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I Hate It Time Limit: 9000/3000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission (s): 28044 Accepted Submission (s): 11126Problem Description many schools have a popular habit. Teachers like to ask, from xx to xx, what is the highest score. This made many students very disgusted. Whether you like it or not, what you need to do now is to write a program to simulate the instructor's inquiry according to the instructor's requi

HDU 1754 I Hate It (Single Point update of Line Segment tree), hdu1754 Problem Description many schools have a popular habit. Teachers like to ask, from xx to xx, what is the highest score. This made many students very disgusted. Whether you like it or not, what you need to do now is to write a program to simulate the instructor's inquiry according to the instructor's requirements. Of course, teachers sometimes need to update their scores. Input this

HDU 1754 I Hate It (line segment tree), hdu1754Problem Description many schools have a popular habit. Teachers like to ask, from xx to xx, what is the highest score.This made many students very disgusted.Whether you like it or not, what you need to do now is to write a program to simulate the instructor's inquiry according to the instructor's requirements. Of course, teachers sometimes need to update their scores.Input this question contains multiple

Suddenly I found myself helpless.No, I don't want to change the title, or I don't want to change the signature. I saw a blog yesterday. I forgot who it was. I said that the best time would be around. Don't let it slip away. I think it is the best time to use such titles and signatures? Now, we should try our best to keep them as they are. Don't let these wonderful times slip away.Suddenly I think of the Battle of pingcheng raccoon, is it me now, just like they at that time, doing a beautiful dre

to use software for Dummies, rather than teaching dummies how to use high technology!Finally, I would like to say: Having a cohabitation before marriage is also considered a real marriage. Why must we let everyone follow the so-called technical standards? No matter how much you hate, IE6 has become a de facto standard. If you reject IE6, your website will not have much traffic. If you reject it, you have to give IE6 a face, isn't it? Finally, I would

A simple line segment tree is unnecessary. 1 # include HDU 1754 I hate it (line segment tree)

value to a small value, that is, the smaller than the second largest. How can we update the maximum value! // Only the problem occurs here, but not elsewhere. My AC code # Include # Include # Define maxsize 200005 using namespace STD; Struct Node { Int left, right, M; } Tree [maxsize * 4]; Void build (INT node, int left, int right) { Tree [node]. Left = left; Tree [node]. Right = right; Tree [node]. m = 0; If (Left = right) Return; Int mid = (left + right)/2; Build (node * 2, left, mid ); Bu

HDU 1754 I Hate it (maximum line segment tree template) Idea: The same as the thought I posted on the previous summation process, it is only now the maximum value. AC code: # Include # Include # Include # Include # Define deusing namespace std; inline int Max (int a, int B) {return a> B? A: B;} const int MAXN = 200001; // range: struct {int l, r, m; // l left endpoint, r right endpoint, m is the maximum score of this r

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that this is an update operation that requires the student with ID A to change the grade to B. Outputfor each query operation, output the highest score in one line. Sample Input5 61 2 3 4 5Q 1 5U 3 6Q 3 4Q 4 5U 2 9Q 1 5Sample Output5659Test instructionsGiven n values arranged in a certain order, the N values are operated in two ways:1. Query the maximum value of an interval [a, b];2. Change the value of the ordinal to A; Segment tree, update node, interval to find the most value idea: This ques

;} InlinevoidTREE_UP (intNow ) {Tree[now].dis=max (tree[now1].dis,tree[now1|1].dis);}voidTree_build (intNowintLintR) {TREE[NOW].L=l,tree[now].r=R; if(l==r) {tree[now].dis_ (); return ; } tree[now].mid_ (); Tree_build ( now1, L,tree[now].mid); Tree_build ( now1|1, tree[now].mid+1, R); TREE_UP (now);}intTree_query (intNowintLintR) { if(tree[now].l==ltree[now].r==r) {returnTree[now].dis; } if(L>tree[now].mid)returnTree_query (now1|1, L,r); Else if(RreturnTree_query (now1, L,r); Else {

);/* Here is wrong, left and right endpoint confused, error occurred, run error can only input three sets of data will automatically end */ElseIf(b)Query(I*2AB);Else{Query(I*2A, mid);Query(I*2+1, mid+1B);}}IntMain(){int nKXY, I;Char Str[11];While(scanf("%d%d", n, k)!=eof){For(I=1; I; I++)scanf("%d", num[I]);Build(1,1N);While(k--){scanf('%s 'Str);It's better to use strings here.If(str[0]==' Q '){scanf("%d%d", x, y); Ans=0;Query(1XY);Printf ( "%d\n" Span class= "Sh-symbol" >,ans); else { Scanf (

