heap sort complexity

Copy Code code as follows: Import Java.util.Arrays; public class Heapsort { public static void Heapsort (datawraper[] data) {System.out.println ("start sort");int arraylength=data.length;Loop Build Heapfor (int i=0;iBuild a heapBuildmaxheap (data,arraylength-1-i);Swap heap top and last elementSwap (data,0,arraylength-1-i);System.out.println (arrays.tostring (data));}} private static void Swap (

An Python implementation of heap-sortbased onthe detailed algorithm description in Introduction to algorithmsThird Edition /c0>ImportRandomdefmax_heapify (arr, I, length): whileTrue:l, R= i * 2 + 1, I * 2 + 2largest= LifL andARR[L] > Arr[i]ElseIifR andARR[R] >Arr[largest]: largest=RifLargest! =I:arr[i], arr[largest], I=Arr[largest], Arr[i], largestElse: Breakdefbuild_heap (arr): forIinchRange (len (arr)/2,-1, 1): Max_heapify (L, I, Len (

; - for(intI=size;i>1; i--) the { -TMP = arr[0];Wuyiarr[0] = arr[i-1]; thearr[i-1] =tmp; -Max_heapify (arr,--size,1); Wu } - } About $ //return max key of Arr - intTopintArr[],Const intsize) - { - returnarr[0]; A } + the //return max key of arr and delete it - intPopintArr[],intsize) $ { the if(Size 1)returnERROR; the intmax = arr[0]; thearr[0] = arr[--size]; theMax_heapify (Arr,size,1); - returnMax; in } the the //increase the key of I About voidHeap_increase_key

Code:#!/usr/bin/env python#Coding=utf-8Importrandom,copydefHeap_sort_helper (lst,left,right):#Max HeapifyCurrent_value =Lst[left] child= 2 * left + 1 while(Child Right ):if(Child andLst[child] ]): child= child + 1if(Current_value >Lst[child]): Break Else: lst[( child-1) >>1] =Lst[child] child= 2 * child + 1lst[( child-1) >>1] =Current_valuedefHeap_sort (LST):#Build Heap forIinchRange (len (LST)-1) >>1,-1,-1): Heap_sort_helper (Lst,i,len (L

HeapSort.cpp: Defines the entry point of the console application. #include "stdafx.h" #include Reference URL: http://www.cnblogs.com/ahalei/p/3783543.htmlHttp://www.cnblogs.com/ahalei/p/3792155.htmlSpecific code explanation look at the above two URLs on the line, and then to "Ah Halle" praise one.Look at the data structure write code (63) Heap Sort

1 /**2 * Definition for singly-linked list.3 * struct ListNode {4 * int val;5 * ListNode *next;6 * ListNode (int x): Val (x), Next (NULL) {}7 * };8 */9 Ten structHelper { OneListNode *head; A intLen; -Helper (ListNode *h,intl): Head (h), Len (l) {} - }; the - classhelpercmp { - Public: - BOOL operator() (ConstHelper a,ConstHelper b) { + returnA.len >B.len; - } + }; A at classSolution { - Public: -Priority_queueHeap; - -InlineintListsize (ListNode *head) { -

Topological ordering, to make the dictionary order smallest, so the stack changed piles.1#include 2#include 3#include 4 using namespacestd;5 #defineN 1000016priority_queueint,vectorint>,greaterint> >Q;7 intn,m,x,y;8 intV[n],first[n],next[n],en,chu[n],ru[n],tot,ans[n];9 voidAddedge (Const intu,Const intV)Ten { Onev[++en]=V; Anext[en]=First[u]; -first[u]=en; - } the intMain () - { -scanf"%d%d",n,m); - for(intI=1; i) + { -scanf"%d%d",x,y); +chu[x]++; ru[y]++; A Addedge (x, y); at }

#include "stdafx.h" #include C + + heap sort source code

/*recently in the C language version of the data structure, C usage is really difficult, so according to the meaning, in the C language to write a JavaScript version of the three sorting Method! For everyone to learn together and refer to the following difficult merge sort, and quick sort, later, say nonsense, direct edge code side explain! */Heap

