frog vector

The frog jumping game is a seemingly simple intelligent game. The game task is to change the positions of frogs on both sides of the game. Click the frog and it will jump to a vacant stone closest to it. Yesgame interface: Crop + crop/crop + zcrHye62yMvRy/ejrNXStb3Su7j2veK + zU9LoaO0 + crop + CjxwcmUgY2xhc3M9 "brush: java;"> pos = [0 for x in range (7)] for I in range (3): pos [I] =-1for I in range (3): pos

Problem Description: A frog can jump up to 1 steps at a time, can also jump up to level 2 ... It can also jump up n levels. How many jumps are there in total for the frog to jump up the N-level steps? Topic Analysis: 1 here the F (n) represents the n steps there is a 1,2,... N-order number of hops. 2 n = 1 o'clock, only 1 kinds of jumps, f (1) = 1 3 N = 2 o'clock, there will be two jumps, a 1-order or 2-ord

[Luogu 1516] frog appointment Two years ago, I worked with my junior high school teammates to simulate the issues I 've learned, and I 've done it together with TLE; A year ago, my teammate's blog was used as an example. I copied the questions that I had taken to the playground; I finally learned the exgcd before I found out that it was a question that was easily cut out... Lighting city in the rain to sleep, has been Xiao for

Problem descriptionjack and Jill play a game called "leap frog" in which they alternate turns jumping over each other. both Jack and Jill can jump a maximum horizontal distance of 10 units in any single jump. you are given a list of valid positions x1, x2 ,..., Xn where Jack or Jill may stand. jill initially starts at position X1, Jack initially starts at position X2, and their goal is to reach position XN. determine the minimum number of jumps needed

Problem descriptionjack and Jill play a game called "leap frog" in which they alternate turns jumping over each other. both Jack and Jill can jump a maximum horizontal distance of 10 units in any single jump. you are given a list of valid positions x1, x2 ,..., Xn where Jack or Jill may stand. jill initially starts at position X1, Jack initially starts at position X2, and their goal is to reach position XN. determine the minimum number of jumps needed

The author of the idea of synthesis is very good, with blue bubbles to show the texture of the surface, and then through the deformation of the bubble lines are affixed to the various components of the frog, the overall very natural lifelike. Final effect 1, open the bubble picture, in the toolbar, select the Elliptical Marquee tool. 2, Style: fixed ratio. 3, select your bubble, click and drag fr

Core tip: This flash example made a lovely "little Frog Clock" animation, using the basic graphics tools such as ellipses, rectangles, lines and arbitrary deformation, simple and easy to understand, suitable for practice. This flash example made a lovely "little Frog Clock" animation, using the basic graphics tools such as ellipses, rectangles, lines and arbitrary deformation, easy to understand, suitable

Green Bean frog series light pulling games This game, also known as "lamp pulling", is very damaging to brain cells. When all LEON laugh, you win. Baidu, there will be a lot of web pages that play this game online. One of the following is provided, with the help of the lazy _ ^Http://game.163.com/game2002/editor/edit_jianzhi/060602/060602_635067.html If you need my help, please download the following compressed package, which contains the C ++ prog

Frog recommendation: a simple example of using web services to transmit Dataset First of all, I declare that I am a beginner in Asp.net. If I write something rough, you are welcome to instruct the experts to correct it. In this example, I wrote it for time without doing too much optimization, for example, adding the Web service to the local application cache, and adding secure identity authentication. The emergence of Web Services is undoubtedly a goo

Rom Introduction This rom has removed the official recovery. After the phone is flushed, the recovery of the mobile phone will not be replaced. It is easy to fl the ROM into other Rom. 1. Maintain the development version of WiFi and network optimization. 2. Standby RF optimization. And power-saving code optimization. Mobile phones consume less power. Longer standby time 3. The camera is normal. High focus speed. Better imaging effect 4. Optimize the GPS configuration file. Effectively impro

Output1 1 3) 1 1The following:The idea is very good a problem ... first of all, consider how to get this K-far point out, think of a half-day completely no idea, ah ah ah ah ah. later read the solution to know to maintain a [l,l+k] of the interval, the answer must be one of the left and right (too god%%%%)then the center point in the move, if A[i]-a[l]>a[r+1]-a[i], then the interval can be one, because r+1 this point is better than L. The next approach to the final position is also very ingenio

DescriptionFrom one point to the point where he is at the distance from (k\), ask to jump from each point to (m\) times to reach that point.SolQueue + Multiply.Keep the number of elements in the queue is \ (k\), the previous sweep is not difficult to find that the left and right endpoints are monotonous.To jump \ (m\) times is multiplied, roll the array.Code/************************************************************** problem:2093 User:beiyu language:c++ Result : Accepted time:7256 ms memory:2

#include dp~ frog across the river (hrbust1186)

It's a simple question, but there's a bunch of disgusting boundaries.After gouging out the disgusting border:Suppose we know that the cyclic section on both sides is B1,B2Where H is the first time to reach the target is A1,A2And know that for the answer TT=a1+b1*t1=a2+b2*t2You can enumerate T1 to see if there is a viable solution.And because the LCM (B1,B2) began to circulate.and B1*b2So we enumerate the range of T1 in [0,mod]If there is no solution within this range, there must be no solution#i

// Frog recommendation: Example of positive expression in C #// I used C # To solve the last problem. paste it first.// First put all Code Copy and save as arr_reg.cs// Then compile the following code into the console using CSC Program Then you can see the result. The compilation command is as follows:// CSC/T: EXE arr_reg.csUsing system;Using system. Text. regularexpressions;Public class regextest {Public static void wawa_reg (){String [] arr = new s

Frog recommended: demonstrate CSS style sheet priority It can be seen that the effectiveness of the label style is the lowest, followed by the pseudo class defined, The next step is to add a pseudo class with a redefinition tag (similar to h2.myclass {color: Blue}). The highest level is the CSS style defined by id -->

Original formula AX + by = c => Ax1 + by1 = gcd (A, B ); If A, B, and C are any integers and D = gcd (a, B), a group of solutions for ax1 + by1 = D is (x1, Y1 ), when C is a multiple of gcd (a, B), one of them is (x1 * C/D, Y1 * C/D); C is not gcd (A, B) no solution A frog appointment is an example. According to the question, it is easy to name the equation: (x + MS)-(Y + NS) = K * l; (k = 1... n) deformation to the Extended Euclidean FormulaYo

To improve the performance of the homepage, whenever the homepage needs to call the database to display data, it first tries to call data from the cache,If no data is available in the cache, enable the database to retrieve the record set. To synchronize the data displayed on the page with the database within a certain period of time,We set the cache expiration time to 30 seconds.Statement: The cache management class comes from Forum 7.0.Note: it is best not to directly cache stateful objects and

/* - The output in vc++6.0 is: Wu ----------------------------------- - About Please enter number of steps (positive integer): 1 $ There are 1 kinds of jumping methods for 1 steps. - do you want to continue? (y/y): Y - Please enter number of steps (positive integer): 2 - There are 2 kinds of jumping methods for 2 steps. A do you want to continue? (y/y): Y + Please enter number of steps (Positive integer): 3 the There are 3 kinds of jumping methods for 3 steps. - do you want to continue? (y/

like it, really can accept ah. But the thought of life's various, will retreat. Maybe that's what everyone says about the age of 30. At that time, the overtime energy is gone, how to do it. Vigilance vigilance, can not fall into this too dull work, must have their own planning, always think today than yesterday actually improved. Can not become the frog inside the warm water, until the discovery of temperature rise, has no ability to jump out to save