Binary XML has aroused a lot of discussion. One reason is that relatively compact transmission formats are needed, especially for Web Services. The existing ready-to-use solution is compression. This tip illustrates how to use compression to prepare XML files for transmission in Web Services.In the discussion of XML, the view of binary XML has always been heard. Due to its traditional text and the rules required to make international texts more friendly, XML is very lengthy. The equivalent binar
virtual function of the subclass is called through the constructor of the parent class, and this virtual function may fail to access data members of the subclass.
Let's take a look at the compiled code generated by vc7.1 to easily understand this behavior.
This is the c190 constructor:
01 000000fe0 push EBP 02 000000fe1 mov EBP, esp 03 000000fe3 sub ESP, 0cch 04 00426fe9 push EBX 05 00426fea push ESI 06 00426feb push EDI 07 00426fec push
bug correction used in the code, see the article "GDI + for VCL basics-GDI + and VCL". (8.8.18)Data Type:
Type
// Image data structure compatible with the GDI + tbitmapdata Structure
Timagedata = packed record
Width: longword; // The image width.
Height: longword; // Image Height
Stride: longword; // The length of the scanned line of the image in bytes.
Pixelformat: longword; // unused
Scan0: pointer; // image data address
Reserved: longword; // Reserved
End;
Pimagedata = ^ timaged
constant Stack (Stack Space ). Why does tail recursion achieve constant stack space? We use the famous fibonacci series as an example to illustrate this. The implementation method of the fibonacci series is generally like this. int FibonacciRecur (int n) {if (0 = n) return 0; if (1 = n) return 1; return FibonacciRecur (n-1) + FibonacciRecur (n-2);} but note that this implementation method is not tail recursion, because the last action of tail recursion must be called itself, the final action he
parameters are ejected, here is not, really strange!Then we'll track into the dark alley and see what he's done!37:int __stdcall fnstandardcall (int arg1, short arg2, char arg3, void *arg4): {00401200 push ebp00401201 MOV ebp,esp00401203 sub esp,50h00401206 push ebx00401207 push esi00401208 push edi00401209 Lea edi,[ebp-50h]0040120c mov ecx,14h00401211 mov eax,0cccccccch00401216 re P STOs DWORD ptr [Edi
convert the value in Edx:eax to a decimal output form string, which is familiar, as in the previous example!; For example: edx=0,eax=01234567h, the converted string is:; -> ' 19088743 ', 0OUTEDXEAX proc uses ebx esi edi,lpstringMOV edi,lpstring points to the address where the results are storedMOV esi,lpstringmov ecx,10 converted into decimal. While eax!=0 | | Edx!=0Push EAXMOV Eax,edxXOR Edx,edxdiv ECXMOV
: Manual construction Stack Practice-How to manually construct the call stack ============ first illustrate the characteristics of the stack with a few pictures to help you understand. 1. Stack to low address growth. 2. Press the data into the stack, in the case of the stack. 3. Read the full textView the command summary for the disassembly code of the function in windbg: Command ========== U. U $ip the two commands above are the same effect, and disassemble the 8 commands on the current $IP add
simple.The main function first calls ProcCommandLine () to analyze the command line, obtain the Service Group to be started, and then calls SvcHostOptions () to query the options of the Service Group and all services of the Service Group, use a Data Structure svcTable to save the DLL of these services and their services, call the PrepareSvcTable () function to create the SERVICE_TABLE_ENTRY structure, and direct all processing functions SERVICE_MAIN_FUNCTION to one of your own functions FuncSer
Article Title: linux memory management initialization. Linux is a technology channel of the IT lab in China. Includes basic categories such as desktop applications, Linux system management, kernel research, embedded systems, and open source.
ENTRY (startup_32)
/*
* Set segments to known values.
*/
Cld
Lgdt boot_gdt_descr-_ PAGE_OFFSET/* set the segment register */
Movl $ (_ BOOT_DS), % eax
Movl % eax, % ds
Movl % eax, % es
Movl % eax, % fs
Movl % eax, % gs
/*
* Clear BSS first so that there are
data members of the subclass.Let's take a look at VC7.1The generated assembly code can easily understand this behavior.This is the C190 constructor:01 00426FE0 push ebp 02 00426FE1 mov ebp,esp 03 00426FE3 sub esp,0CCh 04 00426FE9 push ebx 05 00426FEA push esi 06 00426FEB push edi 07 00426FEC push ecx 08 00426FED lea edi,[ebp+FFFFFF34h] 09 00426FF3 mov ecx,33h 10 00426FF8 mov eax ,0CCCCCCCCh 11 00426FFD rep
push edi
00402099 lea edi, [ebp-40h]
0040209C mov ecx, 10 h
004020A1 mov eax, 0 CCCCCCCCh
004020A6 rep stos dword ptr [edi]
252: return 0;
004020A8 xor eax, eax
253 :}
004020AA pop edi
004020AB pop esi
004020AC pop ebx
004020AD mov esp, ebp
004020AF pop ebp
004020B0 ret
250: static int process ()
251 :{
00402090 push
issue CCDebuger has been very clear. If you have any questions, read the article. We directly open the RUN trace, add the "entry to all function processes", and return to the "Check" button in the program. In this case, open the RUN trace record in OllyDBG to find the key location, then you can break down at this position. The program is broken here.004010E2 |. 8BFE mov edi, ESIUser name is sent to edi004010E4 |. 03F8 add
It turns out that there have been checksum-related cracking on the internet. I will interview the checksum compilation code and the vb version for cracking.Currently, I am using the checksum code of vb.Assembly Code of checksum:GOOGLECHECK proc nearVar_8 = dword ptr-8Var_4 = dword ptr-4Url_offset = dword ptr 8Url_length = dword ptr 0ChMagic_dword = dword ptr 10 hPush ebpMov ebp, espPush ecxPush ecxMov eax, [ebp + url_length]Cmp eax, 0ChPush ebxPush esiMov esi, [ebp + magic_dword]; = 0xE6359A60Pu
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