hack cf

A string composed of FT is given. f Represents Forward, t represents turn, and the initial direction is 1. After turning, F changes from 1 to-1 (or-1 to 1) For example, the value of ftfffffff is 3. Given N, you must perform n operations (Change F to T or change t to F) to find how far forward from the original place (absolute value) You can search to solve this problem. For each trip, we can choose Continue in the current direction Or change the direction. In a rough estimation, the m

Test instructionsIf a number can be divisible by the number of its own bits, then it is called Beautiful numbers.The number of Beautiful numbers in the interval [a, b].Analysis: First analysis, 2~9 the largest least common multiple is 2520 ({5,7,8,9}), first preprocess all possible least common multiple m[c]DP[I][D][C] Indicates the number of length I, remainder d, least common multiple is m[c].#include #include#defineMoD 2520ll dp[ *][2520][ -];intbit[ -],m[ $],mnum;intgcdintAintb) { inttmp;

+ =lowbit (x); to } + } - int Get(intx) { the intres =0; * while(X >0) { $Res + =Tree[x];Panax NotoginsengX-=lowbit (x); - } the returnRes; + } A } TA; the +pairint,int>QUERY[MAXN]; -Vector int>LSH; $Vector int>A; $ intN; - LL ans; - the voidinit () { -CIN >>N;Wuyi intx, y; the lsh.clear (); - for(inti =0; I i) { WuCIN >> x >>y; -Query[i] =MP (x, y); About LSH. PB (x); Lsh. PB (y); $ } - sort (Lsh.begin (), Lsh.end ()); - lsh.e

cause the two or the node in the degree can not be reduced to 0 for(intI=0; I) { intE=G[u][i]; Deg[e]--; for(intj=2; j) { //cout if(dp[e][j]>dp[u][j-1]+F[u][i]) dp[e][j]=dp[u][j-1]+f[u][i],pre[e][j]=u; } } for(intI=1; i) if(deg[i]==0) Q.push (i), Deg[i]--; }}voidIni () { for(intI=0; i) Deg[i]=0, flag=0, G[i].clear (), f[i].clear (); CNT=0, sum=N; for(intI=0; i) for(intj=0; j) Dp[i][j]=t+ -, pr

CF 538D (Weird Chess-Inverse Calculation) D. Weird Chess time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Igor has been into chess for a long time and now he is sick of the game by the ordinary rules. He is going to think of new rules of the game and become world famous. Igor's chessboard is a square of sizeN? ×?NCells. igor decided that simple rules guarantee success, that's why his game wi

CF #149 D Coloring Brackets (interval dp) D-Coloring Brackets Time Limit:2000 MS Memory Limit:262144KB 64bit IO Format:% I64d % I64u Submit Status Practice CodeForces 149D Description Once Petya read a problem about a bracket sequence. He gave it much thought but didn't find a solution. Today you will face it. You are given stringS. It represents a correct bracket sequence. A correct bracket sequence is the sequence of opening ("(") and closing (")")

Bayan 2012-2013 Elimination Round (acm icpc Rules, English statements CF, ruanale #105, with T-shirts in the top 100. However, the rate is increased. When can it be yellow. Question: a rectangle is given. There are two holes on both sides. There are some mirrors on the upper and lower sides. A ball is emitted from a hole. The mirror on both sides will reflect and finally reach another hole. Each mirror goes through at most once, and each mirror has a

): L (L), R (r), ID (ID) {} the BOOL operatorConstSeg O)Const { + returnL>O.L; - } $ }seg[n]; $ intAns[n]; - intMain () { - intN; thescanf"%d",n); - intt=0;Wuyi for(intI=1; i) { thescanf"%d%d",seg[i].l,SEG[I].R); -b[t++]=SEG[I].L; Wub[t++]=SEG[I].R; -Seg[i].id=i; About } $Sort (b,b+t); - intK=unique (b,b+t)-b; - for(intI=1; i) { -Seg[i].l=lower_bound (B,B+T,SEG[I].L)-b+1; ASeg[i].r=lower_bound (b,b + T,SEG[I].R)-b+1; + } theSort (seg+1, seg+1+n); -

about the changes. The i-th of these lines describes the i-th change and contains II integers kand F K *, which mean the amount of the force inside the k-th youngling b Ecomes equal to FK * (1≤ k ≤ N, 1≤ F k *≤10). OutputPrint M + 1 lines, each of the them containing a single integer.On the first line, print the number of winners if the tournament is held before all the chan

