g502 weight

01 Backpack ...-----------------------------------------------------------------------#include #include #include #include #define REP (i, n) for (int i = 0; i #define CLR (x, C) memset (x, C, sizeof (x)) using namespace std;const int MAXN = 45000 + 5;bool d[MAXN];int main () {freopen ("test.in", "R", stdin);CLR (d, 0);d[0] = true;int v, n;Cin >> v >> N;Rep (i, N) {int x;scanf ("%d", x);For (int j = v-x; J >= 0; j--) if (d[j])d[j + x] = true; }int ans = 0;Rep (i, v + 1) if (d[i])ans = max (ans,

code:nsarray *arr = @[@111,@222,@111]; nsset *set = [nsset setwitharray: arr]; NSLog(@ "%@", [set allobjects]); The output is:2013-05-21 12:06:26.508 Test1[4547:c07] (111,222)Sort of the de-weightMany times you may encounter elements that need to be removed from Nsarray, using a number of methods.The most convenient and fast is the nsset. But nsset, sometimes the order of the array elementsUpset. Then another method is as follows:nsmutablearray *categoryarray = [[nsmutablearray al

What is the weight of a website? I understand it as the popularity of a website, just like the official website in our real world, like asp.net/c#. Generally, the weight of a website (including a webpage) is related to the following parameters:Whether or not to include authoritative open directories, such as dmoz and Yahoo DirectoriesRanking of core Keywords of websites or webpages in search enginesHow many

Determine if a person's weight is a standard weightThe formula is: Boys: weight-height +100=±3 girls: weight-height +110=±3Console.WriteLine ("Please enter gender");String a = Console.ReadLine ();Console.WriteLine ("Please Enter your weight");Double b = convert.todouble (Console.ReadLine ());Console.WriteLine ("Please

CSS style weight and css weight InLine style> Internal style sheet> External style sheet)Exception: if an external style table is referenced under an internal style table, an external style table> An internal style table; 1. The Inline style table weight is 1000;2. The weight of the ID selector is 100;3. The

Find the list resolution file include/arc.listview.class.php find that the collation does not follow the weight sort of judgment, so the modifier is added to the collation code is as follows copy code //sort $ordersql = '; if ($orderby = "Senddate" | | $orderby = = " Id ' { $ordersql = ' ORDER by arc.id $orderWay '; } Else if ($orderby = = "Hot" | | $orderb y== "click" { $ordersql = "ORDER by Arc.click $or

1 DOCTYPE HTML>2 HTMLLang= "en">3 Head>4 MetaCharSet= "UTF-8">5 title>Go heavytitle>6 Head>7 Body>8 Scripttype= "Text/javascript">9 /*array de-weight*/Ten functionQuchong (arr) { One varLen=arr.length; A Arr.sort (); - for(varI=Len-1; I>0; I--){ - if(Arr[i]==Arr[i-1]){ the Arr.splice (i,1); - } - } - returnarr; + } - vara= ["a","a",

Translated from: http://www.zccode.com/forum.php?mod=viewthreadtid=637extra=page%3D1NET Fox 6603 Special Database Weight Loss effect script (18G into 300M) is as follows:Copy script statements to SQL Server new query, execute, clear redundant log/** Database Super Weight loss, 18G can become 300M.*/--Truncate The log by changing the database recovery model to simple.Use QptreasuredbALTER DATABASE Qptreasure

Divide 101 coins into three heaps, 50 for the two, and the other 1. 50 heap items, if the weight is equal.It indicates that the counterfeit currency is the sameTake a real coin and compare it with the counterfeit coin to determine which coin is heavier. If the weight is not equal, it means that the remaining coin is true, and then there is a false one in the two piles of 50, and the balance is not balan

Site those unhealthy factors cause weight reduction, then need to pay attention to the points to do.1, there is a security alliance to risk the site, you need to apply for the closureAfter being detected by the security alliance that the site is hacked, the search results are indicated as risky and blacklisted. Because Baidu search results are access to security Alliance credit data, so the first step should go to the security alliance to apply for th

! =-1; i =Edge[i].next) {v=edge[i].v; if(v = = FA !)flag) {Flag=1; Continue; }//go to the heavy side and skip if there are heavy edges if(!Dfn[v]) {Tarjan (V, u); Low[u]=min (Low[u], low[v]); if(Dfn[u] Low[v]) Min=min (min, edge[i].c); } ElseLow[u]=min (Low[u], dfn[v]); }}intMain () {inti, U, V, c, K; while(SCANF ("%d%d", m, n), M +N) {Init (); K=0; while(n--) {scanf ("%d%d%d", u, v, c); Addedge (U, V, c); Addedge (V, U, c); } Min=INF; for(i =1; I )

Start from and traverse all vertices. pay the price when traversing the edge. do not pay for the side in an SCC. Minimum cost. Point Reduction of a directed graph (no need to create a new graph, N "= 50000, the creation times out), traversing the edge. If it is not in an SCC, use an array to update the minimum edge weight of the connected component... Chat, 1a, haha... # Include