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"Learning Notes" Hibernate annotations (y2-1-9)

) { This. Players =players; }}@Entity @table Public classPlayer {@Id @GeneratedValuePrivateInteger pid; PrivateString pname; @ManyToMany (Cascade= Cascadetype.all, Mappedby = "Players") PrivatesetNewHashset(); PublicInteger getpid () {returnpid; } Public voidsetpid (Integer pid) { This. PID =pid; } PublicString Getpname () {returnpname; } Public voidsetpname (String pname) { This. pname =pname; } PublicSetGetgames () {returnGames ; } Public voidSetgames (setGames

Python recursion and object-oriented first knowledge and programming thought

external # G1.nick = ' Bush lun ' def attack (Self,enemy): # print ('----------> ', Self.nick) #g1. Nick print ('%s attack%s ') % (Self.nick,enemy)) G1=garen (' Bush lun ') #类实例化, class Garen trigger call _init_ #Garen. _init_ (self, ' NB ') g2=garen (' Liu Xia ') print (G1.nick) G1.attack (' Alex ') #执行结果: Bush Warren attack AlexSelf refers to himself.Note: Instantiation of a class automatically triggers execution of the _INIT_ func

[Linux] Unzip the tar.gz file, unzip some files

, you can use the following methods to view the contents of a compressed file: TAR–TZVF *.tar.gz (because I am a. tar file at this time, so use TAR-TVF), and see that you can actually view the contents of a compressed file Use the following methods to decompress: Unzip a single file: TAR–ZXVF *.tar.gz/test/filename.txt Unzip multiple files: TAR–ZXVF *.tar.gz/test/filenam* Unzip to the specified directory: TAR–ZXVF *.tar.gz/text/filename.txt–c/opt/targetfolder The above commands cannot be execut

Excel Financial Application Example: Calculate salary by professional title

The employee's salary is to be adjusted this month, and the manager demands a salary increase according to each person's title. Specific requirements: The primary title for the beginning of this month plus 20 Yuan, the title for the middle of this month plus 50 yuan, the title of the senior 70 yuan this month. But because the company has too many people, adding one by one is not only troublesome but also error prone. After some groping, I found two ways to efficiently solve the problem of salar

Unity API Parsing (3)--gameobject class

system.collections;public class createprimitive_ts:monobehaviour{void Start () {// Use the Gameobject.createprimitive method to create gameobject gameobject g1 = gameobject.createprimitive (Primitivetype.sphere); G1.name = "G1"; G1.tag = "Sphere_tag"; Add the component G1 using AddComponent (classname:string). AddComponent ("Springjoint"); Add the component G1 using AddComponent (Componenttype:type). AddComponent (typeof (Guitexture)); G1.transform.posi

A Java sample that can be printed on a stylus printer

Code:import Java.awt.Color;import Java.awt.Font;import java.awt.Graphics;import Java.awt.Graphics2D;import Java.awt.print.PageFormat;import Java.awt.print.Paper;import java.awt.print.Printable;import java.awt.print.PrinterException;import Java.awt.print.PrinterJob; Public classPrintImplementsPrintable {Private intPageSize;//Total pages printed Private Doublepaperw=0;//Printed paper width Private DoublePaperh=0;//Printed paper height //implementation of Java.awt.print.Printable interface p

Python XML grooming

. Subelement (University, "D4") D4.text = "Seniors"High_school = ET. Subelement (School, "{Http://www.ehaomiao.com}high_school", attrib={"Time": "3"}) G1 = ET. Subelement (High_school, "G1") G1.text = "Freshman"G2 = ET. Subelement (High_school, "G2") G2.text = "Sophomore" g3 = ET. Subelement (High_school, "G3" ) G3.text = "Senior" Middle_school = ET. Subelement

Securing network isolation in security groups

reachable, even if an increase in the allowed access ACL does not work. Network isolation is limited to instances within the current group (NIC) assuming that the current security group is G1, the network in the group is set to "quarantine", vm1 and vm2 belong to G1,VM2 and vm3 within the group of G2,G2, then VM1 and vm2 networks are unreachable, but the network between VM2 and VM3 can be reached. To bette

Troubleshooting for MPLS LDP

. This column more highlights: http://www.bianceng.cn/Network/basis/ Notice here that the g2/0 interface, the g2/0 of R2, is the LDP, and there are two extremely important parameters, XMit and recv. XMit said that from g2/0 successfully sent the LDP hello out. Recv indicates that the port was successfully received by the interface g1/0 of the end R3 sent bac

Definitions of Lvalue and rvalue in C and C + +

{   int a;   int operator()() { return a; }   int operator+(const fun f) { return a+=f.a; }   int operator-(const fun f) { return a-f.a; }  };  fun f, g1, g2;  f() = 1;  // 这里 f() 是 lvalue! 所以, 这个赋值是正确的!  g1 + g2 = 1;// 这里 g1+g2 是 lvalue! 所以, 这个赋值是正确的!  g1 - g2 = 1;// 这里 g1-g2

