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operations. Consider the original hook is a made up of cupreous sticks. Input the input consists of several test cases. The first line of the input is the number of the cases. There is no more than cases. For each case, the first line contains a integer N, 1Next Q lines, each line contains three integers X, Y, 1 Print a number in a line representing the total value of the hook after the operations. Use the format in the example. Sample Input 1 10 2 1 5 2 5 9 3 Sample Output Case 1:the total v

(); + } - for(i =1; I ) the { * if(Num[i] = =0) $ {Panax Notoginsengmon[i]=888; - Que.push (i); the } + } A while(!que.empty ()) the { +ans++; -m=Que.front (); $ Que.pop (); $sum+=Mon[m]; - for(i = head[m]; I! =-1; i =st[i].next) - { the if(--num[st[i].to] = =0) - {Wuyi Que.push (st[i].to); themon[st[i].to]=mon[m]+1; - } Wu } - } About if(ans = =N) $printf"%d\n", sum); - El

The original question is as followsC-Language legal identifiersTime limit:2000/1000 MS (java/others) Memory limit:65536/32768 K (java/others)Total submission (s): 59747 Accepted Submission (s): 23638Problem description Enter a string to determine whether it is a valid identifier for C.Input data contains multiple test instances, the first row of the data is an integer n, which indicates the number of test instances, followed by n rows of input data, each of which is a string of not more than 50

sky.", otherwise the output "#n is not a sky numbers." Each result occupies one row. Note: #n表示所读入的n值.Sample Input299212340Sample Output2992 is a Sky number.1234 are not a sky number.Import Java.util.scanner;public class Main {public static void main (string[] args) {Scanner scan = new Scanner (system.in); while (Scan.hasnext ()) { int n=scan.nextint (); if (n==0) break; int s1=f (n,10), S2=f (n,12), s3=f (n,16); if (S1==S2S2==S3) System.out.println (n + "is a Sky number.");

Java Problem Solving:ImportJava.util.*;ImportJava.io.*;ImportJava.math.BigInteger; Public classmain{ Public Static voidMain (string[] arg) {Scanner Scan=NewScanner (NewBufferedinputstream (system.in)); intn =Scan.nextint (); intL =N; while(N--! =0) {BigInteger integer=NewBigInteger (Scan.next ()); BigInteger Integer2=NewBigInteger (Scan.next ()); System.out.println ("Case" + (l-n+1) + ":"); System.out.println (integer+ "+" + integer2 + "=" +Integer.add (integer2)); if(n!=1) {System.out.println

A Northwest Electric Power Design Institute is a well-known design consulting and engineering contracting enterprise in the Chinese power industry. National level a qualification certificate for power engineering design, survey, consulting, supervision, general contracting, environmental impact assessment, pressure vessel design, construction engineering, etc. It ranks among the top Survey and Design Enterprises in China. As the production management

;//* Priority Comparison * - } - }; - + intMain () - { + AC t; A intA, B, ans=0; at Charko[Ten], s[Ten]; -Priority_queue Q; - //priority_queue //small →→ Large; - //priority_queue //large →→ small; - while(~SCANF ("%s", s)) - { in if(s[0] =='P') - { toscanf"%s%d%d", Ko, a, b); + strcpy (t.ch, KO); -T.para =A; theT.pri =b; *T.id = + +ans; $ Q.push (t);Panax Notoginseng } - Else the { + if(!q.empty ()) A

" > class= "Bs-docs-featurette-title" > Campus business Card class= "Lead" > in-school Circle of Friends, you may know them Oh!? Header> class= "Row Text-right" > class= "Col-xs-12 text-right" > class= "Btn Btn-primary" >More Alumniclass= "Glyphicon glyphicon-chevron-right" >class= "Row Bs-docs-featured-sites" > class= "Col-xs-6 col-sm-3" > class= "Img-responsive"/>class= "Col-xs-6 col-sm-3" > class= "Img-responsive"/>class= "Col-xs-6 col-sm-3" > class= "Img-responsive"/>class= "Col-xs-6 col-sm-

The meaning of the subject, title. It's easy to understand.The solution is to sort the topology, which can be easily solved.Each input pair of players, to determine whether two players have appeared, did not appear, create a new head node, added to the adjacency table, update the node in the degree.Finally determine if there is a node in the degree of 0, there is, yes, otherwise no.I'm using the list container in the STL to create the adjacency table.The following is the code for the AC:#include

