general electric blender

Descriptiona range is given, the begin and the end are both integers.You should sum the cube of all the integers in the range. Inputthe first line of the input was T (1 Each case of input is a pair of integer A, a (0 1#include 2__int64 a[1000000]={0,1};3 intMain ()4 {5 for(__int64 i=1; i1000000; i++)6 {7a[i]=a[i-1]+i*i*i;8 }9__int64 t,k=0;;Tenscanf"%i64d",t); One while(t--) A { - __int64 m,n; -scanf"%i64d%i64d",m,n); theprintf"Case #%i64d:%i64d\n", ++k,a[n]-a[m-1]); - }

) is multiplied, it overflows. The title asks "may assume the result is in the range of 32-bit signed integer", which requires that the sum is a 32-bit signed integer. The sum of the test data given by OJ (n (n+1)/2) must be within the range of 32-bit integers, but (n (n+1)) is not necessarily. The reason you can infer WA should be here. You can subtly change the formula:Putsum=n* (n+1)/2;Switchif (n%2==0)sum=n/2* (n+1);ElseSum= (n+1)/2*n;The entire code is as follows:1#include 2 intMain ()3 {4

=getchar ())if(ch=='-') f=-1; for(; isdigit (ch); Ch=getchar ()) x=x*Ten+ch-'0'; returnx*F;} InlinevoidWriteintx) { if(x0) Putchar ('-'), x=-x; if(x>9) Write (x/Ten); Putchar (x%Ten+'0'); return ;}intn,m;inthead[100006];intnxt[200006],to[200006];intTotal=0;voidAddintXinty) { Total++; To[total]=y; Nxt[total]=Head[x]; HEAD[X]=Total ; return ;}intdfn[100006],low[100006];inttot=0;intnum[100006];voidTarjan (intXintFA) {Dfn[x]=low[x]=++tot; for(intE=head[x];e;e=Nxt[e]) { if(!Dfn[to[e]])

Problem Description There is many lamps in a line. All of the themare off at first. A series of operations is carried out on these lamps. On thei-th operation, the lamps whose numbers is the multiple of I change thecondition (on to off and off).Input Each test case contains only a number n (0Output output The condition of the n-th lamp after infinity operations (0-off, 1-on).Sample Input 15Sample Output 10HintConsider the second test case:The initial condition:0 0 0 0 0 ...After the first Operat

The least oneTime limit:9000/3000 MS (java/others) Memory limit:65536/32768 K (java/others)Total submission (s): 492 Accepted Submission (s): 184Problem Description in the RPG game ' go back Ice Age ' (I decide to develop the game after my undergraduate education), all Heros has their own respected value, and the skill of killing monsters is defined as the following rule:one hero can Ki LL the monstrers whose respected values is smaller then himself and the both respected values have none common

integer Mi, 0Output for each case, there is Q results, in each result, you should output the value of the hero you'll dispatch to C Omplete the task.Sample Input237Sample Output511AuthorwangyeSource2008 "Insigma International Cup" Zhejiang Collegiate Programming Contest-warm up (4)Recommendwangye | We have carefully selected several similar problems for you:1793 1796 1797 1794 1798 test instructions: Kill Monster game, Hero's ability to be greater than the monster, and both ability is prime, co

for(intI=0;i4; i++) + { -next.x=current.x+dir[i][0]; $next.y=current.y+dir[i][1]; $ - if(next.x>=0next.x0next.y'#'!Vis[next.x][next.y]) - { the - if(map[next.x][next.y]=='R')Wuyi returncurrent.time+1; the - if(map[next.x][next.y]=='x') Wunext.time=current.time+2; - Else Aboutnext.time=current.time+1; $vis[next.x][next.y]=1; - Q.push (next); - } - }

pockets is part of the same oil deposit if they is adjacent horizontally, vertically, or diagonally. An oil deposit won't contain more than pockets.Sample INPUT1 1 * 3 5 *@*@* **@** *@*@* 1 8 @@****@* 5 5 ****@ *@@*@ *@**@ @@@*@ @@**@ 0 0Sample Output0 1 22Sourcemid-central USA 1997Recommendeddy | We have carefully selected several similar problems for you:1016 1010 1312 1242 1240//Mark →→1#include 2#include 3 using namespacestd;4 #defineN 110;5 intm, N, I, J;6 7 intac[8][2]={{0,1},{1,1},{1,0},

Prime Ring problemTime limit:4000/2000 MS (java/others) Memory limit:65536/32768 K (java/others)Total submission (s): 28204 Accepted Submission (s): 12561Problem Descriptiona Ring is compose of n circles as shown in diagram. Put Natural number 1, 2, ..., n into each circle separately, and the sum of numbers in the adjacent circles should is a PR Ime.Note:the number of first circle should always be 1.INPUTN (0 Outputthe output format is shown as sample below. Each row represents a series of cir

relationship between inquiries, it is for the current state!OutputEach set of input data corresponds to one row of output. If you can eliminate the output "YES", you cannot output "no".Sample InputSample OutputYesnonononoyes This topic at that time to pit me an afternoon time .... The code is flawed, and there are always unexpected letters, and the most pit is that dir array elements are not the same as the wrong, ghosts know why. It's similar to the one I did before. Just BFS a search to the e

reach from the Initia L tile (including itself).Sample Input6 9....#......#..............................#@...#.#. #.11 9.#..........#.#######. #.#.....#.. #.#.###.#.. #.#[email protected]#.#. #.#####.#.. #.......#.. #########............ 11 6..#. #.. #....#.. #.. #....#.. #.. ###.. #.. #.. #@...#.. #.. #....#.. #.. #.. 7 7..#.#....#.#. ###.###[email protected]###.###. #.#....#.#.. 0 0Sample Output4559613 #include Copyright NOTICE: This article for Bo Master original article, without Bo Master

Least common multipleTime limit:2000/1000 MS (java/others) Memory limit:65536/32768 K (java/others)Total submission (s): 38681 Accepted Submission (s): 21606Problem DescriptionGiven two positive integers, calculate the least common multiple of these two numbers.InputThe input contains multiple sets of test data, with only one row per group, including two positive integers not greater than 1000.OutputFor each test case, the least common multiple of these two numbers is given, and each instance ou

Box of BricksTime limit:2000/1000 MS (java/others) Memory limit:65536/32768 K (java/others)Total submission (s): 5457 Accepted Submission (s): 2358Problem Descriptionlittle Bob likes playing with his box of bricks. He puts the bricks one upon another and builds stacks of different height. "Look, I ' ve built a wall!", he tells his older sister Alice. "Nah, should make all stacks the same height. Then you would has a real wall. ", she retorts. After a little con-sideration, Bob sees that she was

GPA.Input contains more than one set of data, and the first row of each group of data has a number n, and the next row of n rows represents a score. Each line has two actual number S,p,s represents the course's credit, p indicates the student's score (percentile). If p=-1 The student This course lacks the examination, should not be counted. Output outputs a row for each set of data, representing the student's GPA, which retains two decimal places. If GPA does not exist, output-1.Sample Input33