CF #277 (Div. 2) A. (query rule)A. Calculating Functiontime limit per test1 secondmemory limit per test256 megabytesinputstandard inputoutputstandard output question link: http://codeforces.com/contest/486/problem/A For a positive integerNLet's define a functionF: F(N)? = ?? -? 1? +? 2? -? 3? + ?..? +? (? -? 1)NN Your task is to calculateF(N) For a given integerN.Input The single line contains the positive integerN(1? ≤?N? ≤? 1015 ).Output PrintF(N) I

CF 479E Riding in a Lift prefix and DP Input n a B k has n floors. The starting point of n floors cannot be reached at Layer a and layer B. Assuming that the current position on layer x can reach layer y at each time. | x-y | Dp [I] [j] is the number of solutions that reach layer j for the I-th dp [I] [j] = sum (dp [I-1] [k]) | k-j | K that meets the condition is a continuous segment with prefix and Optimization #include #include #inclu

For the first time, you don't need to translate for cf. Chinese English has a resonance. ^_^ But I didn't make a C question. Unfortunately, I did not dare to touch the D question. I have a shadow on the question of mod10 ^ 9 + 7... Question A: The question is A bunch of apples. Can I divide the question into two piles that are equally important? I didn't read the question clearly at first, after taking a backpack (whether the total size can be filled

CF #52 C Circular RMQ (segment tree Interval Update) Description You are given circular arrayA0 ,?A1 ,?...,?AN? -? 1. There are two types of operations with it: Inc( Lf,? Rg,? V)-This operation increases each element on the segment [ Lf,? Rg] (Inclusively) V; Rmq( Lf,? Rg)-This operation returns minimal value on the segment [ Lf,? Rg] (Inclusively ). Assume segments to be circular, so ifN? =? 5 andLf? =? 3 ,?Rg? =? 1, it means the index sequence: 3 ,?

CF 574E (Bear and Drawing-2 * n dot matrix painting tree) E. Bear and Drawing time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Limak is a little bear who learns to draw. People usually start with houses, fences and flowers but why wowould bears do it? Limak lives in the forest and he decides to draw a tree. Recall that tree is a connected graph consistingNVertices andNInvalid-limit 1 edges. L

while(j I) {117 //cout 118 119 //cout - //cout 121 122ans[q[j].id] = Color.Get(q[j].r)-color.Get(q[j].l-1) + (sl.Get(q[j].r)-sl.Get(q[j].l-1) ==0);123++j;124 if(i = =- to) { thecout endl;126 for(intK =1; K Get(k) ' '; cout endl;127 for(intK =1; K ' '; cout endl; - for(intK =1; K Get(k)-sl.Get(k-1) ' '; cout endl;129 } the }131 } the 133 for(inti =0; I "%d\n", ans[i]);134 135 re

Title Link: Http://codeforces.com/problemset/problem/504/ETest instructions: Give a tree, with a letter on each node. Each query gives two paths, asking the longest common prefix of the strings for both paths.Idea: The tree chain, record each chain of strings, both positive and negative are recorded, forming a large string. Record the position of each chain corresponding to the string in the large string. The suffix array is then evaluated for the large string. The last question is the query on

D. Tanya and Passwordtime limit per test2 secondsmemory limit per test256 megabytesinputstandard inputoutputstandard OUTPU TWhi Le Dad was at work, a little girl Tanya decided to play with Dad's password to his secret database. Dad ' s password is a string consisting Of n pieces of paper. Then Tanya realized that dad'll be upset to learn on her game and decided to restore the password or at least any str ing corresponding to the final set of three-letter strings. You have a to-help with this

What if the WIN8 system does not have full screen after the CF game is updated? Win8 not full screen is related to the official recently updated v3.5.9 version, in the update, we saw the optimization win10 full screen, then it may be the official optimization win10 after the WIN8 again problems! So how to solve it? The following Pepsi Web Small series provides a simple resolution and adjust the game resolution can make the game full-screen way!

VS2008 development environment, when programming wm sockets under. NET CF 3.5 Bitmap BMP = Unhandled exception occurred at New Bitmap (Stream) By groping, I find that the problem persists regardless of how the object is set to null and Dispose. The reason, the individual guess is bitmap instantiation of itself will open MemoryStream flow, so then use MemoryStream is very easy to leak memory Therefore, it is recommended that when combined with bi

First, what is the FPS? For like to play CF should know FPS, then do not play, FPS is often mentioned in the game frame number, FPS higher, the game's screen smoother, on the contrary, it will often appear card screen crashes or even blue screen phenomenon. Two, FPS base solution 1, in the game, the resolution to adjust the lower point, which is more conducive to memory optimization. 2, if other software uses CPU too high, it will also cause a ver