=false; - } the voidTsort () * { $top =0;inti;Panax Notoginseng while(Top k) - { the for(i =1; I ) + if(!vis[i] !Indegree[i]) A Break; theVis[i] =1; +top++; - for(intj =1; J ) $ if(Pic[i][j]) $indegree[j]--; - } - } the - /*void Tsort () {//wa: There is no guarantee that there is only one person who has not lost. Wuyi int m; the For (int j = 0; J - m =-1; Wu for (int i = 1; I - if (!indegree[i]) { About m = i; $ Break ;

there are m lines, each line of two integers, a, B (0In addition to this m-group relationship, no other two people are acquainted. Output for each set of tests, if the data conforms to the "Six degree separation" theory, it Outputs "Yes" in one line, otherwise the output "No".Sample Input8 70 11 22 33 44 55 66 78 80 11 22 33 44 55 66 77 0Sample OutputYesyes#include Copyright NOTICE: This article for Bo Master original article, without Bo Master permission not reproduced. Six Degrees separation

languageImport Java.util.*;class p1867{static int[] Next=new int[100005]; public static void Main (String args[]) {int n,m,i,len1,len2; String str1,str2; Scanner sc=new Scanner (system.in); while (Sc.hasnext ()) {str1=sc.next (); Str2=sc.next (); Len1=str1.length (); Len2=str2.length (); N=KMP (STR1,STR2); M=KMP (STR2,STR1); if (n==m) {if (Str1.compareto (str2) >0) {System.out.println (str2+str1.substring (N,

wheel never leaves the ground, and there are no slipping or skidding.Inputinput consists of multiple datasets, one per line, of the form:Diameter Revolutions TimeThe diameter is expressed with inches as a floating point value. The revolutions is an integer value. The time is expressed with seconds as a floating point value. Input ends when the value of revolutions is 0 (zero).Outputfor each data set, print:Trip #N: Distance MPHOf course N should is replaced by the data set number, distance by t

Input121 33 40 73 815 1915 2010 158 186 125 104 142 90Sample Output51#include 2#include 3 using namespacestd;4 structStu5 {6 intBe,en;7} a[ $];8 BOOLCMP (stu A,stu B)9 {Ten returna.enB.en; One } A intMain () - { - intt,k; the while(SCANF ("%d", t) t) - { -k=1; - for(intI=0; i) +scanf"%d%d",a[i].be,a[i].en); -Sort (a,a+t,cmp); + intj=0; A for(intI=1; i ) at { - if(a[i].be>=a[j].en) - { -k++; -j=i; - } in

Problem descriptiongive a number n, find the minimum x (x>0) that satisfies 2^x mod n = 1.Inputone positive integer on each line, the value of N.Outputif the minimum x exists, print a line with 2^x mod n = 1.Print 2^? MoD n = 1 otherwise.You should replace x and n with specific numbers.Sample Input25Sample output2^? MoD 2 = 12^4 MoD 5 = 1 If you do not use the same residual technique, it is often time-out that the remainder of the number product is equal to the sum of each number.Hangzhou

Calculation of the area of any polygon # include http://blog.csdn.net/hemmingway/article/details/7814494----> To understand the principle, see here.Hangzhou Electric OJ--2036 reform spring breeze blowing everywhere

of output. This line would be:NO CRASHIf the height of the 18-wheeler is less than the height of each of the underpasses, or:CRASH XOtherwise, where X is the height of the first underpass in the data set, the 18-wheeler are unable to go under (which M EANs its height was less than or equal to the height of the 18-wheeler).The height of the 18-wheeler is 168 inches.Sample Input180 160 170Sample OutputCRASH 160Sourcesouth Central USA 2003The big night bully me IQ! The damn egg.#include Hangzhou

New students) In addition to the school race, what avenues can you apply to join the ACM school team? People see Love a^b timelimit:2000/1000 MS (java/others) Memory limit:65536/32768 K (java/others)Total submission (s): 33751 Accepted Submission (s): 22894Problem description An integer representing the last three digits of the a^b.Description: The meaning of A^b is "A's B-square"Input data contains multiple test instances, one row per instance, consisting of two positive integers

communication simple characters, 1602 display; ④ to achieve the final scenario. 3. As captain. ① and teachers to do a good job of communication, lubrication, monitoring progress, planning plans, select the appropriate technical route, according to the actual situation to correct and solve some problems in a timely manner. ② ensure team harmony, work happily and act together as much as possible. ③ A lot of trivial things to solve in time, such as material tools, instrumentation and so on, to ens

'; $CC = (A[I]+B[I]+CC)/Ten;Panax Notoginseng } - if(cc) c[i++] = cc +'0'; theC[i] =' /'; + } A voidPrintChar*c) the { + for(i = strlen (c)-1; i>=0; i--) -printf"%c", C[i]); $printf"\ n"); $ } - Main () - { the intN, J; -scanf"%d", n);Wuyi for(j=1; j) the { -Memset (A,0,sizeof(a)); Wumemset (b,0,sizeof(b)); -Memset (c,0,sizeof(c)); Aboutscanf"%s%s", A, b); $printf"Case %d:\n", j); -printf"%s +%s =", A, b); - reverse (a), reverse (b); - Add (A, B, c); A print