A case of MySQL sub-query optimization

written in the previous words: In slow-scan optimization 1 and 2 have repeatedly emphasized the importance of explain, but sometimes the naked eye can not see how the explain Results to guide optimization, this time also need some other basic knowledge of the support, and even need to understand the MySQL implementation principle, such as sub-query slow-scan optimization . When you see the "DEPENDENT subquery" in the Select_type field in the SQL execution plan, you must be mentally

Java Learning Notes (ii) Occasional updates

Java language Drawing PackageCn.witksy.dev;ImportJavax.imageio.ImageIO;Importjava.awt.*;ImportJava.awt.image.BufferedImage;ImportJava.io.File;Importjava.io.IOException;/*** author:alfred * CREATED:2015/5/7*/ Public classMain { Public voidrun () {bufferedimage bufferedimage=NewBufferedImage (100,50, Bufferedimage.type_int_argb); Graphics2D G2=Bufferedimage.creategraphics (); G2.setcolor (color.red);

Java Learning Java 2D Graphics drawing

g) {graphics2d g2= (graphics2d) g;double leftx=100;double topy=100;double width =200;double height=150; Rectangle2D rect=new rectangle2d.double (leftx,topy,width,height); G2.draw (rect); Ellipse2d ellipse=new ellipse2d.double (); Ellipse.setframe (rect); G2.draw (ellipse); G2.draw (New Line2d.double (LeftX, topy,width

A strong connected component-kosaraju algorithm for graphs

Enter a forward graph to calculate the number of strong connected components of each node, and the number of strong connected components of the output1#include 2#include 3#include 4 using namespacestd;5 Const intmaxn=1024x768;6 structedge{7 intGo,next;8 };9 intVis[maxn],count=0, BOOK[MAXN];TenVectorg,g2; Onevectorint>S; A intEND[MAXN],END2[MAXN]; - voidAddint from,intTo) {Edge e;e.go=to;e.next=end[ from]; G.push_back (e); end[ from]=g.size ()-1;}

Java 2048 and java2048

. setBounds (430, 40,120, 30); backJB. setFocusable (false); backJB. setBorderPainted (false); backJB. setFocusPainted (false); backJB. setContentAreaFilled (false); this. add (startJB); this. add (backJB); setVisible (true); GameListener gl = new GameListener (this, arry, jl2, startJB, backJB); addKeyListener (gl); startJB. addActionListener (gl); backJB. addActionListener (gl );} Draw squares and numbers: The drawing of squares and numbers is also based on the drawing of rectangles of the canv

Why Is Inheritance harmful in Java?

development, flexibility is advocated. You have to write your code in a certain way, so that the newly discovered requirements can be easily merged into the existing code as much as possible. It is better than implementing the features you may need. You only need to implement the features you need clearly, and be moderately tolerant of changes. Without such flexible and parallel development, it would be impossible. Inteface programming is the core of flexible structure. To explain why, let's

NetEase Development Engineer Programming problem comparison weight Java

Compare weightXiao Ming accompanied Xiao Red to see the diamonds, they from a bunch of diamonds randomly extracted two and compare their weight. The weight of these diamonds varies. After they had been comparing for some time, they had a fancy for two diamonds G1 and G2. Now, please judge which of the two diamonds is heavier according to the information you have previously compared.Given the number of two diamonds g1,

Why is it harmful for Java to inherit most of them?

as possible.It is better than implementing the features you may need. You only need to implement the features you need clearly, and be moderately tolerant of changes. Without such flexible and parallel development, it would be impossible.Inteface programming is the core of flexible structure. To explain why, let's take a look at what happens when they are used. Consider the following code:F (){Jsonlist list = new jsonlist ();//...G (list );}G (sort list){List. add (...);

"Turn" Elementary number theory--Huangen, index and its application

be "amplified" several times after X, soEna | XSecond, the original rootSet A and n are integers of coprime, when the order of a-modulo n is? (n), A is called the original root of N.How do you understand it? We calculate the sequence of the power of a, the first time we get 1, we get a complete follow-up link. We've already said that, huh? (n) must be a multiple of (the order of a modulo n). What if the length of the circular section happens to be? (n) (the length of the circular section has re

The closure of Lua

http://blog.csdn.net/ym012/article/details/7208750Functions can still be defined in the body of the function. Assuming that the function F2 is defined in the function F1, then it is called F2 as an inline (inner) function of F1 and F1 as F2 (enclosing) functionInline functions can access all the local variables that the outsourced function has created, which is called the word legal realm (lexical scoping) function F1 (n) --functions parameter is also local variable

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