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HDU 4965 fast matrix calculation (matrix high speed Power)

HDU 4965 Fast Matrix calculationTopic linksMatrix multiplied by axbxaxb ... Multiply nn times. Ability to turn ax (Bxaxbxa ...) XB, which is multiplied by nn-1 times, so that the middle matrix is a mere 6x6. Can be done with a matrix of high-speed powerCode:#include HDU 4965 fast matrix calculation (matrix high speed Power)

Nyoj 298 Phase Change point (Matrix high-speed power)

coordinates of a point (rounding the result to 1 digits after the decimal point, and outputting one decimal place) The output order of the points should be consistent with the input order Example input 2 51.0 2.0 2.0 3.0XYM 2.0 3.0S 2.0R 180 Example output -2.0-2.00.0 0.0 Analysis: The hypothesis is modeled according to the description of the topic. Must be timed out. At this po

How to make the power of the font of High force PPT

. In view of the fact that PPT is used for work, there is not a lot of italics. 4. Black Body Series 3 Key words: modern sense, power sense, exquisite The bold is a font that we often use, almost to a hundred-match font. Microsoft James Black believes everyone is familiar with it. As long as there is a modern style, can be used in bold series, so the bold series of recommended fonts are relatively more:

ZOJ2317-Nice patterns Strike Back: matrix fast power, high precision

). output write the number of Nice patterns of size n × m modulo p to the output file. sample Input 2 2 53 3 23Sample output 40Sourceandrew stankevich contest 1 algorithm: Because m 1 import Java. AWT. checkbox; 2 Import Java. io. bufferedinputstream; 3 Import Java. io. bufferedoutputstream; 4 Import Java. io. printwriter; 5 import Java. math. biginteger; 6 Import Java. util. optional; 7 8 public class main {9 10 static int P; 11 12 public static class Matrix implements cloneable {13 long [] []

PKU 1001 High Precision Power Multiplication

Question: Find RN, where R is a real number range of 0.0 Analysis: high-precision computation, string Operator Simulation numerical computation. Note the processing of various input formats: 123,012 3, 012.3, 123 ., 123.0, 123.01 ,. 123 ,. 1230, etc. My approach is to first process the input in the above cases ), (123,3), (123,3. That is, to delete the decimal point, delete the excess front 0 and back 0 storage, and return the number of decimal place

Maxcompute (High Precision) (6) -- power of maxcompute

/** Power of a large number (High Precision) ** // enter two numbers m (which can contain decimal points), n, and calculate the Npower of m # include

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