gsx edi

methods) : 71a21af5 8bec mov EBP, esp // machine code to be hooked (2nd methods) : 71a21af7 83ec10 sub ESP, 00000010 : 71a21afa 56 push ESI : 71a21afb 57 push EDI : 71a21afc 33ff xor edi, EDI : 71a21afe 813d1c20a371931ca271 cmp dword ptr [71a3201c], 71a21c93 // machine code to be hooked (4th methods) : 71a21b08 0f84853d0000 je 71a25893 : 71a21b0e 8d45f8 Lea eax,

I hope you can come up with some ideas ~ Check whether there is any shell... Microsoft Visual C ++ 6.0, indicating no shell ~ Let's enter an account and password for trial run ~ The error message "incorrect registration name or registration code!" is displayed !" Okay. Let's load it with OD ~~ Search for asii, find the error message, and double-click it to go to the code ~ 00401d00/0f85 df1_00 jnz ultradic.00401de500401d06. | 68 01100000 push 100100401d0b. | 68 f4704300 push ultradic.004370f4; A

, because the parameter needs to be seen before createfont is called, to determine which call corresponds to the song name, use "BC" to clear the breakpoint and set the breakpoint in the last return statement of the kernel, then press "F5" until Winamp starts running and closes it."Load" again, press "F5", this time it stops on the Return Statement in the kernel, and then press "F10" to return to the code area where Winamp is located, and look up, you can see the following code:

"Copyright Notice: respect for the original, reproduced please retain the source: blog.csdn.net/shallnet, the article only for learning Exchange, do not use for commercial purposes"the CMPS directive is used to compare string values, and the CMPS directive has three formats: CMPSB, CMPSW, CMPSL. The implied source operand and target operand locations are stored in the ESI and EDI registers, and each time the cmps instruction is executed, the ESI and

). So the different compilers of different platforms have to be treated differently. The above is the last insufficient supplement. Here's a look at the array: test.c Example: Copy Code code as follows: void Hello1 () { int a[3]={1,2,3}; int b=a[1]; } void Hello2 () { int a[3]={1,2,3}; int b=* (a+1); } void Hello3 () { int a[3]={1,2,3}; int B=1[a]; Is that right? } If you look carefully, the difference between the three functions is that of the

and an internal counter of the repeated (REP) prefix command and LOOP command.(6) edx is always used to place the remainder produced by integer division.(7) esi/edi are called "source/destination index register" (source/destination index), because in many string operation commands, DS: ESI refers to the source string, While ES: EDI points to the target string.On a 32-bit platform, ESP is reduced by 4 bytes

CPU switches from user mode to privileged mode, then jump to the kernel code to execute the exception handling program.In the "B INT" command, the value 0x80 is a parameter. In exception handling, the parameter determines how to handle the problem. In the Linux kernel, an int 0x80 exception is called a system call.The values of C eax and EBX registers are two parameters passed to the system call. The value of eax is the system call number, 1 indicates _ exit call, and EBX indicates the paramete

+ 31o. Text: 000103dc mov ECx, [esp + 8]. Text: 000103e0 and dword ptr [ECx + 18 h], 0. Text: 000103e4 xor dl, DL. Text: 000103e6 mov dword ptr [ECx + 1ch], 1. Text: 000103ed call DS: iofcompleterequest. Text: 000103f3 XOR eax, eax. Text: 000103f5 retn 8 Ntstatus sdbgmsgcreate (pdevice_object pdeviceobject, pirp){IRP-> iostatus. Status = STATUS_SUCCESS;IRP-> iostatus. Information = 1;//// The iofcompleterequest routine is the _ fastcall call method.// Transfer parameters using ECx and EDX//Ioco

same as that of the function I wrote (you can also say that the exponent in the function I wrote is: change the = 1/gamma statement to exponent: = gamma, which is the same as the setgamma method of GDI + ): Procedure imagesetgamma (VAR data: timagedata; GAMMA: single); var I: integer; exponent: Double; gammatab: array [0 .. 255] of byte; begin exponent: = 1/gamma; // This sentence is changed to exponent: = gamma;, which has the same effect as the setgamma parameter of GDI + for I: = 0 to 255 do

The code from chapter 7 of Intel assembly language programming (fifth edition) uses the AAA (ASCII adjust after addition) command to adjust the results after the ASCII addition. The source code is as follows: Title ASCII addition (ascii_add.asm) ; Perform ASCII arithmetic on strings having ; An implied fixed decimal point Include irvine32.inc Decimal_offset = 5; offset from right of string . Data Decimal_one Byte "100123456789765"; 1001234567.89765 Decimal_two Byte "900402076502015"; 900402

the program73d311ab 817e 38 6a030000 cmp dword ptr ds: [ESI + 38], 36a73d311b2 74 1A je short mfc42.73d311ce73D311B4 8B06 mov eax, dword ptr ds: [ESI]73D311B6 57 PUSH EDI73D311B7 8BCE mov ecx, ESI73D311B9 FF50 60 call dword ptr ds: [EAX + 60]; PreTranslateMessage (Message preprocessing)73D311BC 85C0 test eax, EAX73D311BE 75 0E jnz short MFC42.73D311CE73D311C0 57 push edi; message preprocessing returns FALSE73D311C1 FF15 ACB6DC73 call dword ptr ds: [7

