gaussian elimination calculator

Topic Connection:http://poj.org/problem?id=2065Title Description:Given the same length of the same cipher, each letter F (k) of the cipher is converted by the plaintext AI according to the F (k) =∑0Problem Solving Ideas:Using Gaussian elimination, it is important to model transformation, listed to augment the matrix problem is not far away from AC. The augmented matrix of this topic is:a0*1^0 + a1*1^1 + a2*

The main idea: to give the light of some relationship, ask how many ways from the beginning state to the final state.Idea: In fact, according to the light of these relations can be listed a series of equations, and then use the Gaussian elimination of the number of free elements can be obtained, the answer is 2^ the number of free elements.CODE:#define _crt_secure_no_warnings#include POJ 1830 switching prob

For the first time, we use Gaussian elimination to solve the light plate as a linear equation group./*########################################################################## File name:poj_1222.cpp# Author: caolei# Created time:2015/7/20 15:48:04#########################################################################* /#include #include #include #include #include #include #include using namespace STD;#de

DescriptionBecky and her bedroom are playing games in their bullpen. But the day does not from the person, suddenly, the source of the barn jump shutter, all the lights are closed. Baby is a very small girl, in the endless darkness that reaches her thumb, she is horrified, miserable and hopeless. She wants you to help her, to start all the lights again! She can continue to play the game with her bedroom! A total of n (1 Input* First line: The whole number of two spaces separated: N and M.* Secon

............................................................Am1*x1 xor Am2*x2 xor ... XOR AMN*XN = 1The solution can be solved by using the Gaussian elimination element.However, the problem requires a minimal solution.When will the solution not be the only one?If there is an item XI, the last equation to be solved is 0*xi = 0That is, when the first and subsequent equations of the XI coefficients are all 0,

the current matrix . Then the next request, the need for non-existent circumstances, because each number is taken or not taken, that is, the 2^row-1 species, remove all the situation. Code:#include #include#include#include#include#include#includeSet>#include#include#includestring>#defineLL Long Longusing namespacestd;//The linear basis of XOR Gaussian elimination element//time Complexity O (63n)Const intMA

300 maximum factorization less than 2000, select several of their product is the total square number of how many schemes.The number of qualitative factors for each number of the legal scheme is different from the odd or even value of 0.For example 12=2^2*3, the corresponding parity value of 01 (2 is the number of the number of 0,3 is odd 1), 3 of the corresponding parity value is 01, so the 12*3 is the total square number.Then the XOR Equation Group is:A11x1+a12x2+...+a1nxn=0A21x1+a22x2+...+a2nx

circle formula, the center is obtained. Then use the nth + 1 equation (set subscript N) Sigma ((xi-oi) ^2) = r^2 n equations to be easily obtained: Sigma ((xi-oi) ^2) = Sigma ((yi-oi) ^2)Both sides expand and then eliminate the oi^2 to get Sigma (xi-yi) *oi) = Sigma (xi^2-yi^2). After getting n such n-ary once equation, we can solve it by using Gaussian elimination element. But first Fabs (xi) #include #in

Topic:http://www.lydsy.com/JudgeOnline/problem.php?id=1013ExercisesConsider the two-dimensional we can understand a truth:Two points to the left can represent an equation, and then subtract from the 22 equation to get a one-time equationSo we can do it with Gaussian elimination.#include #include#include#include#defineN 13using namespacestd;intn,m;DoubleC[n][n],f[n][n],ans[n];inlinevoidGauss () { for(intI=1;

DescriptionThere is a spherical space generator capable of producing a hard sphere in n-dimensional space. Now that you are trapped in this n-dimensional sphere, you only know the coordinates of the n+1 points on the sphere, and you need to determine the spherical coordinates of the n-dimensional sphere as quickly as you can to destroy the sphere space generator.Input OutputinputThe first line is an integer n (1OutputWith only one row, the n-dimensional coordinates (n real numbers) of the globe

data, 1For 100% of data, 1Tip: Give two definitions:1, the ball sphere: to the spherical surface any point distance is equal points.2, Distance: Set two n for Space point A, B coordinates (a1, a2, ..., an), (B1, B2, ..., BN), then AB distance is defined as: dist = sqrt ((A1-B1) ^2 + (A2-B2) ^2 + ... + (an-bn) ^2)Ps:Gaussian elimination!Set the center of the circle (x, y), and then use the radius equal! Using the distance formula we can get n equation

