tianji Forum)'*************************Dim RS, strxmlStrxml = ""Strxml = strxml "Strxml = strxml "Set rs = server. Createobject ("ADODB. recordset ")Rs. Open SQL, Conn, 1, 1If not (Rs. EOF and Rs. bof) thenDo while not Rs. EOFDim IFor I = 0 to Rs. Fields. Count-1Strxml =

P1933"poetize3" mung Bean Frog's home time: 1000ms/Space: 131072kib/java class name: Main background with the new version of Baidu Space online, blog pet mung Bean Frog completed its mission, to find its new destination. The description gives a direction-free graph with a starting point of 1 ending at N, each edge having a length, and starting from the beginning to reach all points, all points can also reach the end point. The mung bean

"Title description"Give a direction-free graph with a starting point of 1 ending to n, each side having a length, and starting from the beginning to reach all points, all points can also reach the end point. The mung bean frog starts from the starting point and goes to the end.At each vertex, if there is a road where K leaves the point, the mung bean Frog can choose any route to leave the point, and the pro

ProblemA frog can jump up to 1 steps at a time, or jump up to level 2. Ask the frog to jump on an n-level step with a total number of hops.IdeasWhen N=1, there is only one method of jumping, and f (1) = 1, when n=2, there are two kinds of jumping, and f (2) = 2, when n=3, you can jump from the n=1 directly to the n=3, can also jump from n=2 directly to N=3, and F (3) =f (1) +f (2) =3 ..., so you can use rec

"Title description"The trail of the frog through the farmland is a straight line, the farmland plants are in the farmland of the two-dimensional coordinate system of the integer lattice point, if a frog through the farmland, that is, along a straight line through the farmland, then the straight line through the whole number of the lattice point of the plant will be destroyed, now give the location of all th

Title: Hdoj 5037 Frog Ask: Always clever frog, each can the length of L, Hecoin for M, drink center some land, it will choose to jump as few times as possible, now God can go to drink inside the land (as a point), let the frog jump the most times, the maximum number of times. Analysis: 1: First of all, if you add a distance greater than (l+1), then God will giv

topic Description (1) A frog can jump up to 1 steps at a time, or jump up to level 2. How many jumps are there in total for the frog to jump up the N-level steps? Topic Description (2) A frog can jump up to 1 steps at a time, or jump up to level 2 ... It can also jump up n levels. How many jumps are there in total for the fr