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Smart phone rankings, flagship mobile phones under ten Operating Systems

Today, the smartphone field is highly competitive, and major mobile phone manufacturers also have their own "dedicated secrets" in terms of smart phones ". As the leader in the mobile phone industry, Nokia's Symbian systems have a large share. However, the advantage of note is declining, and Nokia is worried about the future situation. This is directly related to the impact of other smart systems. The biggest threat is Mac OS, Windows Mobile, and Android. In addition, the old BlackBerry OS and P

[Cf739e] Gosha is hunting (wqs dual set wqs dual)

balls, Represented by \ (g2_ I \)The second method used to capture the number of balls. In fact, \ (DP \) is also quite simple. There are \ (4 \) cases: No capturing ball is used. \ (F_ I = F _ {I-1}, g1_ I = G1 _ {I-1}, g2_ I = G2 _ {I-1 }\). Use the first method to capture the ball. \ (F_ I = F _ {I-1} + s1_i-C1, g1_ I = G1 _ {I-1} + 1, g2_ I = G2 _ {I-1 }\) Use the second method to capture the ball.

Zoj 3088 Easter holidays (spfa)

ratio shoshould be rounded to the closest 1/1000th. if there are two possibilities, then the rounding is away from zero (e.g ., 1.9812 and 1.9806 become 1.981, 3.1335 becomes 3.134, and 3.1345 becomes 3.135 ). if there are multiple journeys that prior to rounding are equally scary, print an arbitrary one. Sample Input 15 4 31 3 122 3 63 4 95 4 94 5 125 1 124 2 18 Sample output 4 5 1 3 40.875 Question: The maximum ratio of the elevator time to the skiing time. Use spfa to find the time at each

Hibernate lazy -- delayed Loading

The Hibernate lazy policy can be used in:* * * * Lazy concept: it is created only when this object is actually used. For hibernate, SQL is issued only when this object is actually used. Hibernate supports the lazy policy only when the session is enabled. 1 Group. HBM. xml Http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd> Test cases: Public class lazytest extends testcase { Public void testload1 (){Session session = NULL;Transaction TA = NULL;Try {Session = hibernateutil. getsession ()

[Called the animal school-fan outan] teaches you to use HTC magic, which is white and slippery, without money.

This article is transferred from "Android Network" [Called the animal school-fan outan] teaches you to use HTC magic, which is white and slippery, without money. Download(62.6 KB) It's called the beast, who recently fell in love with the android simulator. Every day, they basically have to turn on the simulator to play!However, I am tired of seeing the red simulator and calling it a beast for a long time!I remember seeing a nice white G2 simul

Comparison between the Bayer mode and the X3 Mode

algorithm is doubled, but the accuracy is higher.For video monitoring systems, the accuracy is not too high. simply use the R or B solution. The following describes the complexity:For graphs:R1G1R4 G4 R G2 r2G3R3For the intermediate point R, it needs to insert G and B, B is not discussed, mainly discusses g, it has four points around G1, G2, G3, G4.(G1 + G3)/2 -------------- if | R1-R3 | G (R) = (

Summary of the days for calculating the difference between two dates in JAVA

result; } The method in ElapseTime is: The code is as follows:Copy code Public int getDays (GregorianCalendar g1, GregorianCalendar g2 ){Int elapsed = 0;GregorianCalendar gc1, gc2;If (g2.after (g1 )){Gc2 = (GregorianCalendar) g2.clone ();Gc1 = (GregorianCalendar) g1.clone ();} Else {Gc2 = (GregorianCalendar) g1.clone ();Gc1 = (GregorianCalendar)

Gradient fill color Algorithm

Method 1:Bilinear interpolation method 1. Calculate the zoom ratio first. Bl = 2/W... 2 is the source image width (because there are only two colors)... W is the enlarged width.2. Start the loop, from 1 to w the target width. If the loop variable is I..., use n = I * BL.3. extract the fractional part of N and store it in Variable P .. then synthesize the color. The target color r = R1 * (1-p) + R2 * p g = G1 * (1-p) + G2 * p B = b1 * (1-p) + B2 * p ..

Linux-User rights and Disk Management

Linux-User rights and Disk Management1. User Group and Rights managementA, add 4 users u1 U2 U3 U4. And see if the profile is increased successfully. Disable U2, test effect, restart U2, test effect;B, delete the account U1 and home directory.C, the password to modify U3: MashenD, add the group G1,G2, the user U2 join G2 Group, and the G1 group deleted.E, use the root user to create a new file AA, and use t

IE6 pisition:fixed does not work, floating window does not roll with the screen solution

));} 3, to solve the position:fixed layer flashing method Adding in CSS style sheets The code is as follows Copy Code *html{Background-image:url (About:blank); background-attachment:fixed;} Property We can also use JS to solve some problems. code is as follows copy code G1 = (Getclientheight () –o.height)/2;//1000px total element height 300px g1=350px g2 = G1 /Getcl

Day6--python Data types

= {} #n =m.fromkeys (l,123) #赋值所有的一个默认值为123n =dict.fromkeys (l,124) #上面也可以这么写也是成立的print (n) Prints the result:Zip:zip is a culvert that merges two lists into a dictionary (by chance), #如果有两个字典的话, treats L1 as key, L2 as VALUEH1 = [' A ', ' B ', ' C ', ' d ']g2 = [1,2,3,4]dict_test = Zip (h1,g2) print (dict_test) results are:Update: Merge Dictionary # If there are two dictionaries, take L1 as key, take L2 a

