Price B
A supplier supports his medium-disk vendors with an attitude of "unchanged" for price fluctuations on the market. But is this really the best price strategy? Are there any worries?
English text
A: You know, I think it's smart to stay with the same low price. Your MERs will be pleased.B: We think that the basis price shocould stay low. It's wrong to raise prices just because market demand is going up fast.A: Right. With such competitive
, we either take a rest, by just using the old decision at I-1, *or buy At/before i-1, then sell at I . *so we get the following formula: *buy[i] = Math.max (Buy[i-1], sell[i-2]-prices[i]); *sell[i] = Math.max (Sell[i-1], buy[i-1] + prices[i]);*/ Public intMAXPROFIT5 (int[] prices) { if(Prices
1.ref:http://blog.csdn.net/linhuanmars/article/details/23164149The difference is that it can be traded infinitely many times (of course we know that the deal will not exceed n-1 times, that is, every day we sell first and buy it). Since there is no limit to the number of transactions, we can see that we can get the maximum profit if we trade for a two-day spread greater than 0. So the algorithm is actually adding up all the spreads greater than 0 can be, very simple. So only a single scan is req
Topic:Say you has an array for which the i-th element is the price of a given-stock on day I.If you were-permitted-to-complete at most one transaction (ie, buy one and sell one share of the stock), design an AL Gorithm to find the maximum profit.Analysis: One-dimensional dynamic programming (hard counting is OK)Dp[i] is the maximum profit for the [0,1,2...i] interval, the one-dimensional dynamic programming equation for the problem is as followsDP[I+1] = Max{dp[i],
Title Description:Say you has an array for which the i-th element is the price of a given-stock on day I.Design an algorithm to find the maximum profit. You could complete as many transactions as (ie, buy one and sell one share of the stock multiple times). However, engage in multiple transactions for the same time (ie, you must sell the stock before you buy again).Problem Solving Ideas:Greedy algorithm: The profit is updated as long as the current value is smaller than the previous value.1 clas
arrays. In the related array, you can associate each variable value with any keyword or index.
1 Initializing related arrays
The code shown below can create a related array with the product name as the keyword and the price as the value:
$prices = Array (' Tires ' =>100, ' oil ' =>10, ' Spark plugs ' =>4);
The symbol between the keyword and the value is just a greater than sign with the equals sign.
2 Accessing array elements
Similarly, you can use v
Php traversal array foreacheach () list () method summary
Foreach ($ array as $ value) {// $ array indicates the array to be traversed. $ value indicates the pointer pointing to the current value of the array. as assigns a value.
Code to executed;
}
The foreach statement can also obtain the key name of the array, as shown below:
Foreach ($ array as $ key => $ value ){
Echo $ key "-" $ value ."";
}
2. the echo () function eac
Personally, this is a relatively difficult DP problem. This link posts a typical DP solution to it. Need some time to get how it works.The code is rewritten as follows.1 classSolution {2 Public:3 intMaxprofit (vectorint>prices) {4 intn = prices.size (), num =2;5 if(N 1)return 0;6vectorint> > dp (num +1, vectorint> (n,0));7 for(intK =1; K ) {8 inttemp = dp[k-1][0]-prices
Reuters, Beijing, November 30-there were many conferences in Beijing at the end of the year. in addition to reporters, we need several financiers. each of them has millions or even tens of millions of dollars in their hands, looking for investment directions. behind them is the world's major fund and investment banks that want to get a share of China's economic growth. if you have an enterprise or a piece of land, do not be tempted by their high prices
, BufferedInputStream improves the performance by buffering arrays, provides a readLine method to read the entire row for expansion. The figure below gives you a better understanding of the decorator in the IO stream:
In this figure, byte streams are listed, and hidden streams are similar. However, the decorative stream adds more classes in IO, which may sometimes cause us troubles. If you have to say so, this is also a "disadvantage ";
Write your own example
After learning the examples in the
Original title address: https://oj.leetcode.com/problems/best-time-to-buy-and-sell-stock-iii/Test instructionsSay you has an array for which the i-th element is the price of a given-stock on day I.Design an algorithm to find the maximum profit. You are in most of the transactions.Note:Engage in multiple transactions on the same time (ie, you must sell the stock before you buy again).The idea of solving problems: the "low buy and sell high" rule in the trading market (buy lower and sell)Only two
Php array required
Foreach ($ prices as $ key => $ value)
Echo $ key. '=>'. $ value .'';
The following code uses the each () structure to print the content of the $ prices array:
While ($ element = each ($ prices ))
{
Echo $ element ['key'];
Echo '-';
Echo $ element ['value'];
Ech
it is behind a buddy's state machine solution compared to make sense. The above solution is based on a day with only one operation, or buy or sell or hold. There are also some understandings that can be bought and sold on the day, listed in the discuss. It seems that the topic really must be specified very carefully, otherwise it is difficult to read.Time Complexity-o (n), Space complexity-o (n) Public classSolution { Public intMaxprofit (int[] prices
Topic:Say you has an array for which the i-th element is the price of a given-stock on day I.Design an algorithm to find the maximum profit. You could complete as many transactions as (ie, buy one and sell one share of the stock multiple times). However, engage in multiple transactions for the same time (ie, you must sell the stock before you buy again).ExercisesThe simple way is that once the next day's price is higher than the previous day, it is sold the next days before buying. The code is a
Topic:Say you has an array for which the i-th element is the price of a given-stock on day I.Design an algorithm to find the maximum profit. You are in most of the transactions.Note:Engage in multiple transactions on the same time (ie, you must sell the stock before you buy again).The following:According to the requirements of the title, up to two times to buy and sell stocks, and the hands can not have 2 stocks, is not two consecutive buy operations.Therefore, two trades must be distributed wi
(repost) Bollinger bands Boll usage Bollinger Bands are one of the most frequently used technical indicators in the stock market, reflecting the volatility of stock prices. In the mountain version of the software indicator Chart of the Bollinger bands are composed of three, the upper white Line (UP) is the resistance line, the lower Yellow Line (down) is the support line, the middle of the Pink Line (MB) is the average line . When the stock price con
Say you has an array for which the i-th element is the price of a given-stock on day I.If you were-permitted-to-complete at most one transaction (ie, buy one and sell one share of the stock), design an AL Gorithm to find the maximum profit.Analyse:dp[i] = max (dp[i-1], prices[i]-lowest[0,..., i-1]).Runtime:8ms.1 classSolution {2 Public:3 intMaxprofit (vectorint>prices) {4 Const intn =prices.siz
.
Shan Tao Ren: supply is not urgent years ago, the price fell slightly, the current market Shan Tao Ren net goods 60-65 yuan.
Bugu fat: New products are coming to the market, prices are slippery, and the price for unified products is 7-RMB. as new products continue to go public, there is room for decline in the market outlook.
Snake bed: the supply of goods is moving smoothly, the price is strong, unified goods 20 yuan up and down, the net goods 2
Reading: Worries about global economic growth and the general decline in risky assets have put oil prices under pressure and crude futures prices fell in Thursday. The Fed's meeting minutes, "pigeon-racing", pushed the yen, gold and other safe-haven assets up, and the dollar continued to be pressurized.Fears of global economic growth and a general decline in risky assets have put oil
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