To give you the number of n (nIdea: Gaussian-if the elimination of the elimination of the element after the cut into a number of independent line vectors, they will be different or up good#include #include #include #include #define MAXN 3000#define LL __int64using namespace Std;LL BIN[MAXN],A[MAXN];int main (){int n;scanf ("%d", n);for (int i=1;ifor (int i=1;iint

pointer. So, // Get the X address and pass it back. Obtains the address of juzhen [I] [J]. % lf indicates that juzhen [I] [J] is a double precision floating point type. } } // Convert the original matrix into an upper Triangle Matrix For (I = 0; I { // Select the maximum absolute value of each time as the [I], that is, the principal element. If (zhaozuidazhi (I) // function call { Jisuan (I); // function call } Else { Printf ("This matrix is irreversible"); // The

Http://poj.oRG/problem? ID = 1222 First paste a link Http: // blog.Csdn.net/u013081425/artiCLE/details/24248247 Enumerate the status of the first row and test it. If the last row is 0, this solution is feasible. Another method is Gaussian elimination. Reprinted analysis: the name of this game is lights out. There are mxn buttons on a board, and buttons are also lights. Each time you press a button, the b

represents n,m,hp. The next line of integers, section I, indicates the amount of blood to be lost from JC to point I. Ensure that the number of 1th and N is 0. The next M-line of two integers per line, A, B, has a non-forward edge between AB.OutputOnly one line, which means JC finds the expected probability of his little apple, retains eight decimal places.Sample Input 3 3 20 1 01 21 32 3Sample Output 0.87500000HINTFor 100% of the data 2 The puzzle: If there is no ai=0, direct DP, if HP is very

SGU 275 To xor or not to xor (Gaussian elimination element) Question address: SGU 275 First of all, the greedy idea is that every binary bit should be 1 as much as possible, and whether it can be 1 should be solved by Gaussian elimination element. When this digit has a variable that can be set to 1, it indicates that t

According to the simple column equation, we can list n+1 of n-element 2-th equation.By subtracting the adjacent two equations, we can get N-n-ary 1-th equation, and the Gaussian elimination element can be done.1 varB:Array[0.. -,0.. -] ofextended;2Temp,ans:Array[0.. -] ofextended;3 I,j,k,n:longint;4 cnt:extended;5 begin6 READLN (n);7 fori:=1 ton+1 Do8 forj:=1 toN Do9 read (b[i,j]);Ten

Subtract the upper and lower two equations and then Gaussian elimination 1013: [JSOI2008] spherical space generator sphere time limit: 1 Sec Memory Limit: 162 MB Submit: 2901 Solved: 1517 [Submit] [Status] [Discuss] DescriptionThere is a spherical space generator capable of producing a hard sphere in n-dimensional space. Now that you are trapped in this n-dimensional spher

1196: Gaussian elimination • Two time limit: 10000ms single point time limit: 1000ms memory limit: 256MB descriptionIn the last time, small hi and Little ho took advantage of the convenience store discount, bought a lot of snacks. When they checkout, there are other activities in front of the convenience store.Shopkeeper: Buy things can also participate in game activities Oh, if you can complete the game th

Topic linksChinese problem, Gaussian elimination template problem.#include #include#include#include#include#include#include#include#includeusing namespaceStd;typedefLong Long inch;Const intmaxn= -;//there is a equ equation, var variable element. The number of rows in the augmented matrix is equ and the number of columns is var+1, 0 to Var, respectivelyinchEquvar;inchA[MAXN][MAXN];//Augmented matrixinchX[MAX