heap sort complexity

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Classical sorting algorithm--heap sort

For an int array, write a heap sort algorithm that sorts the array elements.Given an int array a and the size of the array n, return the sorted array.Test examples:[1,2,3,5,2,3],6[1,2,2,3,3,5] Class Heapsort {public:int* heapsort (int* A, int n) { buildmaxheap (A, n);//First build the array A into a large top heap for (int i = n-1; i > = 1; i--) {

PAT (Advanced level) 1098. Insertion or Heap Sort (25)

Simple question. Determine if it is a row or a heap.#include #include#include#include#include#include#include#includeusing namespacestd;Const intmaxn= $;intA[maxn],b[maxn],n;intMain () {memset (b,-1,sizeofb); scanf ("%d",N); for(intI=1; i"%d",A[i]); for(intI=1; i"%d",B[i]); intflag=1; intp=n+1; for(intI=2; i) if(b[i]1]) {p=i; Break; } for(intI=p; i) { if(A[i]==b[i])Continue; Elseflag=0; } if(flag==1) {printf ("insertion

Heap sort "Ten algorithms"

The top ten algorithms for heap sequencing:The heap is defined as follows: the sequence of n elements {k0,k1,..., ki,..., k (n-1)} is called a heap if and only if the next relationship is satisfied. "kiIf a one-dimensional array corresponding to this sequence (that is, a storage structure with a one-dimensional array for this sequence) is considered a complete bi

Build and sort the [data structure] Heap

First, the generation of small Gan1. Randomly generate a completely binary tree2. Adjust node 56 and its subtree3. Adjust node 77 and its subtree4. Adjust node 45 and its subtree5. Adjust node 18 and its subtree6. Adjust node 29 and its subtree(1) Adjust several 29 and their left and right sons(2) Adjustment node 29 and its left and right son.Second, heap sequencing1. Remove the current minimum element 3(1) Pinch tip(2) Place the node 65 on top of the

7-26 Windows Message Queuing (25 points) (Heap sort)

]) * { $ Case 'P' :Panax Notoginseng Put (); - Break; the Case 'G' : + Get (); A Break; the default : + Break; - } $ } $ - return 0; - } the - Wuyi voidPut () the { - //read the data and build a small top heap Wu inti; -Node temp = (node)malloc(sizeof(structNode)); Aboutscanf"%s%d",temp->mes,temp->Priority ); $ for(I=++heap.num; heap.heap[i/2]->prio

Heap Sort Review

(inta,intAMP;B) {intS;s=a;a=b;b=s;return;}void inch(int*a,intl);voidBuildint*a,intl);voidHeap_sort (int*a,intl);intMain () {inta[ the],l; inch(a,l); Build (a,l); Heap_sort (a,l); for(intk=1; k) cout" "; return 0;}void inch(int*a,intl) { intI=1; while(Cin>>a[i]) i++; L=i-1; return;}voidMaintenance (int*a,intIintLen) { intL=left (i), r=right (i), large=0; if(Ll; ElseLarge=i; if(RR; if(large==i)return; Swap (A[i],a[large]); Maintenance (A,large,len); return;}voidBuild (int*a,in

Heap sort (not understood)

Packagesort;ImportJava.util.Scanner; Public classHeapsort { Public Static intarr[]; Static{System.out.println ("Please enter the array into sort, and use ', ' as a separator:"); Scanner SC=NewScanner (system.in); String s=Sc.nextline (); String n[]=s.split (","); Arr=New int[N.length]; System.out.println ("Before sort:"); for(inti=0;i) {Arr[i]=Integer.parseint (N[i]); System.out.print (Arr[i]+" "); } Sy

2269:minval (priority queue heap sort)

2269:minval time limit: 3 Sec Memory limit: Submissions: 638 Resolution: 65 Submitted State [Discussion Version] [Propositional person: external import] Title DescriptionThere are two sequences A and b of length n, and the sum of each number in A and B can be obtained N2 and, the N2 and the smallest n.InputThe first line enters a positive integer N (1The second row n integer AI and aiOutputOutput only one row, containing n integers, from small to large output this n smallest and, adjac

sorting | Heap Sort

Start with a C + + code to see the process of push sequencing:1#include 2#include 3 using namespacestd;4 5 BOOLcmpConst intLhsConst intRHS)6 {7 returnLHS >RHS;8 }9 Ten intMain () One { A intArr[] = {4,2,Ten,9,5,6,8,6,7,1,3}; -Make_heap (arr, arr+Ten); - for(inti = One; I >=0; --i) { thePop_heap (arr, arr+i); - for(inti =0; I One; ++i) cout ' '; -cout Endl; - } + - return 0; +}Mainly Make_heap, pop_heapMake_heap: Build heap

