gaussian elimination calculator

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Mathematical---Gaussian elimination POJ 1830

) { if(con[row][col]==0) { for(i=row+1; i) { if(con[i][col]!=0) { for(j=1; j1; J + +) {swap (con[row][j],con[i][j]); } Break; } } } if(con[row][col]==0) {row--; Continue; } for(k=1; k) { if(con[k][col]!=0k!=row) {Temp=-(con[k][col]/Con[row][col]); for

POJ 1222-extended LIGHTS out (Gaussian elimination to solve an XOR equation group)

Title Address: POJ 1222Test instructions: There is a 5*6 matrix, each position represents a button and a light, 1 is light, 0 is off. Whenever you press a position button, it and the status of the lights around it all flipped (how to affect the topic), asked in such a square to press which buttons can turn the whole square into an out, then 1 means press, 0 said did not press.#include Copyright NOTICE: This article for Bo Master original article, without Bo Master permission not reproduced. POJ

HDU 5833 Zhu and 772002 (Gaussian elimination)

;voidGetprime () {inti,j; memset (Prime,1,sizeof(prime)); prime[0]=prime[1]=0; for(i=2; i) { if(Prime[i]) prime[++prime[0]]=i; for(j=1; j0]i*prime[j]) {Prime[i*prime[j]]=0; if(i%prime[j]==0) Break; } }}voidGeta (intIdLong Longnum) { inti; I=1; while(num!=1) { while(num%prime[i]==0) {num/=Prime[i]; A[i-1][id]^=1; } I++; }}//A return value of 1 means no solution, 0 is the only solution, otherwise the number of free arguments is returnedintGauss () {int

"HDU 5833" Zhu and 772002 (interpretation of the Gaussian elimination of an XOR equation group)

,sizeof(p)); CNT=0; for(i=2; i -; i++) { if(!V[i]) {p[++cnt]=i; for(J=i; j -; j+=i) {v[j]=1; } } }}intRank ()//Calculate Rank{ intI,j,k,r,u; I=1; J=1; while(iN) {R=i; while(!c[r][j] rCNT) R++; if(C[r][j]) {swap (c[i],c[r]);//if the first R row J column is found to be 1, it is said that the R line and I row interchange (elementary line transformation) for(u=i+1; u) { if(C[u][j]) { for(k=i; k) {C[u][k]=C[U][K]^C[I][K];//each unknown

Ultraviolet A 1564-widget Factory (Gaussian element elimination + reverse element)

Link to the question: Ultraviolet A 1564-widget Factory N kinds of parts, m Work Schedule, Part number from 1 to n, give m work schedule information, X, S, E, indicates that the production of X parts, from week s to week e (it may be multiple weeks), and then the serial number of X parts produced is given. How many days is required for each part to be produced (3 to 10 days guaranteed) Solution: because it cannot be determined that each calendar has been produced for several days, the correspond

HDU 4870 rating Gaussian elimination method

Link: http://acm.hdu.edu.cn/showproblem.php? PID = 1, 4870 Assume that you use two accounts to participate in a competition. In the initial state, both accounts have zero points. Each game uses a low-score account to compete. A probability of winning a game is P, the score of the corresponding account increases by 50 points. Otherwise, the score of the corresponding account decreases by 100 points. Ask the expected number of times of participation in the competition when the score of one account

Poj 1222 extended lights out Gaussian elimination Element

on initially. OutputFor each puzzle, the output consists of a line with the string: "puzzle # m", where M is the index of the puzzle in the input file. following that line, is a puzzle-like display (in the same format as the input ). in this case, 1's indicate buttons that must be pressed to solve the puzzle, while 0 indicate buttons, which are not pressed. there shoshould be exactly one space between each 0 or 1 in the output puzzle-like display. Sample Input 20 1 1 0 1 01 0 0 1 1 10 0 1 0 0 1

Select all principal component Gaussian elimination algorithm

/*Select all principal component Gaussian elimination algorithm to solve linear equations A x = BBy Kingwei 2005.2.27*/ # Include # Include # Define EPS 1e-11 # Define MAX_DIM 20 Int GaussLEquation (double x [], int dim, double A [] [MAX_DIM], double B []){Int maxColPos [MAX_DIM], maxRowPos;Double maxElem, absElem, temp;Int k, I, j, status = 1;For (k = 0; k {MaxElem = 0.0;For (I = k; I For (j = k; j {AbsEl

POJ 1222 extended lights out (Gaussian elimination method)

. OutputFor each puzzle, the output consists of a line with the string: "PUZZLE # m", where m is the index of the puzzle in the input file. following that line, is a puzzle-like display (in the same format as the input ). in this case, 1's indicate buttons that must be pressed to solve the puzzle, while 0 indicate buttons, which are not pressed. there shoshould be exactly one space between each 0 or 1 in the output puzzle-like display. Sample Input 20 1 1 0 1 01 0 0 1 1 10 0 1 0 0 11 0 0 1 0 10

HDU 3364 Lanterns Gaussian elimination element (Water difference or Equation

HDU 3364 Lanterns Gaussian elimination element (Water difference or Equation Question: Given n lamps, m switches The m line below shows which lights can be controlled by each switch (that is, when you press this switch, the status of these lights will change) Q: one query in one row, and one query with n numbers indicates the final state of the lamp. Number of solutions from full darkness to this State (on

POJ 3185 The Water bowls Gaussian elimination + Enumeration free variable _ state compression

0 1 1 1 0 0 1 1 0 1 1 0 0 0 0 0 0 0-0 Sample Output 3 Hint Explanation of the sample:Flip Bowls 4, 9, and them all drinkable:0 0 1 1 1 0 0 1 1 0 1 1 0 0 0 0 0 0 0 [Initial State]0 0 0 0 0 0 0 1 1 0 1 1 0 0 0 0 0 0 0 0 [after flipping Bowl 4]0 0 0 0 0 0 0 0 0 1 1 1 0 0 0 0 0 0 0 0 [after flipping Bowl 9] 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 [after flipping Bowl 11] 20 integers of 0 or 1, known to change the number of position I, will change the number of i-1 and i+1 positions at the same t

Shandong Province Fifth annual ACM Province Race Circle (Gaussian elimination Element)

problem Description You are been given a circle from 0 to n-1. If you is currently at x, you'll move to (x-1) mod n or (x + 1) mod n with equal probability. Now we want to know the expected number of steps you need to reach X from 0. Input The first line contains one integer t-the number of test cases. Each of the next T lines contains, integers n, x (0≤x Output For each test case. Print a single float number-the expected number of steps you need to reach X from 0. The figure was accurate to 4

POJ 3185 The water bowls (math: Gaussian elimination)

Each location affects only adjacent locations Do the Gaussian elimination and then enumerate. The code is as follows: #include

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