I remember writing a HOOK API article (C/C ++ HOOK API (in-depth analysis of the principle-loadlibrarya). The main principle of this article is to construct a code byte, modify the first 16 bytes of the loadlibrarya function, and then jump to the custom function. When you call a normal function, unhook it again. In this way, when you call a function again, the unhook and hook operations appear too frequent. Moreover, the hook and unhook were designed as thiscall at the time. Therefore, maintaini

// Http://stackoverflow.com/questions/1715224/very-fast-memcpy-for-image-processing CourtesyWilliam Chan and Google. 30-70% faster than memcpy in Microsoft Visual Studio 2005. void X_aligned_memcpy_sse2(void* dest, const void* src, const unsigned long size_t){ __asm { mov esi, src; //src pointer mov edi, dest; //dest pointer mov ebx, size_t; //ebx is our counter shr ebx, 7; //divide by 128 (8 * 128bit registers) loop_copy:

{2002.8.5 kingron} {Source: Source string} {Sub: Sub string} {Return: Count} {Ex: strsubcount ('abccdcd', 'bc') = 2} Function strsubcount (const source, Sub: string): integer; VaR Buf: string; I: integer; Len: integer; Begin Result: = 0; Buf: = source; I: = pos (sub, Buf ); Len: = length (sub ); While I Begin INC (result ); Delete (BUF, 1, I + len-1 ); I: = pos (sub, Buf ); End; End; {strsubcount} {The following function returns the position after the specified position of substr in S}{Example:

KiInterruptTemplate .. That's it... The KiInterruptTemplate code is in ntoskrnl/ke/i386/Traps. s .... . Func KiInterruptTemplate_ KiInterruptTemplate: /* Enter interrupt trap */INT_PROLOG kit_a, kit_t, DoPushFakeErrorCode _ KiInterruptTemplate2ndDispatch:/* Dummy code, will be replaced by the address of the KINTERRUPT */Mov edi, 0 _ KiInterruptTemplateObject:/* The jump instruction address will be replaced with the actual address of the function to b

corresponding to the main function is as follows 123456789101112131415161718192021222324252627282930313233343536 7: int main()8: {00401020 push ebp // ebp初始为0018FF84h压栈，压栈后esp = 0018FF48h - 4 = 0018FF44h00401021 mov ebp,esp // ebp保存栈顶0，ebp=esp=0018FF44h00401023 sub esp,48h // esp -= 48h开辟了一段栈空间，留待后面保存局部变量，此时esp=0018FF44h-48h=0018FEFCh00401026 push ebx 00401027 push esi00401028 push edi // ebx、esi和

program, and no other auxiliary components. To control the register of passed parameters, you can extract the generic gadgets in the program initialization function.Enter Objdump–d./vul to observe the _libc_csu_init () function.There are two accessories available:Accessories 14005f0: 4c 89 ea mov %R13,%RDX 4005f3: 4c 89 f6 mov %R14,%RSI 4005f6: 44 89 ff mov %R15d,%EDI 4005f9: 41 ff 14 dc

Windows XP, Windows Server 2003 experiments, you can perform experiments on diskless workstation of 3COM VLD and 3COM DABS, and terminal experiments of Windows 2000/Server 2003 and Citrix MetaFrame 1.8/XP. V. Enterprise Users Many enterprises, for historical reasons or other reasons, each department has a server, or several important departments have servers. These servers have a single function and fewer applications, but these applications are different. They cannot coexist on one server. P

Two redhetEnterprise-R4-U4 systems rac1 and rac2 are installed on the Virtual Machine VMwareGSXServer, And the oracle10gRAC ring is built on the Virtual Machine VMwareGSXServer. Two redhet Enterprise-R4-U4 systems rac1 and rac2 are installed on the Virtual Machine VMware GSX Server, and the oracle10g RAC ring is built on this basis. I. Overview of software and hardware Environments Two redhet Enterprise-R4-U4 systems rac1 and rac2 are installed on

Hardware configuration IBM R50 5GC China 1.5 GB , 1G Memory, 40 GB Hard Disk Software Configuration Windows XP Pro SP1,VMware GSX Server 2.5.1 ,RHEL3,Oracle 10g For Linux Install VMware This step is not mentioned.,What I installed isVMware GSX Server,No testsVMware Workstation,Therefore, the steps in this article cannot be implemented. In VMwar