heap sort python

Simple question. Determine if it is a row or a heap.#include #include#include#include#include#include#include#includeusing namespacestd;Const intmaxn= $;intA[maxn],b[maxn],n;intMain () {memset (b,-1,sizeofb); scanf ("%d",N); for(intI=1; i"%d",A[i]); for(intI=1; i"%d",B[i]); intflag=1; intp=n+1; for(intI=2; i) if(b[i]1]) {p=i; Break; } for(intI=p; i) { if(A[i]==b[i])Continue; Elseflag=0; } if(flag==1) {printf ("insertion

First, the generation of small Gan1. Randomly generate a completely binary tree2. Adjust node 56 and its subtree3. Adjust node 77 and its subtree4. Adjust node 45 and its subtree5. Adjust node 18 and its subtree6. Adjust node 29 and its subtree(1) Adjust several 29 and their left and right sons(2) Adjustment node 29 and its left and right son.Second, heap sequencing1. Remove the current minimum element 3(1) Pinch tip(2) Place the node 65 on top of the

]) * { $ Case 'P' :Panax Notoginseng Put (); - Break; the Case 'G' : + Get (); A Break; the default : + Break; - } $ } $ - return 0; - } the - Wuyi voidPut () the { - //read the data and build a small top heap Wu inti; -Node temp = (node)malloc(sizeof(structNode)); Aboutscanf"%s%d",temp->mes,temp->Priority ); $ for(I=++heap.num; heap.heap[i/2]->prio

Heap sorting can be used as real-time sorting, is the original sort, does not require additional space, time complexity is O (NLGN), the best worst-case average is this, but is not stable ordering, the following is the C language implementation code://in order to simplify programming, the first position in a heap array element is not used. struct

Packagealgorithm; Public classLargeheapsort {/*** The array is adjusted so that Arr[low] becomes the largest low-len *@paramarr *@paramLow The root of the current binary tree (part of the heap) *@paramlength of Len Array*/ Public Static voidSiftint[] arr,intLowintLen) { intI=Low ; intJ=2*i+1; inttemp=Arr[low]; while(jLen) { if(j]) J++; if(tempArr[j]) {Arr[i]=Arr[j]; I=J; J=2*i+1; } ElseJ=len+1; } Arr[i]=temp; } /**

Packagesort;ImportJava.util.Scanner; Public classHeapsort { Public Static intarr[]; Static{System.out.println ("Please enter the array into sort, and use ', ' as a separator:"); Scanner SC=NewScanner (system.in); String s=Sc.nextline (); String n[]=s.split (","); Arr=New int[N.length]; System.out.println ("Before sort:"); for(inti=0;i) {Arr[i]=Integer.parseint (N[i]); System.out.print (Arr[i]+" "); } Sy

Before looking at other algorithms and data structure of the book to find the heap sorting code more difficult to write, read the "Introduction to the algorithm" found that is not so difficult, so I started to write a. The principle is based on an introduction to the algorithm of the third version of the heap sorting pseudo code. #include The heap

Package heapsort;public class Testmain{/*** Adjustment Heap* @param array arrays* @param I adjust the element i* Number of elements @param length heap*/public static void Adaptationarray (int[] array,int i, int length){Current elementint cur = i;while (2*cur+2{int curvalue = Array[cur];int leftvalue = array[2*cur+1];int maxindex;if (2*cur+3{Maxindex = array[2*cur+2]>leftvalue?2*cur+2:2*cur+1;}Else{Maxindex

There are three types of selection: Simple selection sorting, tree selection sorting, heap sortingLet's take a quick look at the heap ordering today:Complete binary tree, that is, from beginning to end, from left to right, in order to match the large heap (small heap), that is Ki>=k2i ki >= k2i+1Since arrays are used

This is a creation in Article, where the information may have evolved or changed. The go language also has its own container data structure. The list, heap, and ring are the main Package MainImport ( "Container/heap" "FMT" "Sort"//"StrConv") Type Heapint []intfunc (H heapint) Len () int {returnLen (h)}func (H heapint) Less (i, J int) bool {returnH[i] H[j

from S+1...M except for the first S - voidHeapsort (vectorint> Nums,intSintm) the { - inttemp,j; -temp=Nums[s]; - for(j=2*s;j2*j) + { - if(j1]) +J + +; A if(temp>Nums[j]) at Break; -nums[s]=Nums[j]; -s=J; - } -nums[s]=temp; - } in //Main function - intFindkthlargest (vectorint> Nums,intk) to { +vectorint>Vec; - intn=nums.size (); theVec.push_back (0); * for(intI=0; i) $ Vec.push_back (Nums[i]);Panax Notoginseng - for(inti=n/2; i>=1; i

Prime + Heap is God's time to optimize a lot, by the way, the Heapsort to theDetailed ViewHeapsort uses the structure of the complete binary tree + large (small) top cone to exchange the elements of the cone and the end of the cone at the same time large (small) top cone elements-1, iterative n-1 secondary OKI'm here on a small-to-big shoot.1 //Heap Sort Time com

1 Packagesorting;2 3 /**4 * Heap Sorting5 * Average O (nlogn), preferably O (nlogn), Worst O (nlogn), Space complexity O (1), unstable, more complex6 * @authorZeng7 *8 */9 Public classDuipaixu {Ten One Public Static voidDuipaixu (int[] a) { A inti, TMP; - for(i = A.LENGTH/2; I >= 1; i--) - Heapadjust (A, I, a.length); the for(i = a.length; i > 1; i--) { -TMP = A[0]; -A[0] = a[i-1]; -A[I-1] =tmp; +Heapadjust (A, 1,

) {System.out.println (top[i]); } } Public int[] tophundred (int[] Array,intk) {//The heap with size k int[] top =New int[K]; for(inti = 0; I ) {Top[i]=Array[i]; } buildminheap (top); for(inti = k; i ) { if(Top[0] Array[i]) {top[0] =Array[i]; Minheapify (Top,0, top.length); } } returntop; } //Create a min heap Public voidBuildminheap (int[] Array) {

Basic idea:diagram: (88,85,83,73,72,60,57,48,42,6)Average Time complexity:O (Nlogn) due to the time complexity of each re-recovery heap is O (logn), a total of N-1 redo heap operations, coupled with the previous build heap n/2 times downward adjustment, each time the complexity of Adjustment is O (logn). Two operation times added or O (N * logn).Java Code Impleme

>=0;i--) { Maxheap (Tt,i,len); } System.out.println ("Create done"); /*for (int j=0;jSystem.out.print (tt[j]+ ""); } System.out.println (); System.out.println ("Sort:"); /** * MAXHEAP (Tt,0,i) I must be I, can not be i-1, this is to follow the method of rebuilding the heap. I corresponds to the length of the array that needs to be rebuilt by Len. */ for (int i=len-1;i>=0;i--) { int temp=tt[i]; TT[I]=TT[0];