#include using namespacestd;voidHeapadjust (intArr[],intSintM//large Top Heap, m represents the last digit position, s represents the first position, is subscript{ intCur=s; intindex; inttmp=Arr[cur]; while(cur*2+1m) {index=cur*2+1;// Left Child if(index1]) {index++;// Right Child } if(arr[cur]Arr[index]) {Arr[cur]=Arr[index]; Arr[index]=tmp; Cur=index; } Else { Break; } }}voidHeapsort (intArr[],in

The problem is not to ask for the smallest dictionary order ... Tore it up for half an hour to find something wrong t tThis question is able to make small as far as possible before, regardless of dictionary order ... For example, 1 can be in front of 2 must be in front of 2 ...It is clear that the topology is sorted first, so that the small one is converted to make the big one as far back as possible, so it is actually irrelevant to the dictionary order. Then build a reverse diagram, with the

Use heap sorting to find the small number of k in list, with a small top heapdef min_heap_k(nums, topk): def siftdown(nums, e, begin, end): i = begin j = 2*i + 1 while j Linked list reversal Today's headline intern interview common topics Heap sort topk, reverse list

The process diagram is as follows: (build first heap, in adjustment, insert, output) Code: Heap sort (heapsort)//Yang Xin #include

=rightIndex; } if(largest!=rootIndex){ int temp=arr[largest]; arr[largest]=arr[rootIndex]; arr[rootIndex]=temp; maxHeap(arr,largest,heapSize); } } void builMaxHeap( int *arr,unsigned int heapSize){ for ( int Span class= "PLN" > i = heapsize / Span class= "lit" >2 - 1 ; I >= 0 ;-- i maxHeap(arr,i,heapSize); } } void heapsort ( int * arr , int length ) { for(int size=Length-1;size>0;size--){ builMaxHeap(arr,si

Defadjust (a,root,n): k=a[root-1]c =root*2whilecLiu Shuo teacher Python Boutique Courses: " Python advanced Programming Skills Combat": http://coding.imooc.com/class/62.html " python algorithm Combat video Course": http://study.163.com/course/coursemain.htm?courseid=1003617013 " Python scientific Computing-numpy Combat Course": http://edu.51cto.com/course/course_id-5046.html panda tv Live room: http://www.panda.tv/671023[Shuo. Love Python] Heapsort (

1 #!/usr/bin/env python2 3 defHeap_sort (elems):4 defSiftdown (Elems, E, Begin, end):5I, j = begin, Begin*2+16 whileJ End:7 ifJ+1 andELEMS[J+1] Elems[j]:8J + = 19 ifE Elems[j]:Ten Break OneElems[i] =Elems[j] AI, j = j, 2*j + 1 -Elems[i] =e - theEnd =Len (elems) - forIinchRange (END//2,-1,-1): - Siftdown (Elems, elems[i], I, end) - forIinchRange ((end-1), 0, 1): +E =Elems[i] -Elems[i] =Elems[0] + Siftdown (Elems, E, 0, i) A at if

Sort Time Limit: 6000/1000 MS (Java/others) memory limit: 65536/32768 K (Java/Others)Total submission (s): 27771 accepted submission (s): 8400 Problem description gives you n integers. Output The first m in the ascending order. There are two rows of test data in each input group. The first row has two numbers n, m (0 5 33 -35 92 213 -644Sample output 213 92 3 knowledge points: heap, STL#include

#include Heap sort (Keng Gen)

Heap sort C + + implementation #includeHeap sort C + + implementation

array=[0,30,20,80,40,50,10,60,70,90]# to sort sequences #i=4-1 or 1#n =len (array) total=len (array) -1# resize to a large top heap, I refers to the node from which to start the adjustment, n represents the total number of elements to be sorted def adjust_heap (N,i,array): #length =len (array) # Print_tree (Array) whilei*2This article is from the "12064120" blog, please be sure to keep this source http://12