Val2)returnPnt0,0,1); Else returnPnt0,0,0); } if((!flag) (~DP[POS][VAL1][VAL2].VAL1))returnDp[pos][val1][val2]; PNT ans=PNT (0,0,0);Long LongUp=flag?bit[pos]:9; for(Long LongI=0; i) { if(i==7)Continue; Ans=comb (Ans,dfs (pos-1, (val1*Ten+i)%7, (val2+i)%7, flagi==up), pos,i); } if(!flag) dp[pos][val1][val2]=ans; returnans;}Long LongWorkLong Longx) {get_bit (x); returnDFS (ret,0,0,1). Val1;}intMain () {scanf ("%i64d",t); get_table (); for(Long LongI=1; i) {scanf ("%i64d%i64

Topic linksLine tree entry problem, line tree Single-point update to find the maximum value problem. #include #include#include#include#include#defineN 200005using namespacestd;intData[n];structtree{intL,r,ans;} Tree[n*4];voidBuildintRootintLintR) {TREE[ROOT].L=l; TREE[ROOT].R=R; if(l==r) {Tree[root].ans=Data[l]; return; } intMid= (l+r) >>1; Build (Root1, L,mid); Build (Root1|1, mid+1, R); Tree[root].ans=max (tree[root1].ans,tree[root1|1].ans);}voidUpdateintRootintPosintval) { if(tree[root]

Single-point modification, interval of the most value of the standard, nothing to say.1#include 2#include 3#include 4#include 5#include 6 using namespacestd;7 8 #defineLson l,m,root9 #defineRson m+1,r,rootTen Const intmaxn=200000+ -; One intn,m; A intmaxn[maxn*4]; - - voidPushup (introot) the { -Maxn[root]=max (maxn[root1],maxn[root1|1]); - } - + voidBuildintLintRintroot) - { + if(l==R) A { atscanf"%d",Maxn[root]); - return; - } - intM= (l+r) >>1; - build (Lson); - buil

not wayward better, men will be aware of. >でも, trilogy centered にどちらでもいいと う もありますよね. その は asked to return to しがおすすめ. "そうだね, xx June はどちらが food べたいの? "と say いましょう.However, there are still cases where all of them are OK. Recommend this way of answering "so, you want to eat that?" ”"~は Get Started ですね"Very good at what?~は Get started ですね "は, a see めの words developed See えますが, どこがngポイントなのでしょう. "~" は "to get started ですね"の, "は" が problem.Very good at what ", at first glance seems to be commendatory,

Topic Links:hdu:http://acm.hdu.edu.cn/showproblem.php?pid=1754ExercisesSingle point update, query into segments.Code:1#include 2#include 3#include 4#include 5 #defineLson o6 #defineRson (o7 #defineM L + (r-l)/28 using namespacestd;9 Ten Const intMAXN = 2e5 +Ten; One A intN, M; - intmaxv[maxn2]; - the voidBuildintOintLintr) { - if(L = =r) { -scanf"%d", MAXV +o); - } + Else { - Build (Lson, L, M); +Build (Rson, M +1, R); AMaxv[o] =Max (Maxv[lson], Maxv[rson]); at } - } - - int_p

when C is ' Q ', it indicates that this is a query operation, which asks for the highest number of students whose IDs are from a to B (including A, a). When C is ' U ', it indicates that this is an update operation that requires the student with ID A to change the grade to B.The topic is this, and then this problem, is a line segment tree interval query and endpoint update problems .With the interval and the difference is: This problem is to maintain the maximum value of the line tree, so at the

(node); - } the intQueryintLeftintRightintNode//max value for query interval [left,right] * { $ //the range checked is not in scopePanax Notoginseng if(Tree[node].left > Right | | tree[node].right Left ) - return 0; the //the interval to be checked contains the interval managed by the current node + if(left Right ) A returnTree[node]. Max; the intMid = (Tree[node].left + tree[node].right)/2; + //The interval that is checked is partially intersected with t

Test instructionsN a score. M operations.Q a B: Query the highest score from the first to the B scoresU a B: Conversion of Grade A to BIdeas:Look at the code,Code:Const intMAXN =200010;intmaxs[maxn2];intn,m;voidPushup (intRT) {Maxs[rt]= Max (maxs[rt1], maxs[rt1|1] );}voidBuildintLintRintRT) { if(l==R) {scanf ("%d",Maxs[rt]); return; } intm = (L + r) >>1; Build (Lson); Build (Rson); Pushup (RT);}voidUpdateintPintAddintLintRintRT) { if(l==R) {Maxs[rt]=add; return; } intm = (L + r