Heap Sort Example-java

Package heapsort;public class Testmain{/*** Adjustment Heap* @param array arrays* @param I adjust the element i* Number of elements @param length heap*/public static void Adaptationarray (int[] array,int i, int length){Current elementint cur = i;while (2*cur+2{int curvalue = Array[cur];int leftvalue = array[2*cur+1];int maxindex;if (2*cur+3{Maxindex = array[2*cur+2]>leftvalue?2*cur+2:2*cur+1;}Else{Maxindex

(i) Select one of the sorts: heap sort

There are three types of selection: Simple selection sorting, tree selection sorting, heap sortingLet's take a quick look at the heap ordering today:Complete binary tree, that is, from beginning to end, from left to right, in order to match the large heap (small heap), that is Ki>=k2i ki >= k2i+1Since arrays are used

Heap Sort (Dagen)

Packagealgorithm; Public classLargeheapsort {/*** The array is adjusted so that Arr[low] becomes the largest low-len *@paramarr *@paramLow The root of the current binary tree (part of the heap) *@paramlength of Len Array*/ Public Static voidSiftint[] arr,intLowintLen) { intI=Low ; intJ=2*i+1; inttemp=Arr[low]; while(jLen) { if(j]) J++; if(tempArr[j]) {Arr[i]=Arr[j]; I=J; J=2*i+1; } ElseJ=len+1; } Arr[i]=temp; } /**

Heap Sort TOPK

) {System.out.println (top[i]); } } Public int[] tophundred (int[] Array,intk) {//The heap with size k int[] top =New int[K]; for(inti = 0; I ) {Top[i]=Array[i]; } buildminheap (top); for(inti = k; i ) { if(Top[0] Array[i]) {top[0] =Array[i]; Minheapify (Top,0, top.length); } } returntop; } //Create a min heap Public voidBuildminheap (int[] Array) {

Heap sort of Java

>=0;i--) { Maxheap (Tt,i,len); } System.out.println ("Create done"); /*for (int j=0;jSystem.out.print (tt[j]+ ""); } System.out.println (); System.out.println ("Sort:"); /** * MAXHEAP (Tt,0,i) I must be I, can not be i-1, this is to follow the method of rebuilding the heap. I corresponds to the length of the array that needs to be rebuilt by Len. */ for (int i=len-1;i>=0;i--) { int temp=tt[i]; TT[I]=TT[0];

Golang Container Heap&sort

This is a creation in Article, where the information may have evolved or changed. The go language also has its own container data structure. The list, heap, and ring are the main Package MainImport ( "Container/heap" "FMT" "Sort"//"StrConv") Type Heapint []intfunc (H heapint) Len () int {returnLen (h)}func (H heapint) Less (i, J int) bool {returnH[i] H[j

Minimum number of k C + + (bfprt, heap sort)

Title Description Enter n integers to find the smallest number of K. For example, enter 4,5,1,6,2,7,3,8 these 8 numbers, then the smallest 4 number is 1,2,3,4,.//Heap Sort#include #include#includeusing namespacestd;classsolution{ Public: voidHeapadjust (vectorint> a,intSintN) {intRc=A[s]; for(intj=2*s+1; j1; j=j*2+1) { if(j1a[j]>a[j+1]) J++; if(rcA[j]) Break; Else{A[s]=A[j]; S=J; }} A[

leetcode_215 problem--kth largest Element in an Array (heap sort)

from S+1...M except for the first S - voidHeapsort (vectorint> Nums,intSintm) the { - inttemp,j; -temp=Nums[s]; - for(j=2*s;j2*j) + { - if(j1]) +J + +; A if(temp>Nums[j]) at Break; -nums[s]=Nums[j]; -s=J; - } -nums[s]=temp; - } in //Main function - intFindkthlargest (vectorint> Nums,intk) to { +vectorint>Vec; - intn=nums.size (); theVec.push_back (0); * for(intI=0; i) $ Vec.push_back (Nums[i]);Panax Notoginseng - for(inti=n/2; i>=1; i

Heap sort (python)

Heap Sorting algorithmFirst look at the first function heapadjust, this function is already the composition of the heap of the two-fork tree, if the node K data changes, the node K is modified to make it a new heap binary tree, n is the data length.def heapadjust (lst,k,n): While (2*k+1The Heapsort function, using the first function above, constructs a

Heap Sort C language version of

2016_2_25_heap.cpp:defines the entry point for the console application.//#include "stdafx.h" //adjust the tree heap so that the maximum value is placed at the root node //i is the location of the array element and the tree //length void heapadjust (int Array[],int i,int nlength)//This is done only once { int nchild;//This is the child node of I int ntemp; for (; 2*i+1 { //left Dial Hand node location =2* (parent node location) +1 //

Heap Sort C + +

In the future, I want to put my usual writing here. If there is any improvement, please point out.#include"stdafx.h"#includeusing namespacestd;int*p;intLength//Save the number of elements that need to be sortedvoidInit () {//initialized. cout "Enter the number of elements to sort"Endl; CIN>>length; P=New int[length]; cout"Enter the elements you want to sort"Endl; for(inti =0; i ) {cin>>P[i]; }}voidShow ()

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