Accidentally removed the Android ringtones solution

Since the Android platform has launched a resource manager that can get the highest root of the system, many G2 have tried the software to remove some of the components from the Android system with their phones, but some users often accidentally delete some system components, take the ringtone components. After deletion, there is no support for cell phone ringtones and SMS ringtones. So what about deleting the Android ringtone component by mistake? T

python-Implementation of Level 3 menu (homework lesson)

1 #Task:2 #Show Level 3 menu3 #Level 1 Menu # shows 3 cities + 1 Beijing 2 Shanghai 3 Guangzhou4 #Level 2 Menu #显示 Select 1 Beijing = B1 B2 B35 #Level 2 Menu #显示 select 2 Shanghai = S1 S2 S36 #Level 2 Menu #显示 Select 3 Guangzhou = G1 G2 G37 8 #Level 3 Menu #显示 Choose B1 = b1_1 b1_2 b1_39 #Level 3 Menu #显示 Choose B2 = B2_1 b2_2 b2_3Ten #Level 3 Menu #显示 Choose B3 = B3_1 b3_2 b3_3 One A #Level 3 Menu #显示 Choose S1 = s1_1 s1_2 s1_3 - #Level 3 Menu #显示 C

Bzoj 3594: [Scoi2014] Uncle Fang's maize field DP Tree Array optimization

510#defineMAXK 53#defineVAL1 MAXV-2#endif#defineINF 0x3f3f3f3f#defineDeal (X-y) if ((x) intDP[MAXK];//11000*550==6050000intA[MAXN];voidAdd_val (int*tarr,intPosintValintll) {POS++; while(posll) {Tarr[pos]=Max (tarr[pos],val); POS+=pos (-POS); }}intQry_val (int*tarr,intPOS) {POS++; intres=-INF; while(POS) {res=Max (Res,tarr[pos]); POS-=pos (-POS); } returnRes;}intG1[MAXK][MAXV];intG2[MAXK+MAXV][MAXV];//5600*5100==25000000intMain () {Freopen ("Input.txt","R", stdin); intn,m; inti,j,k; sca

Java implementation Gobang Small game _java

Boolean canplay=true; Save display information String message= "black side First"; Save up to how much time (sec) int maxtime = 0; To do the countdown thread class thread t = new thread (this); Save the remaining time of the black and white side int blacktime = 0; int whitetime = 0; Save the display letter for the remaining time of the two partiesCoupon String Blackmessage = "Unrestricted"; String whitemessage = "Unrestricted"; @SuppressWarnings ("deprecation") public Op

PAT Problem Report

locations for the "gas station," are supposed to give the best recom Mendation. If There are more than one solution, output the "one with" smallest average to all distance. If Such a solution is still isn't unique, output the one with the smallest index number. Input Specification: Each input file contains one test case. For each case, the the 4 positive integers:n ( Then K lines Follow, each describes a road in the formatP1 P2 DistWhere P1 and P2 are the two ends of a road which can be either

26th max Flow (modifying)

path is offset26.2-4According to the definition of anti-symmetry and residual networkC|f (u,v) + c|f (v,u)= C (U,v)-F (u,v) + C (v,u)-F (v,u)= C (u,v) + C (v,u)26.2-5Based on the conservation of flow26.2-622.2-7Seems to be a very obvious thing.26.2-8I don't know what the title means, I hate the proof question.26.2-9To construct such a weighted graph G2,The vertices of the G2 are the same as the G. If there

Several ways to summarize the range of values in SQL

Several ways to summarize the range of values in SQLIn statistical work, we often encounter a group summary of a number of value ranges, such asAssuming that the ID value is 1~20000, grouped according to the group distance of 5000, we have to find out 5000 of the following including 5000,5000 above 10000 including 10000,10000 and above 15000 including 15000 below, 15000 or more 20000 below includes 20000.Can be obtained by using the built-in rounding function Ceil and division operations.Select

MySQL sub-query slow problem

Tags: style color io ar sp data div on problemWhen you use the Explain tool to view the execution plan of an SQL statement, you should be aware of the Select_type field when "DEPENDENT subquery" appears. You have fallen into the MySQL sub-query slow "pit" ... Let's look at a concrete exampleThere is such a query statement:select Gid,count (ID) as COUNT from shop_goods G1 WHERE status =0 and GID in (SELECT gid from Shop_goods G2 WH ERE SID in (1519066

"Strong Unicom Component Indent" "Search" bzoj2208 [Jsoi2010] Connectivity number

Two times Dfs shrinks, and then n times DFS bursts.1#include 2#include 3#include 4 using namespacestd;5 #defineN 20016vectorint>G[n],rg[n],vs,g2[n];7typedef vectorint>:: iterator ITER;8 Chars[n+1][n+1];9 intCmp[n],sum,cnt[n],ans,n;Ten BOOLVis[n]; One voidDfsintU) A { -vis[u]=1; - for(ITER it=g[u].begin (); It!=g[u].end (); it++) the if(!vis[*it]) -DFS (*it); - Vs.push_back (U); - } + voidDFS2 (intU) - { +vis[u]=1; Acmp[u]=sum; atcnt[sum]++;

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